• Series R-C Circuit

by physics on April 20, 2010

Now consider an ac circuit consisting of a resistor of resistance R and a capacitor of capacitance C in series with’ an ac source supposes in phasor diagram current is taken along positive x-direction.

Then VR is along positive x-direction but VC is along negative y-direction as potential difference across a capacitor in ac lags in phase by 90° with the current in the circuit

So we can write.

and the potential difference lags the current  by an angle,

Illustration 3 : An a.c. source of angular frequency    is ,fed across a resistor R and a capacitor C in series. The current registered is l. If now the frequency of the source is changed to w/3 (but maintaining the same voltage), the current in the circuit is found to be halved. Calculate the ratio of reactance of resistance at the original frequency.

Solution: At angular frequency   , the current in R-C circuit is given by

When frequency is changed to   the current is halved Thus

From equation (i) and (ii),

Solving this equation,

Hence, the ratio of reactance to resistor is

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