Area – Maharashtra Board Class 7 Solutions for Mathematics

Area – Maharashtra Board Class 7 Solutions for Mathematics (English Medium)

MathematicsGeneral ScienceMaharashtra Board Solutions

Exercise 66:

Solution 1:

1. Area of a rectangle = length × breadth
2. Area of a square = side × side = (side)²

Solution 2:

Length of the rectangle = 4 cm
Breadth of the rectangle = 2 cm
Area of a rectangle = length × breadth
= 4 × 2
= 8 sq. cm
Thus, the area of the rectangle is 8 sq. cm.

Solution 3:

Side of the square = 40 cm
Area of a square = (side)² = (40)² = 1600 sq. cm
Thus, the area of the square is 1600 sq. cm

 

Exercise 67:

Solution 1:

Solution 2:

Exercise 68:

Solution 1:

Solution 2:

Solution 3:

Solution 4:

Length of the pit, l = 2 m
Breadth of the pit, l = 2 m
Area of the pit =l × b = 2 × 2 = 4 sq. m
Length of the plot, l = 12.4 m,
Breadth of the plot, b = 10.2 m
Area of the plot = l × b = 12.4 × 10.2 = 126.48 sq. m
Now, area of the plot after the pit is dug = 126.48 − 4= 122.48 sq. m
Thus, the area of the plot after the pit is dug is 122.48 sq. m.

Solution 5:

Solution 6:

Exercise 69:

Solution 1:

Solution 2:

Solution 3:

Exercise 70:

Solution 1:

Solution 2:

Solution 3:

Solution 4:

Solution 5:

Solution 6: