Constructions of Quadrilaterals – Maharashtra Board Class 7 Solutions for Mathematics

Constructions of Quadrilaterals – Maharashtra Board Class 7 Solutions for Mathematics (English Medium)

MathematicsGeneral ScienceMaharashtra Board Solutions

Exercise-92

Solution 1:

Solution 2:

Solution 3:

Exercise-93

Solution 1:
Steps of construction:

1. Draw seg PQ of length 4 cm.
2. Using a protractor, draw a ray PX ⊥ PQ at point P and a ray QY ⊥ PQ at point Q.
3. Placing the point of the compass on point P and taking a radius of 2 cm, draw an arc of circle to cut AX at point S. Taking the same radius and placing the point of the compass on point Q, draw an arc of circle to cut AY at point R
4. Draw seg RS.

Thus a rectangle PQRS with PQ = 4 cm and RS = 2 cm is constructed.

Solution 2:
Steps of construction:

1. Draw seg LM of length 5.5 cm.
2. Using a protractor, draw a ray LX ⊥ LM at point L and a ray MY ⊥ LM at point M.
3. Placing the point of the compass on point L and taking a radius of 3.5 cm, draw an arc of circle to cut LX at point P. Taking the same radius and placing the point of the compass on point M, draw an arc of circle to cut MY at point N.
4. Draw seg NP.

Thus a rectangle LMNP with LM = 5.5 cm and MN = 3.5 cm is constructed.

Solution 3:
Steps of construction:

1. Draw seg WX of any length, say, 4.5 cm.
2. Using a protractor, draw a ray WA ⊥ WX at point W and a ray XB ⊥ WX at point X.
3. Placing the point of the compass on point W and taking a radius of 2.5 cm, draw an arc of circle to cut WA at point Z. Taking the same radius and placing the point of the compass on point X, draw an arc of circle to cut XB at point Y.
4. Draw seg YZ.

Thus a rectangle WXYZ with WX = 4.5 cm and WZ = 2.5 cm is constructed.