**GSEB Solutions for Class 6 Mathematics – Revision: 2 (Sem -II)**

GSEB SolutionsMathsScience

**Revision – 1**

**Solution 1(1):**

a. 0

We know that subtracting a negative number is the same as adding a positive number.

(-2) – (-2)

= (-2) + 2 = 0

**Solution 1(2):**

b. (-4), (-1), 0, 2, 3

The numbers in the ascending order on the number line are the numbers from left to right.

**Solution 1(3):**

b. 78°

Measure of complementary angle of an angle = 90˚ – Measure of the given angle

The measure of given angle = 12˚

∴ Measure of its complementary angle = 90˚ – 12˚ = 78˚

**Solution 1(4):**

c. 72°

Measure of supplementary angle of an angle = 180˚ – Measure of the given angle

The measure of given angle = 108˚

∴ Measure of its supplementary angle = 180˚ – 108˚ = 72˚

**Solution 1(5):**

d. 71°

The measures of vertically opposite angles are equal.

**Solution 1(6):**

b. 1

The numbers 7 and 17 are the prime numbers and H.C.F. of two or more prime numbers is always 1

**Solution 1(7):**

d. 24

L.C.M of 8 and 12 = 2 × 2 × 2 × 3 = 24

**Solution 1(8):**

a. 33 and 37

H.C.F. of 33 and 37 = 1

H.C.F. of 2 and 8 = 2

H.C.F. of 7 and 21 = 7

H.C.F. of 25 and 75 = 25

**Solution 1(9):**

**Solution 1(10):**

**Solution 1(11):**

d. circumference

Perimeter of circle is known as circumference of a circle.

**Solution 1(12):**

**Solution 2:**

**Solution 3:**

**Solution 4:**

**Solution 5:**

The measure of given angle = 64˚

Measure of complementary angle of an angle = 90˚ – Measure of the given angle = 90˚ – 64˚ = 26˚

Measure of supplementary angle of an angle = 180˚ – Measure of the given angle= 180˚ – 64˚ = 116˚

**Solution 6:**

Angles forming a linear pair are always supplementary.

∴The sum of the measures of angles of a linear pair = 180˚

The measure of given angle = 102˚

∴Measure of angle forming its linear pair = 180˚ – 102˚ = 78˚

**Solution 7:**

1. 35, 77 and 84

35 = 5 × 7

77 = 7 × 11

84 = 2 × 2 × 3 × 7

∴H.C.F. of 35, 77 and 84 = 7

2. 30 and 110

30 = 2 × 3 × 5

110 = 2 × 5 × 11

H.C.F. of 5 and 11 = 2 × 5 = 10

3. 78, 96 and 108

78 = 2 × 3 × 13

96= 2 × 2 × 2 × 2 × 2 × 3

108 = 2 × 2 × 3 × 3 × 3

∴H.C.F. of 78, 96 and 108 = 2 × 3 = 6

**Solution 8:**

1. 36 and 54

L.C.M. of 36 and 54 = 2 × 2 × 3 × 3 × 3 = 108

2. 27, 54 and 81

L.C.M. of 27, 54 and 81 = 2 × 3 × 3 × 3 × 3 = 162

3. 15, 25 and 30

L.C.M. of 15, 25 and 30 = 2 × 3 × 5 × 5 = 150

**Solution 9:**

**Solution 10:**

**Solution 11:**

**Solution 12:**

**Solution 13:**

**Solution 14:**

**Solution 15:**

**Solution 16:**

**Solution 17:**