How can you prove that \(1-\tanh ^{2} x= sech^{2} x ?\)
Answer:
Let’s rewrite in terms of \(e^{x}\), using the identities \(sech x=\frac{2}{e^{x}+e^{-x}}\) and \(\tanh x=\frac{e^{x}-e^{-x}}{e^{x}+e^{-x}}\).
This has been proved!
Hopefully this helps!