Contents
- 1 Important Questions for CBSE Class 12 Chemistry – Coordination Compounds
- 1.1 PREVIOUS YEARS QUESTIONS
- 1.2 2015
- 1.3 Very Short Answer Type Question [1 Mark]
- 1.4 Short Answer Type Questions [I] [2 Marks]
- 1.5 Short Answer Type Questions [II] [3 Marks]
- 1.6 2014
- 1.7 Very Short Answer Type Questions [1 Mark]
- 1.8 Short Answer Type Questions [l] [2 Marks]
- 1.9 2013
- 1.10 Short Answer Type Questions [ii] [3 Marks]
- 1.11 2012
- 1.12 Short Answer Type Questions [II] [3 Marks]
- 1.13 2011
- 1.14 Very Short Answer Type Questions [1 Mark]
- 1.15 Short Answer Type Questions [I] [2 Marks]
- 1.16 Short Answer Type Questions [II] [3 Marks]
- 1.17 2010
- 1.18 Very Short Answer Type Questions [1 Mark]
- 1.19 Short Answer Type Questions [I] [2 Marks]
- 1.20 Short Answer Type Questions [II] [3 Marks]
- 1.21 2009
- 1.22 Short Answer Type Questions [II] [3 Marks]
Important Questions for CBSE Class 12 Chemistry – Coordination Compounds
PREVIOUS YEARS QUESTIONS
2015
Very Short Answer Type Question [1 Mark]
Question 1:
Why are tetrahedral complexes high spin?
Answer:
It is because of small splitting energy gap, electrons are not forced to pair, therefore, there are large number of unpaired electrons, i.e. high spin.
Short Answer Type Questions [I] [2 Marks]
Question 2:
(i) Write down the IUPAC name of the following complex:
[Pt(NH3)(H20)Cl2]
(ii) Write the formula for the following complex:
tris(ethane-l,2-diamine)chromium(III) chloride.
Answer:
(i) Ammineaqua dichlorido platinum [II]
(ii) [Cr(en)3]Cl3.
Question 3:
(i) Write down the IUPAC name of the following complex:
K3[Fe(CN)6]
(ii) Write the formula for the following complex:
Pentaaminenitrito-N-cobalt(III)
Answer:
(i) Potassium hexacyano ferrate (III)
(ii) [CO(NH3)5N02]2+
Question 4:
Write down the IUPAC name of the complex [Co(en)2Cl2]+. What type of isomerism is shown by this complex?
Answer:
Dichloro Bis-(ethane-l,2 diamine) Cobalt (III).
It will show geometrical as well as optical isomerism.
Question 5:
Using IUPAC norms write the formulae for the following coordination compounds:
(i) Tetracarbonylnickel(O)
(ii) Potassium tetracyanidoferrate(Il)
Answer:
(i) [Ni(CO)4] (ii) K2[Fe(CN)4]
Question 6:
Write down the IUPAC name of the complex [CO(NH3)5(C03)]Cl. What type of isomerism is shown by this complex?
Answer:
Pentaamminecarbonato cobalt (III) chloride.
It shows ionisation isomerism.
Question 7:
Using IUPAC norms write the formulae for the following coordination compounds:
(i) Tetrachloridocuprate(II)
(it) Potassium tetrahydroxozincate(II).
Answer:
(i) [CuCl4]2- (ii) K2[Zn(OH)4]
Question 8:
Write down the IUPAC name of the complex [Pt(en)2Cl2]2+. What type of isomerism is shown by this complex?
Answer:
Dichlorido bis(ethane 1,2-diamine) platinum (IV)
It will show geometrical as well as optical isomerism
Question 9:
Using IUPAC norms write the formulae for the following coordination compounds:
(i) Hexaamminecobalt(III) chloride
(ii) Potassium tetrachloridonickelate(II).
Answer:
(i) [CO(NH3)6]Cl3 (ii) K2[NiCl4]
Question 10:
(i) Write down the IUPAC name of the following complex: [CO(NH3)5(N02)](N03)2
(ii) Write the formula for the following complex: Potassium tetracyanidonickelate(II).
Answer:
(i) Pentaammine nitrito-N-cobalt(III) nitrate
(ii) K2[Ni(CN)4]
Question 11:
(i) Write down the IUPAC name of the following complex: ‘
[Cr(NH3)2Cl2(en)]Cl (en = ethylenediamine)
(ii) Write the formula for the following complex:
Pentaamminenitrito-O-Cobalt (III).
Answer:
(i) Diammine dichlorido (ethane 1, 2-diamine) Chromium (III) chloride.
(ii) [CO(NH3)5ONO]2+
Question 12:
(i) Write down the IUPAC name of the following complex: [CO(NH3)5Cl]2+
(ii) Write the formula for the following complex:
Potassium tetrachloridonickelate (II)
Answer:
(i) Pentaamminechloridocobalt (III)
(ii) K2[NiCl4]
Question 13:
(i) Write down the IUPAC name of the following complex:
[Cr(en)3]Cl3
(ii) Write the formula for the following complex:
Potassium tri oxalato chromate(III)
Answer:
(i) Tris (ethane 1, 2-diamine) Chromium (III) Chloride.
(ii) K3[Cr(C204)3]
Short Answer Type Questions [II] [3 Marks]
Question 14:
(i) What type of isomerism is shown by [CO(NH3)5ONO]Cl2?
(ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if A0 < P.
(iii) Write the hybridization and shape of [Fe(CN)6]3-. (Atomic number of Fe — 26)
Answer:
(i) Linkage isomerism
(ii) t32g e1g
(iii) d2sp2, octahedral shape.
Question 15:
(i) What type of isomerism is shown by the complex [Ag(NH3)2][Ag(CN)2]?
(ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if A0 < P.
(iii) Write the hybridization and shape of [Ni(CN)4]2_. (Atomic’number of Ni = 28)
Answer:
(i) Coordination isomerism
(ii) t32g e1g
(iii) dsp2, square planar.
Question 16:
(а) Write the hybridization and shape of the following complexes:
(i) [FeF6]3 (ii) [Ni(CO)4]
(b) Out of CN- and CO which ligand forms more stable complex with metal and why?
Answer:
(a) (i) [FeF6]3_ has sp3d2 hybridization, octahedral shape.
(ii) [Ni(CO)4] has sp3 hybridization, tetrahedral shape.
(b) CO forms more stable complex than CN- because it can form both a as well as n-bond with central metal atom or ion.
Question 17:
(a) Write the hybridization and shape of the following complexes:
(i) [CoF6]3- (ii) [Ni(CN)4]2-
(Atomic number : Co = 27, Ni = 28)
(b) Out of NH3 and CO, which ligand forms a more stable complex with a transition metal and why?
Answer:
(a) (i) sp3d2, octahedral (ii) dsp2, square planar.
(b) CO can form more stable complex than NH3 because it is the strongest ligand and can form both a as well as Ti-bond (strategic bonding or back bonding).
Question 18:
(a) Write the hybridization and shape of the following complexes:
(i) [CO(NH3)6]3+ (ii) [NiCl4]2-
(Atomic number : Co = 27, Ni = 28)
(b) Out of NH3 and ‘en’, which ligand forms more stable complex with metal and why?
Answer:
(a) (i) d2sp3, octahedral
(ii) sp3, tetrahedral.
(b) en will form more stable complex because it is bidentate ligand.
Question 19:
(i) Draw the geometrical isomers of complex [Co(en)2Cl2]+.
(ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.
(iii) [NiCl4]2_ is paramagnetic while [Ni(CO)4] is diamagnetic, though both are tetrahedral. Why? (Atomic number of Ni = 28)
Answer:
(ii) t4 2g
(iii) [NiCl4]2_ has unpaired electron, whereas [Ni(CO)4] does not have unpaired electrons, therefore, diamagnetic.
Question 20:
(a) Predict the number of unpaired electrons in hexaaquamanganese(II) ion. [Atomic number of Mn = 25]
(b) Write the chemical formula and shape of hexaamminecobalt(III) sulphate.
(c) A CuS04 solution is mixed with (NH4)2 S04 solution in the ratio of 1 : 4 does not give test for Cu2+ ion, Why?
Answer:
(a) It has 5 unpaired electrons.
(b) [CO(NH3)6]2 (S04)3, octahedral.
(c) [CU(NH3)4] S04 is formed which does not have free Cu2+ ions.
Question 21:
(i) Draw the geometrical isomers of complex [Pt(NH3)2Cl2].
(ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 < P.
(ii) Write the hybridization and magnetic behaviour of the complex [Ni(CO)4].
Answer:
Question 22:
(i) What type of isomerism is shown by the complex [Cr(H20)6]Cl3?
(ii) On the basis of crystal field theory, write the electronic configuration for d4 ion if Δ0 > P.
(iii) Write the hybridization and shape of [CoF6]3-.
(Atomic number of Co = 27)
Answer:
Question 23:
(i) Draw the geometrical isomers of complex [Pt(en)2Cl2]2+.
(ii) On the basis of crystal field theory, write the electronic configuration for d4 ion, if Δ0> P.
(iii) Write the hybridization type and magnetic behaviour of the complex
Answer:
2014
Very Short Answer Type Questions [1 Mark]
Question 24:
Which of the following is more stable complex and why?
[CO(NH3)6]3+ and [Co(en)3]3+
Answer:
[Co(en)3]3+ is more stable since ‘en’ is didentate ligand which forms more stable complex than NH3(unidentate ligand).
Question 25:
What type of isomerism is shown by the following complex:
[Co(NH3)6][Cr(CN)6]
Answer:
Coordination isomerism.
Question 26:
What type of isomerism is exhibited by the following complex:
[CO(NH3)5S04]Cl
Answer:
Ionisation isomerism.
Question 27:
What type of isomerism is exhibited by the complex [Co(NH3)5N02]2+?
Answer:
Linkage isomerism.
Short Answer Type Questions [l] [2 Marks]
Question 28:
Write the IUPAC name of the complex [Cr(NH3)4Cl2]+. What type of isomerism does it exhibit?
Answer:
Question 29:
Write the state of hybridization, shape and IUPAC name of the complex [C0F6]3-.
(Atomic no. of Co = 27)
Answer:
Question 30:
Write the state of hybridization, shape and IUPAC name of the complex [Ni(CN)4]2-.
(Atomic no. of Ni = 28)
Answer:
Question 31:
Write the state of hybridization, shape and IUPAC name of the complex [CO(NH3)6]3+. (Atomic no. of Co = 27)
Answer:
Question 32:
(i) Write the IUPAC name of the complex [Cr(NH3)4Cl2]Cl.
(ii) What type of isomerism is exhibited by the complex [Co(en)3]3+? (en = ethane-1, 2-diamine)
(iii) Why is [NiCl4]2- paramagnetic but [Ni(CO)4] is diamagnetic? (At. nos.: Cr = 24, Co = 27, Ni = 28)
Answer:
Question 33:
Write down the IUPAC name for each of the following complexes:
(i) [CO(NH3)5Cl]Cl2 (ii) K3[Fe(CN)6] (iii) [NiCl2]2-
Answer:
(i) Pentaammine chlorido cobalt(III) chloride
(ii) Potassium hexacyanido ferrate(III).
(iii) Tetrachloridonickelate(II).
Question 34:
Draw the structures of optical isomers of each of the following complexes:
[Co(C204)3]3-, [Pt Cl2(en)2]2+, [Cr(NH3)2Cl2(en)]+
Answer:
Question 35:
Write IUPAC name and draw structure of following complexes:
(a) [Co(OX)3]3- (b) Cr[(CO)6] (c) [PtCl3(C2H4)]+
Answer:
2013
Short Answer Type Questions [ii] [3 Marks]
Question 36:
Write the IUPAC names of the following coordination compounds:
(i) [Cr(NH3)3Cl3]
(ii) K3[Fe(CN)6]
(iii) [CoBr2(en)2]+, (en = ethylenediamine)
Answer:
(i) Triamminetrichloridochromium (III)
(ii) Potassiumhexacyanoferrate (III)
(iii) Dibromidobis (ethane 1, 2-diamine)cobalt (III)
Question 37:
Write the types of isomerism exhibited by the following complexes:
(i) [CO(NH3)5Cl]S04 (ii) [Co(en)3]3+ (iii) [Co(NH3)6] [Cr(CN)6]
Answer:
(i) Ionisation isomerism (ii) Optical isomerism (iii) Coordination isomerism
Question 38:
For the complex [NiCl4]2_ , write
(i) the IUPAC name,
(ii) the hybridization type,
(iii) the shape of the complex.
(Atomic no. of Ni = 28)
Answer:
(i) Tetrachloridonickelate(II) (ii) sp4 (iii) Tetrahedral
Question 39:
What is meant by crystal field splitting energy? On the basis of crystal field theory, write the electronic configuration of d4 in terms of tgg and eg in an octahedral field when (i) Δ0 > P (ii) Δ0 < P
Answer:
The difference between energies of two sets of d-orbitals t2g and e is called crystal field splitting energy (ΔQ).
(i) If Δ0 > P, the configuration will be t2g, eg. Ligands will produce strong field and low spin complex will be formed.
(ii) If Δ0 < P, the configuration will be t2g, eg and it is in the case of weak field ligands and high spin complex will be formed.
Question 40:
(a) Write the IUPAC name of the complex [CoBr2(en)2]+.
(b) What type of isomerism is shown by the complex [Co(NH3)5S04]Br?
(c) Why is CO a stronger ligand than NH3 in complexes?
Answer:
(a) Dibromidobis (ethane-1, 2-diamine)cobalt(III)
(b) Ionisation isomerism
(c) It is because CO can form a as well as tr-bonds, therefore, it is stronger ligand thap NH3 which can form only a-bond.
Question 41:
(a) Write the formulae for the following coordination compounds:
(i) Tetraammineaquachloridocobalt (III) chloride (ii) Potassium tetracyanonickelate (II)
(b) Write the hybridization of the complex [NiCI4]2-. (Atomic number of Ni = 28)
Answer:
Question 42:
(a) What type of isomerism is shown by each of the following complexes:
(i) [Pt(NH3)2Cl2] (ii) [CO(NH3)5(N02)]Cl2
(b) Give an example of the role of coordination compounds in biological systems.
Answer:
2012
Short Answer Type Questions [II] [3 Marks]
Question 43:
State a reason for each of the following situations:
(i) Co2+ is easily oxidised to Co3+ in presence of a strong ligand.
(ii) CO is a stronger complexing reagent than NH3.
(iii) The molecular shape of Ni(CO)4 is not the same as that of [Ni(CN)4]2_.
Answer:
(i) Strong ligands provide energy which overcomes 3rd ionisation enthalpy and Co2+ gets oxidised to Co3+.
(ii) CO can form a as well as n bond, therefore, it is stronger ligand than NH3which can form only a bond.
(iii) Ni(CO)4 has spb3 hybridization, tetrahedral shape, whereas [Ni(CN)4]2- has dsp2 hybridization, therefore, it has a square planar shape.
Question 44:
Give the formula of each of the following coordination entities:
(i) Co3 + ion is bound to one Cl-, one NH3 molecule and two bidentate ethylene diamine (en) molecules.
(ii) Ni2+ ion is bound to two water molecules and two oxalate ions.
Write the name and magnetic behaviour of each of the above coordination entities. (At. nos. Co = 27, Ni = 28)
Answer:
Question 45:
Write the name of the structure and the magnetic behaviour of each one of the following complexes:
(i) [Pt(NH3)2Cl(N02)]
(ii) [CO(NH3)4 Cl2] Cl
(iii) Ni(CO)4
(At. nos. Co = 27, Ni = 28, Pt = 78)
Answer:
(i) Diammine chlorido nitrito-N-platinum(II). It is square planar and diamagnetic.
(ii) Tetraammine dichlorido cobalt(III) chloride. It is octahedral and diamagnetic.
(iii) Tetracarbonyl nickel(O). It is tetrahedral and diamagnetic complex.
Question 46:
Answer:
Question 47:
Name the following coordination entities and draw the structures of their stereoisomers:
(i) [Co(en)2Cl2]+ (en = ethan-1, 2-diamine)
(ii) [Cr(C204)3]3-
(iii) [CO(NH3)3Cl3] (Atomic numbers Cr = 24, Co = 27)
(Atomic numbers Fe = 26, Cr = 24, Ni = 28)
Answer:
(i) Hexacyanido ferrate(II). It has octahedral structure.
(ii) Tetraammine dichlorido chromium(III). It has octahedral structure.
(iii) Tetracyanidonickelate(II). It has square planar structure.
Question 48:
Explain the following:
(i) The n-complexes are known for transition elements only.
(ii) Nickel (II) does not form low spin octahedral complexes.
(iii) [Fe(CN)6]4- and [Fe(H20)6]2 + are of different colours in dilute solutions.
Answer:
(i) Transition metals have vacant d-orbitals which accept lone pair from ligands to form a bond and give pair of electron to molecular orbital of ligand forming 7t-bond.
(ii) Ni2+ has unpaired electrons, therefore, forms high spin complex as pairing of electrons does not take place because after pairing only one d-orbital will be left which cannot be used in octahedral complex.
(iii) They absorb different wavelengths from visible light, undergo d-d transitions and radiate complementary colour. CN- is stronger ligand than H2O.
Question 49:
Name the following complexes and draw the structures of one possible isomer of each:
(i) [Cr(C204)3]3-
(ii) [Pt(NH3)2Cl2]
(iii) [Co(en)2Cl2]+
(en = ethane-1,2-diamine or ethylenediamine)
Answer:
(i) Refer Ans. to Q.46 (ii).
(ii) Refer Ans. to Q.42 (a) (i).
(iii) Refer Ans. to Q.46 (i).
2011
Very Short Answer Type Questions [1 Mark]
Question 50:
What do you understand by ‘denticity of a ligand’?
Answer:
It is defined as the number of coordinate bonds formed by a ligand.
Question 51:
Why is CO a stronger ligand than Cl-?
Answer:
It is because CO forms a as well as x-bond, therefore, it is stronger ligand than Cl-.
Question 52:
Name the following coordination compound: K3[CrF6].
Answer:
Potassium hexafluoridochromate(III)
Short Answer Type Questions [I] [2 Marks]
Question 53:
Name the following coordination compounds and draw their structures:
(i) [CoCl2(en)2]Cl .
(ii) [Pt(NH3)2Cl(N02)] (At no. Co = 27, Pt = 78)
Answer:
Question 54:
Draw the structures of isomers, if any, and write the names of the following complexes:
(i) [Cr(NH3)4Cl2]+ (ii) [Co(en)3]3+
[Atomic numbers Cr = 24, Co = 27]
Answer:
Question 55:
Give the name, the stereochemistry and the magnetic behaviour of the following complexes:
(i) [CO(NH3)5 Cl] Cl2 (ii) K2[Ni(CN)4]
Answer:
(i) Pentaammine chloridocobalt III chloride. It is octahedral (d2sp3) and diamagnetic.
(ii) Potassium tetracyanido nickelate(II). It is square planar (dsp2 hybridised) and diamagnetic
Short Answer Type Questions [II] [3 Marks]
Question 56:
Write the name, stereochemistry and magnetic behaviour of the following:
(At. nos Mn = 25, Co = 27, Ni = 28)
(i) K4[Mn(CN)6]
(it) [CO(NH3)5Cl]Cl2
(iii) K2[Ni(CN)4]
Answer:
(i) Potassium hexacyano-manganate(II). It has octahedral shape and is paramagnetic in nature.
(ii) Pentaaminechloridocobalt(III) chloride. It has octahedral shape and is diamagnetic in nature.
(iii) Potassium tetracyanonickelate(II). It has square planar shape and is diamagnetic in nature.
Question 57:
For the complex [Fe(en)2Cl2]Cl, identify the following:
(i) Oxidation number of iron.
(ii) Hybrid orbitals and shape of the complex.
(iii) Magnetic behaviour of the complex.
(iv) Number of its geometrical isomers.
(v) Whether there may be optical isomer also.
(vi) Name of the complex.
Answer:
(i) +3 (III)
(ii) d2sp3, octahedral
(iii) paramagnetic
(iv) Two geometrical isomers
(v) Yes, there may be optical isomer also due to presence of polydentate ligand.
(vi) Dichlorido bis-(ethane 1, 2-diamine) Iron (III)
Question 58:
Explain the following terms giving a suitable example in each case:
(i) Ambidentate ligand
(ii) Denticity of a ligand
(iii) Crystal field splitting in an octahedral field.
Answer:
Question 59:
Write the structures and names of all the stereoisomers of the following compounds:
(i) [Co (en)3]Cl3
(ii) [Pt(NH3)2Cl2]
(iii) [Fe(NH3)4 Cl2] Cl
Answer:
Question 60:
Write the state of hybridisation, the shape and the magnetic behaviour of the following complex entities:
(i) [Cr(NH3)4Cl2] Cl
(ii) [Co(en)3] Cl3
(iii) K2[Ni(CN)4]
Answer:
(i) [Cr(NH3)4Cl2]Cl has d2sps hybridization, octahedral shape and paramagnetic.
(ii) [Co (en)3] Cl3 has d?sp3 hybridization, octahedral shape and diamagnetic.
(iii) K2[Ni(CN)4] has dsp2 hybridization, square planar shape, diamagnetic.
2010
Very Short Answer Type Questions [1 Mark]
Question 61:
Give an example of coordination isomerism.
Answer:
CO(NH3)6], [Cr(CN)6] and [Cr(NH3)6] [Co(CN)6] are coordination isomer
Question 62:
Give an example of ionisation isomerism.
Answer:
[Co(NH3)5Br]S04 and [Co(NH3)5S04)]Br is the example of ionisation isomerism.
Short Answer Type Questions [I] [2 Marks]
Question 63:
Name the following coordination compounds according to IUPAC system of nomenclature.
(i) [CO(NH3)2 (H2O) Cl] Cl2
(ii) [Cr Cl2(en)2] Cl, (en = ethane-1,2-diamine)
Answer:
(i) Tetraammineaquachlorido cobalt(III) chloride.
(ii) Dichlorido bis(ethane 1, 2-diamine) chromium (III) chloride.
Question 64:
Describe the shape and magnetic behaviour of following complexes:
(i) [CO(NH3)6]3+ (ii) [Ni(CN)4]2-,
(At. No. Co = 27, Ni = 28)
Answer:
(i) It is octahedral, d2sp3 hybridised, diamagnetic in nature.
(ii) It is square planar, dsp2 hybridised, diamagnetic in nature.
Question 65:
Describe the state of hybridization, the shape and the magnetic’behaviour of the following complexes:
(i) [Cr(H20)2(C204)2]- (ii) [Co(NH3)2(en)2]3+, (en = ethane-1, 2-diamine)
(At. Nos : Cr = 24, Co = 27)
Answer:
Question 66:
Explain the following terms.
(i) Crystal field splitting in an octahedral field.
(ii) Spectrochemical series.
Answer:
(i) Refer Ans. to Q.58 (iii).
(ii) The series in which ligands are arranged in the increasing order of their strength is called spectrochemical series.
T< Br-< SCN-< Cl-
Short Answer Type Questions [II] [3 Marks]
Question 67:
Explain the following:
(i) Nickel does not form low spin octahedral complexes.
(ii) The Tt-complexes are known for the transition metals only.
(iii) Co2+ is easily oxidised to Co3+ in the presence of a strbng ligand.
Answer:
(i) Ni (28) : [Ar] 452 3d8 Ni2+ (28) : [Ar] 45° 3d8
In octahedral complexes, pairing of electrons will not take place even if we have strong field ligand, therefore, Ni does not form low spin octahedral complexes.
(ii) In tt-complexes, CT bond is formed by donation of n electrons or lone pair to vacant d-orbital of transition metal and 7t-bond is formed by back donation of pair of electrons from transition metal to vacant antibond¬ing orbitals of alkene or carbon monoxide. These conditions are met or found only in transition metals.
(iii) Co2+ is oxidised to Co3+ in presence of strong field ligand because energy needed for oxidation is provided by strong field ligand and Co3+ is more stable than Co2+.
Question 68:
(a) Square planar complexes (of MXJLJ type) with coordination number of 4 exhibit geometrical isomerism, whereas tetrahedral complexes with similar composition do not. Why?
(b) Describe the type of hybridization, shape and magnetic property of [CO(NH3)4Cl2]Cl. [Given : At. no. of Co = 27]
Answer:
Question 69:
Write the name, the state of hybridization, the shape and the magnetic behaviour of the following complexes:
[CoCl4]2-, [Cr(H20)2(C204)2]- , [Ni(CN)4]2-,
(At. No. : Co = 27, Ni = 28, Cr = 24)
Answer:
2009
Short Answer Type Questions [II] [3 Marks]
Question 70:
Giving a suitable example for each, explain the following:
(i) Crystal field splitting (ii) Linkage isomerism (iii) Ambidentate ligand
Answer:
(i) The splitting of d-orbitals in presence of ligands is called crystal field splitting, e.g. octahedral and tetrahedral.
(ii) Complex having ambidentate ligand shows linkage isomerism, e.g. [CO(NH3)5N02]2+ and [Co(NH3)5ONO]2+ are linkage isomers.
(iii) Refer Ans. to Q.58 (iii).
Question 71:
Compare the following complexes with respect to their shape, magnetic behaviour and the hybrid orbitals involved:
(i) [COF4]2- (ii) [Cr(H20)2(C202)2]- (iii) [Ni(CO)4]
(At. no. : Co = 27, Cr = 24, Ni = 28)
Answer:
Question 72:
Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units: [Co(NH3)6]3+, [Cr(NH3)6]3+, [Ni(CO)4]
(At. Nos.: Co = 27, Cr = 24, Ni = 28)
Answer:
Question 73:
Compare the following complexes with respect to structural shapes of units, magnetic behaviour and hybrid orbitals involved in units:
(i) [Ni(CN)4]2- (ii) [NiCl4]2- (iii) [CoF6]3- [At. nos. : Ni = 28; Co = 27]
Answer:
Question 74:
Three geometrical isomers are possible for [Co(en) (H20)2(NH3)2]3+. Draw molecular structures of these three isomers and indicate which one of them is chiral.
Answer:
Question 75:
Compare the following complexes with respect to their molecular shape and magnetic behaviour :
(i) [Cr(NH3)6]3+ (ii) [Fe(CN)6]4- (iii) [NiCl4]2-
(At. No. : Cr = 24, Fe = 26, Ni = 28)
Answer:
Question 76:
Explain the following giving an example in each case:
(i) Linkage isomerism
(ii) An outer orbital complex
(iii) A bidentate ligand
Answer:
Question 77:
Explain the following:
(i) Low spin octahedral complexes of nickel are not known.
(ii) The n-complexes are known for transition elements only.
(iii) CO is a stronger ligand than NH3 for many metals.
Answer:
(i) Refer Ans. to Q.67 (i).
(ii) Refer Ans. to Q.67 (ii).
(iii) Refer Ans. to Q.17 (b).