Complete solutions of Ex 13.1 Class 10 Maths Chapter 13 with additional questions and answers from new NCERT syllabus textbook Class 10 Maths.

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.1 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.1.

- Surface Areas and Volumes Class 10 Ex 13.1
- Surface Areas and Volumes Class 10 Ex 13.2
- Surface Areas and Volumes Class 10 Ex 13.3
- Surface Areas and Volumes Class 10 Ex 13.4
- Surface Areas and Volumes Class 10 Ex 13.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 13 |

Chapter Name |
Surface Areas and Volumes |

Exercise |
Ex 13.1 |

Number of Questions Solved |
9 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.1

**[Unless stated otherwise, take π = \(\frac { 22 }{ 7 }\)]**

**Ex 13.1 Class 10 Maths Question 1.**

**2 cubes each of volume 64 cm ^{3} are joined end to end. Find the surface area of the resulting cuboid.**

**Solution:**

Let the length of side of the cube be a cm.

Then, its volume = a

^{3}cm

^{3}⇒ a

^{3}= 64 [Given]

⇒ a = \(\sqrt [ 3 ]{ 64 } \) = 4 cm

By joining the two cubes, a cuboid is formed withe length, breadth and height 8 cm, 4 cm and 4 cm respectively.

∴ Surface area of the cuboid = 9(lb + bh + hl)

= 2(8 x 4 + 4 x 4 + 4 x 8) cm

^{2}

= 2(32 + 16 + 32) = 160 cm

**Ex 13.1 Class 10 Maths Question 2.**

**A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel.**

**Solution:
**Radius of hemisphere, r = \(\frac { 14 }{ 2 } \) = 7 cm

Height of cylinder, h = 13 – 7 = 6 cm

**Ex 13.1 Class 10 Maths **Question 3.

**A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.**

**Solution:**

Radius of cone, r = 3.5 cm

Height of cone, h = 15.5 – 3.5 = 12 cm

**Ex 13.1 Class 10 Maths Question 4.**

**A cubical block of side 7 cm is surmounted by a hemisphere. What is the greatest diameter the hemisphere can have? Find the surface area of the solid.**

**Solution:**

**Ex 13.1 Class 10 Maths Question 5.**

**A hemispherical depression is cut out from one face of a cubical wooden block such that the diameter l of the hemisphere is equal to the edge of the cube. Determine the surface area of the remaining solid.**

**Solution:**

Diameter of hemisphere = edge of cube = l

So the radius of hemisphere = \(\frac { l }{ 2 } \)

**Ex 13.1 Class 10 Maths Question 6.**

**A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends (see figure). The length of the entire capsule is 14 mm and the diameter of the capsule is 5 mm. Find its surface area.**

Solution:

Radius of cylinder, r = 2.5 mm

Length of cylinder, h = 9 mm

**Ex 13.1 Class 10 Maths Question 7.**

**A tent is in the shape of a cylinder surmounted by a conical top. If the height and diameter of the cylindrical part are 2.1 m and 4 m respectively, and the slant height of the top is 2.8 m, find the area of the canvas used for making the tent. Also, find the cost of the canvas of the tent at the rate of ₹ 500 per m². (Note that the base of the tent will not be covered with canvas.)**

**Solution:**

**Ex 13.1 Class 10 Maths Question 8.**

**From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm².**

**Solution:**

**Ex 13.1 Class 10 Maths Question 9.**

**A wooden article was made by scooping out a hemisphere from each end of a solid cylinder, as shown in figure. If the height of the cylinder is 10 cm, and its base is of radius 3.5 cm, find the total surface area of the article.**

**Solution:**

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