Complete solutions of Ex 15.1 Class 10 Maths Chapter 15 with additional questions and answers from new NCERT syllabus textbook Class 10 Maths.

NCERT Solutions for Class 10 Maths Chapter 15 Probability Ex 15.1 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 15 Probability Ex 15.1.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 15 |

Chapter Name |
Probability |

Exercise |
Ex 15.1 |

Number of Questions Solved |
25 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 15 Probability Ex 15.1

**Ex 15.1 Class 10 Maths Question 1.**

**Complete the following statements:**

**(i)** The probability of an event E + Probability of the event ‘not E’ = ………

**(ii)** The probability of an event that cannot happen is ……… Such an event is called ………

**(iii)** The probability of an event that is certain to happen is ………. Such an event is called ………

**(iv)** The sum of the probabilities of all the elementary events of an experiment is ………..

**(v)** The probability of an event is greater than or equal to …………. and less than or equal to ………..

**Solution:**

**(i)** 1

**(ii)** 0, impossible event

**(iii)** 1, sure event

**(iv)** 1

**(v)** 0, 1

**Ex 15.1 Class 10 Maths Question 2.**

**Which of the following experiments have equally likely outcomes? Explain.**

**(i)** A driver attempts to start a car. The car starts or does not start.

**(ii)** A player attempts to shoot a basketball. She/he shoots or misses the shot.

**(iii)** A trial is made to answer a true-false question. The answer is right or wrong.

**(iv)** A baby is born. It is a boy or a girl.

**Solution:
**

**(i)**It is

**not an equally likely**outcome because car will not start only when it is out of order.

**(ii)**It is

**not an equally likely**outcome because this game depends on many factors.

**It is an**

(iii)

(iii)

**equally likely**outcome because both have equal chances to happen.

**(iv)**It is an

**equally likely**outcome because both have equal chances to happen.

**Ex 15.1 Class 10 Maths Question 3.**

**Why is tossing a coin considered to be a fair way of deciding which team should get the bail at the beginning of a football game?**

**Solution:
**When we toss a coin, the outcomes head and tail are equally likely. So, the result of an individual coin toss is completely unpredictable.

**Ex 15.1 Class 10 Maths Question 4.**

**Which of the following cannot be the probability of an event?**

**(A)** \(\frac { 2 }{ 3 }\)

**(B)** -1.5

**(C)** 15%

**(D)** 0.7

**Solution:
**-1.5, because the probability of an event is greater than or equal to zero.

**Ex 15.1 Class 10 Maths Question 5.**

**If P (E) = 0.05, what is the probability of ‘not E’?**

**Solution:
**P(not E) = 1 – P(E) = 1 – 0.05 – 0.95 .

**Ex 15.1 Class 10 Maths Question 6.**

**A bag contains lemon flavored candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out**

**(i)** an orange flavored candy?

**(ii)** a lemon flavored candy?

**Solution:
**

**(i)**There is no orange flavored candy. So the probability of orange flavored candy P(E) = 0 (impossible event).

**(ii)**All candies are lemon flavored in the bag. So the probability of a lemon flavored candy P(E) = 1 (sure event).

**Ex 15.1 Class 10 Maths Question 7.**

**It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?**

**Solution:
**As the probability of 2 students not having the same birthday, P (not E) – 0.992

∴ Probability of students having the same birthday,

P(E) = 1 – P(not E) = 1 – 0.992 = 0.008

**Ex 15.1 Class 10 Maths Question 8.**

**A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is**

**(i)** red?

**(ii)** not red?

**Solution:**

Number of red balls = 3

Number of black balls = 5

Total number of balls = 5 + 3 = 8

**(i)** P(red ball) = \(\frac { 3 }{ 8 } \)

**(ii)** P(black ball) = \(\frac { 5 }{ 8 } \)

**Ex 15.1 Class 10 Maths Question 9.**

**A box contains 5 red marbles, 8 white marbles, and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be**

**(i)** red?

**(ii)** white?

**(iii)** not green?

**Solution:**

Number of red marbles = 5

Number of white marbles = 8

Number of green marbles = 4

Total number of marbles = 5 + 8 + 4 = 17

**(i)** P (red marble) = \(\frac { 5 }{ 17 }\)

**(ii)** P (white marble) = \(\frac { 8 }{ 17 }\)

**(iii)** P (not green) = 1 – P(green) = 1 – \(\frac { 4 }{ 17 } =\frac { 13 }{ 17 } \)

**Ex 15.1 Class 10 Maths Question 10.**

**A piggy bank contains hundred 50 p coins, fifty ₹ 1 coins, twenty ₹ 2 coins, and ten ₹ 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin**

**(i)** will be a 50 p coin?

**(ii)** will not be a ₹ 5 coin?

**Solution:**

Number of 50 p coins = 100

Number of ₹ 1 coins = 50

Number of ₹ 2 coins = 20

Number of ₹ 5 coins = 10

Total number of coins = 100 + 50 + 20 + 10 = 180

**Ex 15.1 Class 10 Maths Question 11.**

**Gopi buys a fish from a shop for his aquarium. The shopkeeper takes out one fish at random from a tank containing 5 male fish and 8 female fish (see figure). What is the probability that the fish taken out is a male fish?**

**Solution:**

Total number of fish in the tank = 5 + 8 = 13

Number of male fish = 5

∴ P (a male fish) = \(\frac { 5 }{ 13 }\)

**Ex 15.1 Class 10 Maths Question 12.**

**A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see figure.), and these are equally likely outcomes. What is the probability that it will point at**

**(i)** 8?

**(ii)** an odd number?

**(iii)** a number greater than 2?

**(iv)** a number less than 9?

Solution:

Total number of outcomes = 8

(i) P (getting 8) = \(\frac { 1 }{ 8 }\)

(ii) Number of favourable outcomes = 4(1, 3, 5, 7)

∴ P (an odd number) = \(\frac { 4 }{ 8 }\) = \(\frac { 1 }{ 2 }\)

(iii) Number of favourable outcomes = 6(numbers less than 9)

∴ P (a number greater than 2) = \(\frac { 6 }{ 8 }\) = \(\frac { 3 }{ 4 }\)

(iv) Number of favourable outcomes = 8(numbers less than 9)

∴ P (a number less than 9) = \(\frac { 8 }{ 8 }\) = 1

**Ex 15.1 Class 10 Maths Question 13.**

**A die is thrown once. Find the probability of getting**

**(i)** a prime number

**(ii)** a number lying between 2 and 6

**(iii)** an odd number

**Solution:
**

**Ex 15.1 Class 10 Maths**Question 14.**One card is drawn from a well-shuffled deck of 52 cards. Find the probability of getting**

**(i)**a king of red colour

**(ii)**a face card

**(iii)**a red face card

**(iv)**the jack of hearts

**(v)**a spade

**(vi)**the queen of diamonds

**Solution:**

**Ex 15.1 Class 10 Maths Question 15.**

**Five cards – the ten, jack, queen, king and ace of diamonds, are well shuffled with their face downwards. One card is then picked up at random.**

**(i)** What is the probability that the card is the queen?

**(ii)** If the queen is drawn and put aside, what is the probability that the second card picked up is

**(a)** an ace?

**(b)** a queen?

**Solution:**

**Ex 15.1 Class 10 Maths Question 16.**

**12 defective pens are accidentally mixed with 132 good ones. It is not possible to just look at a pen and tell whether or not it is defective. One pen is taken out at random from this lot. Determine the probability that the pen is taken out is a good one.**

**Solution:**

Number of good pens = 132

Number of defective pens = 12

Total number of pens = 12 + 132 = 144

Number of favorable outcomes = Number of good pens = 132

∴ P (gettinggood one) = \(\frac { 132 }{ 144 }\) = \(\frac { 11 }{ 12 }\)

**Ex 15.1 Class 10 Maths Question 17.**

**(i) A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective?**

**(ii) Suppose the bulb drew in (i) is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective?**

**Solution:
**

**Ex 15.1 Class 10 Maths **Question 18.

**A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the ****probability that it bears**

**(i)** a two digit number.

**(ii)** a perfect square number.

**(iii)** a number divisible by 5.

**Solution:
**

**Ex 15.1 Class 10 Maths **Question 19.

**A child has a die whose six faces show the letters as given below:**

**The die is thrown once. What is the probability of getting**

**(i)** A?

**(ii)** D?

**Solution:
**

**Ex 15.1 Class 10 Maths **Question 20.

**Suppose you drop a die at random on the rectangular region shown in the figure. What is the probability that it will land inside the circle with diameter 1 m?**

Solution:

**Ex 15.1 Class 10 Maths Question 21.**

**A lot consists of 144 ball pens of which 20 are defective and the others are good. Nuri will buy a pen if it is good, but will not buy if it is defective. The shopkeeper draws one pen at random and gives it to her. What is the probability that**

**(i)** she will buy it?

**(ii)** she will not buy it?

**Solution:
**

**Ex 15.1 Class 10 Maths**Question 22.**Two dice, one blue and one grey, are thrown at the same time. Now**

**(i)**Complete the following table:

**(ii)**A student argues that-there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability \(\frac { 1 }{ 11 }\). Do you agree with this argument? Justify your answer.

**Solution:**

**(ii)**No. From the table, it is clear that events are not equally likely and these the probability too.

**Ex 15.1 Class 10 Maths Question 23.**

**A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result, i.e. three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.**

**Solution:**

Total outcomes are HHH, TTT, HHT, HTH, THH, TTH, THT, HTT

so, there are 8 outcomes

Hanif will lose the game if outcomes are HHT, HTH, THH, TTH, THT, HTT

So, favourable outcomes = 6

∴ P(Hanif will lose the game) = \(\frac { 6 }{ 8 }\) = \(\frac { 3 }{ 4 }\).

**Ex 15.1 Class 10 Maths Question 24.**

**A die is thrown twice. What is the probability that**

**(i)** 5 will not come up either time?

**(ii)** 5 will come up at least once?

**Solution:**

**Ex 15.1 Class 10 Maths Question 25.**

**Which of the following arguments are correct and which are not correct? Give reasons for your answer.**

**(i)** If two coins are tossed simultaneously there are three possible outcomes- two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is \(\frac { 1 }{ 3 }\).

**(ii)** If a die is thrown, there are two possible outcomes- an odd number or an even number. Therefore, the probability of getting an odd number is \(\frac { 1 }{ 2 }\).

**Solution:**

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