NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2

NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2.

• Squares and Square Roots Class 8 Ex 6.1
• Squares and Square Roots Class 8 Ex 6.3
• Squares and Square Roots Class 8 Ex 6.4

Board	CBSE
Textbook	NCERT
Class	Class 8
Subject	Maths
Chapter	Chapter 6
Chapter Name	Squares and Square Roots
Exercise	Ex 6.2
Number of Questions Solved	2
Category	NCERT Solutions

NCERT Solutions for Class 8 Maths Chapter 6 Squares and Square Roots Ex 6.2

Ex 6.2 Class 8 Maths Question 1.
Find the square of the following numbers,
(i) 32
(ii) 35
(iii) 86
(iv) 93
(v) 71
(vi) 46
Solution:
(i) 32² = (30 + 2)²
= 30 (30 + 2) + 2 (30 + 2)
= 30² +30 x 2 + 2 x 30 + 2²
= 900 + 60 + 60 + 4 = 1024

(ii) = (30 + 5)² = 30 (30 + 5) + 5 (30 + 5)
= 30 ² + 30 x 5 + 5 x 30 + 5²
= 900 +150 +150 + 25 = 1225

(iii) = (80 + 6)² = 80 (80 + 6) + 6 (80 + 6)
= 80² +80 x 6 + 6 x 80 + 62
= 6400 + 480 + 480 + 36 = 7396

(iv) = (90 + 3)² = 90 (90 + 3) + 3 (90 + 3)
= 90² + 90 x 3 + 3 x 90 + 92
= 8100 + 270 + 270 + 81 = 8649

(v) = (70 +1)² = 70 (70 +1) +1 (70 +1)
= 70² +70 x 1 + 1 x 70 + 1²
= 4900 + 70 + 70 +1 = 5041

(vi) = (40 + 6)² = 40 (40 + 6) + 6 (40 + 6)
= 40² + 40 x 6 + 6 x 40 +6 x 6
= 1600 +240+240 +36 =2116

Ex 6.2 Class 8 Maths Question 2.
Write a Pythagorean triplet whose one member is
(i) 6
(ii) 14
(iii) 16
(iv) 18
Solution:
(i) Put m = 3 in 2m, m² -1, m² +1
∴ 2m=6, m² – l =3² – 1= 9 – 1 = 8
and m² + 1=9 + 1=10
Thus, 6, 8 and 10 are Pythagorean triplets.

(ii) Put m = 7 in 2m, m² -1, m² +1
∴ 2m = 14, m² – 1 = 7² – 1 = 49 – 1 = 48
and m² + 1 = 72 +1 = 49+1 = 50
Thus, 14, 48 and 50 are Pythagorean triplets.

(iii) Put m = 8 in 2m, m² – 1, m² +1
∴ 2m =16, m² – 1 = 8² – 1 = 64 – 1 =63
and m² + 1 =8² + 1 =64 + 1 =65
Thus, 16, 63 and 65 are Pythagorean triplets.

(iv) Put m = 9 in 2m, m² – 1, m² +1
∴ 2m =18, m² – 1 = 9² – 1=81 – 1 = 80,
m²+ 1 =9² + 1 =81 + 1 =82
Thus, 18, 80 and 82 are Pythagorean triplets.

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