Contents
Selina Concise Mathematics Class 7 ICSE Solutions Chapter 1 Integers
Selina Publishers Concise Mathematics Class 7 ICSE Solutions Chapter 1 Integers
Integers Exercise 1A – Selina Concise Mathematics Class 7 ICSE Solutions
Question 1.
Evaluate:
 427 x 8 + 2 x 427
 394 x 12 + 394 x (2)
 558 x 27 + 3 x 558
Solution:
Question 2.
Evaluate:
 673 x 9 + 673
 1925 x 101 – 1925
Solution:
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Question 3.
Verify:

 37 x {8 +(3)} = 37 x 8 + 37 x – (3)
 (82) x {(4) + 19} = (82) x (4) + (82) x 19
 {7 – (7)} x 7 = 7 x 7 – (7) x 7
 {(15) – 8} x 6 = (15) x (6) – 8 x (6)
Solution:
Question 4.
Evaluate:
 15 x 8
 15 x (8)
 (15) x 8
 (15) x 8
Solution:
Question 5.
Evaluate:
 4 x 6 x 8
 4 x 6 x (8)
 4 x (6) x 8
 (4) x 6 x 8
 4 x (6) x (8)
 (4) x (6) x 8
 (4) x 6 x ( 8)
 (4) x (6) x (8)
Solution:
Question 6.
Evaluate:
 2 x 4 x 6 x 8
 2 x (4) x 6 x 8
 (2) x 4 x (6) x 8
 (2) x (4) X 6 x (8)
 (2) x (4) x (6) x (8)
Solution:
Question 7.
Determine the integer whose product with ‘1’ is:
 47
 63
 1
 0
Solution:
Question 8.
Eighteen integers are multiplied together. What will be the sign of their product, if:
 15 of them are negative and 3 are positive?
 12 of them are negative and 6 are positive?
 9 of them are positive and the remaining are negative?
 all are negative?
Solution:
Question 9.
Find which is greater?
 (8 + 10) x 15 or 8 + 10 x 15
 12 x (6 – 8) or 12 x 6 – 8
 {(3) – 4} x (5) or (3) – 4 x (5)
Solution:
Question 10.
State, true or false :
 product of two integers can be zero.
 product of 120 negative integers and 121 positive integers is negative.
 a x (b + c) = a x b + c
 (b – c) x a=b – c x a
Solution:
Integers Exercise 1B – Selina Concise Mathematics Class 7 ICSE Solutions
Question 1.
Divide:
(i) 117 by 9
(ii) (117) by 9
(iii) 117 by (9)
(iv) (117) by (9)
(v) 225 by (15)
(vi) (552) ÷ 24
(vii) (798) by (21)
(viii) (910) ÷ – 26
Solution :
Question 2.
Evaluate:
(i) (234) ÷ 13
(ii) 234 ÷ (13)
(iii) (234) ÷ (13)
(iv) 374 ÷ (17)
(v) (374) ÷ 17
(vi) (374) ÷ (17)
(vii) (728) ÷ 14
(viii) 272 ÷ (17)
Solution:
Question 3.
Find the quotient in each of the following divisions:
(i) 299 ÷ 23
(ii) 299 ÷ (23)
(iii) (384) ÷ 16
(iv) (572) ÷ (22)
(v) 408 ÷ (17)
Solution:
Question 4.
Divide:
(i) 204 by 17
(ii) 152 by19
(iii) 0 by 35
(iv) 0 by (82)
(v) 5490 by 10
(vi) 762800 by 100
Solution:
Question 5.
State, true or false :
 0 ÷ 32 = 0
 0 ÷ (9) = 0
 (37) ÷ 0 = 0
 0 ÷ 0 = 0
Solution:
Question 6.
Evaluate:
(i) 42 ÷ 7 + 4
(ii) 12+18 ÷ 3
(iii) 19 – 20 ÷ 4
(iv) 16 – 5 x 3+4
(v) 6 – 8 – (6) ÷ 2
(vi) 13 12 ÷ 4 x 2
(vii) 16 + 8 ÷ 4 2 x 3
(viii) 16 ÷ 8 + 4 – 2 x 3
(ix) 16 – 8 + 4 ÷ 2 x 3
(x) (4) + (12) ÷ (6)
(xi) (18) + 6 ÷ 3 + 5
(xii) (20) x (1) + 14 – 7
Solution:
Integers Exercise 1C – Selina Concise Mathematics Class 7 ICSE Solutions
Question 1.
Evaluate:
18(20 15 ÷ 3)
Solution:
Question 2.
15+ 24÷ (1513)
Solution:
Question 3.
35 – [15 + {14(13 + \(\overline { 21+3 }\))}]
Solution:
Question 4.
27 [13 + {4(8 + 4 – \(\overline { 1+3 }\))}]
Solution:
Question 5.
32 – [43{51 (20 – \(\overline { 18 7 }\))}]
Solution:
Question 6.
46[26{14(154÷ 2 x 2)}]
Solution:
Question 7.
45 – [38 – {60 ÷ 3 – (6 – 9 ÷ 3) ÷ 3}]
Solution:
Question 8.
17 [17 — {17 — (17 – \(\overline { 17 17 }\))}]
Solution:
Question 9.
2550 – [510 – {270 – (90 – \(\overline { 80 + 7 }\))}]
Solution:
Question 10.
30+ [{2 x (25\(\overline { 13 3 }\))}]
Solution:
Question 11.
88{5(48)+ (16)}
Solution:
Question 12.
9 x (8\(\overline { 3 +2 }\)) – 2 (2 + \(\overline { 3 +3 }\))
Solution:
Question 13.
2 – [3 – {6 – (5 – \(\overline { 4 3 }\))}]
Solution:
Integers Exercise 1D – Selina Concise Mathematics Class 7 ICSE Solutions
Question 1.
The sum of two integers is 15. If one of them is 9, find the other.
Solution:
Question 2.
The difference between an integer and 6 is 5. Find the values of x.
Solution:
Question 3.
The sum of two integers is 28. If one integer is 45, find the other.
Solution:
Question 4.
The sum of two integers is 56. If one integer is 42, find the other.
Solution:
Question 5.
The difference between an integer x and (9) is 6. Find all possible values ofx.
Solution:
Question 6.
Evaluate:
 (1) x (1) x (1) x ….60 times.
 (1) x (1) x (1) x (1) x …. 75 times.
Solution:
Question 7.
Evaluate:
 (2) x (3) x (4) x (5) X (6)
 (3) x (6) x (9) x (12)
 (11) x (15) + (11) x (25)
 10 x (12) + 5 x (12)
Solution:
Question 8.
 If x x (1) = 36, is x positive or negative?
 If x x (1) = 36, is x positive or negative?
Solution:
∴ It is a positive integer.
Question 9.
Write all the integers between 15 and 15, which are divisible by 2 and 3.
Solution:
Question 10.
Write all the integers between 5 and 5, which are divisible by 2 or 3.
Solution:
Question 11.
Evaluate:
 (20) + (8) ÷ (2) x 3
 (5) – (48) ÷ (16) + (2) x 6
 16 + 8 ÷ 4 2 x 3
 16 ÷ 8 x 4 – 2 x 3
 27 – [5 + {28 – (29 – 7)}]
 48 – [18 – {16 – (5 – \(\overline { 4 +1 }\))}]
 8 – {6 (9 – 11) + 18 = 3}
 (24 ÷ \(\overline { 12 9 }\) – 12) – (3 x 8 ÷ 4 + 1)
Solution:
Question 12.
Find the result of subtracting the sum of all integers between 20 and 30 from the sum of all integers from 20 to 30.
Solution:
Question 13.
Add the product of (13) and (17) to the quotient of (187) and 11.
Solution:
Question 14.
The product of two integers is180. If one of them is 12, find the other.
Solution:
Question 15.
 A number changes from 20 to 30. What is the increase or decrease in the number?
 A number changes from 40 to 30. What is the increase or decrease in the number?
Solution: