Contents

**Algebraic Expressions – Maharashtra Board Class 6 Solutions for Mathematics (English Medium)**

MathematicsGeneral ScienceMaharashtra Board Solutions

### Exercise-50

**Solution 1:**

### Exercise-51

**Solution 1:**

- Groups of like terms:

i. (5x, -8x)

ii. (-7y, 6y, -y)

iii. (-3m, m)

iv.(2z, 5z) - Groups of like terms:

i. (4x^{2}, -10x^{2})

ii. (-7y^{3}, -y^{3}, 5y^{3}) - Groups of like terms:

i. (2x^{2}yz, 7yzx^{2})

ii. (xyz^{2}, -6xyz^{2})

iii. (xzy, -xyz)

### Exercise-52

**Solution 1:**

Monomials: (2), (5), (6), (7)

Binomials: (3), (8)

Trinomials: (1), (4), (9)

### Exercise-53

**Solution 1:**

- 5 – x

= 5 – 4 (x = 4)

= 1 - 3 (5 – x)

= 3 (5 – 4) (x = 4)

= 3 (1)

= 3 - (5 – x)
^{2}

= (5 – 4)^{2}(x = 4)

= 12

= 1 - (x + 2)
^{2}

= (4 + 2)^{2}

= (6)^{2}

= 36 - 3 (x + 2)

= 3 (4 + 2) (x = 4)

= 3 (6)

= 18 - 2 (x + 2) + 3

= 2(4 + 2) + 3 (x = 4)

= 2(6) + 3

= 12 + 3

= 15

**Solution 2:**

- 5x – 3

= 5(3) – 3

= 15 – 3

= 12 - x
^{2}

= (3)^{2}

= 9 - 2x
^{3}

= 2(3)^{3}

= 2(27)

= 54 - 5 x
^{2}+ x

= 5(3)^{2}+ 3

= 5(9) + 3

= 45 + 3

= 48 - x
^{2}+ 2x

= (3)^{2}+ 2(3)

= 9 + 6

= 15

**Solution 3:**

- 2a + 5b

= 2 × 3 + 5 × 4

= 6 + 20

= 26 - a + b + c

= 3 + 4 + (- 2)

= 7 – 2

= 5 - b
^{2}+ a^{2}– c^{2}

= (4)^{2}+ (3)^{2}– (-2)^{2}

= 16 + 9 – 4

= 25 – 4

= 21 - b
^{2}– a^{2}

= (4)^{2}– (3)^{2}

= 16 – 9

= 7

**Solution 4:**

- p
^{2}+ q^{2}

= (3)^{2}+ (5)^{2}

= 9 + 25

= 34 - p
^{2}– 2pq + q^{2}

= (3)^{2}– 2 × 3 × 5 + 5^{2}

= 9 – 30 + 25

= 9 + 25 – 30

= 34 – 30

= 4 - qp + 3q

= 5 × 3 + 3 × 5

= 15 + 15

= 30 - p
^{2}+ 2p + q

= (3)^{2}+ 2 × 3 + 5

= 9 + 6 + 5

= 20