• Skip to main content
  • Skip to secondary menu
  • Skip to primary sidebar
  • Skip to footer

CBSE Tuts

CBSE Maths notes, CBSE physics notes, CBSE chemistry notes

  • NCERT Solutions
    • NCERT Solutions for Class 12 English Flamingo and Vistas
    • NCERT Solutions for Class 11 English
    • NCERT Solutions for Class 11 Hindi
    • NCERT Solutions for Class 12 Hindi
    • NCERT Books Free Download
  • TS Grewal
    • TS Grewal Class 12 Accountancy Solutions
    • TS Grewal Class 11 Accountancy Solutions
  • CBSE Sample Papers
  • NCERT Exemplar Problems
  • English Grammar
    • Wordfeud Cheat
  • MCQ Questions

The Electric Spark – Maharashtra Board Class 10 Solutions for Science and Technology

The Electric Spark – Maharashtra Board Class 10 Solutions for Science and Technology (English Medium)

AlgebraGeometryScience & TechnologyHistoryGeography & EconomicsEnglish

Solution 1.1:

(b) 10-3 A

Solution 1.2:

(a) series

Solution 1.3:

(b) 3.6 × 106 Joule

Solution 1.4:

(b) 4 A

Solution 2:

  1. False. The SI unit of charge is coulomb.
  2. False. Voltmeter is always connected in parallel with the device.
  3. True
  4. True
  5. False. Resistivity of pure metal is less than alloys.
  6. False. The electric bulb consists of the filament whose melting point is high.

Solution 3:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-1(3)

Solution 4.1:

  1. A fuse is connected in series in the circuit to protect the appliances from damage due to high current.
  2. When the current in the circuit passes through the fuse, its temperature increases. When the current exceeds the specified value, the fuse should melt to break the circuit. Therefore, the material used for the fuse has a low melting point.

Solution 4.2:

  1. For the conduction of electricity through any material, two conditions are necessary. The first condition is potential difference, and the second is free charge carriers which can be accelerated by potential difference.
  2. Wood and glass do not have such charge carriers, so they cannot conduct electricity. Hence, wood and glass are good insulators.

Solution 4.3:

  1. We get light from the bulb due to heating of the filament by passing a current through it.
  2. The light emitted by the filament depends on the temperature of it. The intensity of light increases with the temperature.
  3. The melting point of a filament of a bulb is very high, so that it can withstand high temperature without melting and can give more light.

Solution 4.4:

  1. For the conduction of electricity, good conducting material is required.
  2. Copper and aluminum are good conductors as they provide a conducting path for motion of electrons through the circuit.
  3. They have free electrons which can be accelerated by a potential difference. Therefore, connecting wires in a circuit are made of copper and aluminum.

Solution 5.1:

The potential difference between two points is said to be 1 volt if 1 joule of work is done in moving 1 coulomb of electric charge from one point to another.

The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-2(5.1)

Solution 5.2:

If one coulomb of charge is passing through any cross section of a conductor in one second, the amount of current flowing through it is called one ampere.

1 A = 1 C/s

Solution 5.3:

If one ampere current flows through a conductor when 1 volt potential difference is applied across it, its resistance is one ohm.
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-3(5.3)

Solution 5.4:

The electric level at a point is called the electric potential at that point.

Solution 5.5:

The resistivity of a conductor is the resistance of a conductor of unit length and unit area of cross section.

Solution 5.6:

Electric power is the electric work done per unit time. Its SI unit is watt (W).

Electric power (P) = 

Solution 6.1:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-4(6.1)

Solution 6.2:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-5(6.2)

Solution 6.3:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-6(6.3)

Solution 6.4:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-7(6.4)

Solution 7.1:

The electric current flowing in a metallic conductor is directly proportional to the potential difference across its terminals, provided the physical conditions of the conductor such as its length, area of cross section, temperature and material remain constant.

Solution 7.2:

The quantity of heat (H) generated in a conductor of resistance (R) when a current (I) flows through it for a time (t) is directly proportional to

  1. Square of the current
  2. Resistance of the conductor
  3. Time for which the current flows

Solution 8(a):

    1. Expression for the resistors in series:

The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-8(8{a})

R1, R2 and R3 are the three resistors connected in series between points C and D as shown in the figure above. I is the current and V is the PD across points C and D.
Then Rs is the effective resistance in a circuit and V1, V2 and V3  are the potentials across the three resistors such that
V = V1 + V2 + V3 —- (1)
Using Ohm’s law, the total potential difference
V = I Rs
and V1 = IR1, V2 = IR2 and V3 = IR3
Substituting these values in equation 1,
we get
IRs = IR1 + IR2 + IR3
 ∴ Rs = R1 + R2 + R3
For n number of resistors connected in series,
  Rs =  R1 + R2 + R3 + R4 + —– + Rn

 2. Expression for the resistors in parallel:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-9(8{a})

R1,R2 and R3 are the three resistors connected in parallel between points C and D as shown in the figure.
Let I1,I2 and I3 be the currents passing through R1, R2 and R3, respectively. Let V be the potential difference between points C and D. The current I will be given by
I = I1 + I2 + I3 —– (1)
Let Rp be the effective resistance in the circuit.
Using Ohm’s law, we get

I1 = 

Putting these values in equation 1, we get
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-10(8{a})

Solution 8(b):

The resistance R of a conductor is directly proportional to its length l and inversely proportional to its area of cross section A.
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-11(8{b})

Solution 9.1:

  1. Wires P and Q have the same resistivity as they are made of the same metal.
  2. Wires P and Q have different resistances.

Resistance       

   where l is length and A is the area of cross section of a conductor. Here r and l are the same for P and Q, but A is not. Hence, the wires have different resistances.

Solution 9.2:

Silver will be the best conductor, because when the resistivity is lower, the conductivity is greater.

Solution 9.3:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-12(9.3)

Solution 9.4:

Assuming that the bulbs have a filament of the same length and the same area of cross section but are made of metals with different resistivity, then the bulb with higher resistance will be brighter.

Solution 10.1(a):

The resistors of resistances 20 Ω, 3.5 Ω and 4.9 Ω are connected in series. Therefore,

R4 = 20 + 3.5 + 4.9 = 28.4 Ω

Solution 10.1(b):

Parallel combination of resistors:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-13(10.1{b})

Solution 10.2:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-14(10.2)

Solution 10.3:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-15(10.3)

Solution 10.4:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-16(10.4)

Solution 10.5:

The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-17(10.5)

Solution 10.6:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-18(10.6)

Solution 10.7:

The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-19(10.7)

Solution 10.8:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-20(10.8)

Solution 10.9:
The Electric Spark - Maharashtra Board Class 10 Solutions for Science and Technology-21(10.9)

Primary Sidebar

NCERT Exemplar problems With Solutions CBSE Previous Year Questions with Solutoins CBSE Sample Papers
  • The Summer Of The Beautiful White Horse Answers
  • Job Application Letter class 12 Samples
  • Science Lab Manual Class 9
  • Letter to The Editor Class 12 Samples
  • Unseen Passage For Class 6 Answers
  • NCERT Solutions for Class 12 Hindi Core
  • Invitation and Replies Class 12 Examples
  • Advertisement Writing Class 11 Examples
  • Lab Manual Class 10 Science

Recent Posts

  • Understanding Diversity Question Answer Class 6 Social Science Civics Chapter 1 NCERT Solutions
  • Our Changing Earth Question Answer Class 7 Social Science Geography Chapter 3 NCERT Solutions
  • Inside Our Earth Question Answer Class 7 Social Science Geography Chapter 2 NCERT Solutions
  • Rulers and Buildings Question Answer Class 7 Social Science History Chapter 5 NCERT Solutions
  • On Equality Question Answer Class 7 Social Science Civics Chapter 1 NCERT Solutions
  • Role of the Government in Health Question Answer Class 7 Social Science Civics Chapter 2 NCERT Solutions
  • Vital Villages, Thriving Towns Question Answer Class 6 Social Science History Chapter 9 NCERT Solutions
  • New Empires and Kingdoms Question Answer Class 6 Social Science History Chapter 11 NCERT Solutions
  • The Delhi Sultans Question Answer Class 7 Social Science History Chapter 3 NCERT Solutions
  • The Mughal Empire Question Answer Class 7 Social Science History Chapter 4 NCERT Solutions
  • India: Climate Vegetation and Wildlife Question Answer Class 6 Social Science Geography Chapter 8 NCERT Solutions
  • Traders, Kings and Pilgrims Question Answer Class 6 Social Science History Chapter 10 NCERT Solutions
  • Environment Question Answer Class 7 Social Science Geography Chapter 1 NCERT Solutions
  • Understanding Advertising Question Answer Class 7 Social Science Civics Chapter 7 NCERT Solutions
  • The Making of Regional Cultures Question Answer Class 7 Social Science History Chapter 9 NCERT Solutions

Footer

Maths NCERT Solutions

NCERT Solutions for Class 12 Maths
NCERT Solutions for Class 11 Maths
NCERT Solutions for Class 10 Maths
NCERT Solutions for Class 9 Maths
NCERT Solutions for Class 8 Maths
NCERT Solutions for Class 7 Maths
NCERT Solutions for Class 6 Maths

SCIENCE NCERT SOLUTIONS

NCERT Solutions for Class 12 Physics
NCERT Solutions for Class 12 Chemistry
NCERT Solutions for Class 11 Physics
NCERT Solutions for Class 11 Chemistry
NCERT Solutions for Class 10 Science
NCERT Solutions for Class 9 Science
NCERT Solutions for Class 7 Science
MCQ Questions NCERT Solutions
CBSE Sample Papers
NCERT Exemplar Solutions LCM and GCF Calculator
TS Grewal Accountancy Class 12 Solutions
TS Grewal Accountancy Class 11 Solutions