GSEB Solutions for Class 6 Mathematics – Polynomial
GSEB SolutionsMathsScience
Activity
Solution 1:
- 4x2, 7x2 and 2x2
- -y3, -y3 and 3y3
- 2xy2 and 3xy2
- 6x7 and x7
Solution 2:
- 5x, 2x2
- -3x, 7x2
- 8xy3, 8yx3
- a2b2, 7ab
- -x, 5x
Solution 3:
4x2, -y2
4b2, p2
4x2, p2
(Note: Many more answers are possible.)
Exercise
Solution 1:
Solution 2:
The polynomials having constant terms are given below.
4x2 + 2x – 3, x + 4, 6a2 + 5ab + 7, 16, 6x2 – 6x + 5
Solution 3:
(1) The pairs of like terms are: 4x2and 3x2;– x and – 2x.
(2) The pairs of like terms are: – 8x2 and 7x2;7x and – 2x; 3y and -y.
(3) The pairs of like terms are: 2ab and – ab; b2 and 3b2 .
Solution 4:
(1) m + 3 = 2 + 3 = 5
(2) 4m2 = 4 × (2 × 2) = 4 × 4 = 16
(3) m2 + 6 = (2 × 2) + 6 = 4 + 6 = 10
(4) 3n2 = 3(1 × 1) = 3
(5) 5m – 6n = (5 × 2) – (6 × 1) = 10 – 6 = 4
(6) mn – n = (2 × 1) – 1 = 2 – 1 = 1
(7) n2 + 3mn = (1 × 1) + 3(2 × 1) = 1 + 6 = 7
(8) 2m – 3n2 = (2 × 2) – 3(1 × 1) = 4 – 3 = 1
(9) 3m2 – 12mn + 4n2
= 3(2 × 2) – 12(2 × 1) + 4(1 × 1)
= 3(4) – 12(2) + 4
= 12 – 24 + 4
= 16 – 24
= (-8)
(10) 3n – 2m2 + 3
= 3(1) -2(2 × 2) + 3
= 3 – 2(4) + 3
= 3 – 8 + 3
= 6 – 2
= (-2)
Practice – 1
Solution 1:
(1) 7x3 + 8x2 + 9xy + 4y2
There are 4 terms in the polynomial.
(2) 2xy + 3x2 – 25y3
There are three terms in the polynomial.
(3) a2bc
There is only on term in the polynomial.
(4) 6a + 5b – 10ab – a2 – b2
There are five terms in the polynomial.
Solution 2:
Polynomials having different terms:
1) 6a + 5b – 10ab
2) 10ab – a2bc
3) 2a2b2
4) 8ab4c
5) 6a -3b
6) y2 + 2xy + 3x2
Solution 3:
The polynomials written in question 2 can be classified into monomials, binomials and trinomials as follows:
Practice – 2
Solution 1:
The monomials from the list of given polynomials are as follows:
8ab, -9x2, -7x2y2, 9abc
Solution 2:
The table below shows three illustrations each of monomial, binomial and trinomial:
Practice – 3
Solution 1:
Solution 2:
Solution 3:
(1) The coefficient of the term x2 is 1.
[x2 = 1 × x2]
(2) The power of the term 3abc is 3.
The power of the term 3abc is = 1 + 1 + 1 = 3
(3) The power of the term 7 in 12x + 7 is 0.
7 is the constant term and in a constant term, the power of the variable is zero.
7 = 7 × x0 …. (x0 = 1)
Practice – 4
Solution 1:
The pairs of like terms are:
- 7x2 and -5x2
- -3y2 and -10y2
- 3a2b2 and 6a2b2
- xy and 3xy
Solution 2:
The pairs of unlike terms are:
(1) 5x and 3xy
(2) -3y2 and -5x2
(3) xy and 7ab
(4) -10y2 and 6a2b2
[Note: Many more pairs of unlike terms are possible in the given example.]
Practice – 5
Solution 1:
(1) x + y = 1 + 3 = 4
(2) x + y – a = 1 + 3 + 2 = 6
(3) 4x – y = 4 + 3 = 1
(4) a2 – x = (2 × 2) – 1 = 4 – 1 = 3
(5) x2 = (x × x) = (1 × 1) = 1
(6) 3a + xy = (3 × 2) + (1 × 3) = 6 + 3 = 9
(7) y2 – a2 = (y × y) – (a × a) = (3 × 3) – (2 × 2) = 9 – 4 = 5
(8) x2 – 6xy + y2 = (x × x) – 6 × x × y + (y × y)
= (1 × 1) – (6× 1 × 3) + (3 × 3)
= 1 – 18 + 9
= -8
(9) 4x2 + 2xy + 9y2 = 4(x × x) + 2 × x × y + 9(y × y)
= 4(1 × 1) + (2 × 1 × 3) + 9(3 × 3)
= 4 + 6 + 81
= 91
(10) a2 – 6ax + 9x2
= (a × a) – (6 × a × x) + 9(x × x)
= (2 × 2) – (6 × 2 × 1) + 9(1 × 1)
= 4 – 12 + 9
= 13 – 12 = 1