**GSEB Solutions for Class 9 Mathematics – Heron’s Formula (English Medium)**

GSEB SolutionsMathsScience

**Exercise – 14**

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**Solution 12(1):**

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b. 26 cm

Perimeter of a trapezium

= Sum of parallel sides + Sum of non-parallel sides

∴50 = Sum of parallel sides + 12 + 12

∴ Sum of parallel sides = 50 – 12 – 12 = 26 cm

**Solution 12(4):**

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**Solution 12(6):**

c. 9

Perimeter of an isosceles triangle = Base + 2 × Length of each congruent side

∴ 28 = 10 + 2 × Length of each congruent side

∴ Length of each congruent side = 9 cm.

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**Solution 12(12):**

d. 41

In ΔABC, m∠B = 90

AC^{2} = AB^{2} + BC^{2} = 9^{2} + 40^{2} = 81 + 1600 = 1681 = (41)^{2}

∴ AC = 41

**Exercise – 14.1**

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**Exercise – 14.2**

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