GSEB Solutions for Class 9 Mathematics – Heron’s Formula

GSEB Solutions for Class 9 Mathematics – Heron’s Formula (English Medium)

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Exercise – 14

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b. 26 cm
Perimeter of a trapezium
= Sum of parallel sides + Sum of non-parallel sides
∴50 = Sum of parallel sides + 12 + 12
∴ Sum of parallel sides = 50 – 12 – 12 = 26 cm

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c. 9
Perimeter of an isosceles triangle = Base + 2 × Length of each congruent side
∴ 28 = 10 + 2 × Length of each congruent side
∴ Length of each congruent side = 9 cm.

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d. 41
In ΔABC, m∠B = 90
AC² = AB² + BC² = 9² + 40² = 81 + 1600 = 1681 = (41)²
∴ AC = 41

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Exercise – 14.2

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