GSEB Solutions for Class 9 Mathematics – Heron’s Formula (English Medium)
GSEB SolutionsMathsScience
Exercise – 14
Solution 1:
Solution 2:
Solution 3:
Solution 4:
Solution 5:
Solution 6:
Solution 7:
Solution 8:
Solution 9:
Solution 10:
Solution 11:
Solution 12(1):
Solution 12(2):
Solution 12(3):
b. 26 cm
Perimeter of a trapezium
= Sum of parallel sides + Sum of non-parallel sides
∴50 = Sum of parallel sides + 12 + 12
∴ Sum of parallel sides = 50 – 12 – 12 = 26 cm
Solution 12(4):
Solution 12(5):
Solution 12(6):
c. 9
Perimeter of an isosceles triangle = Base + 2 × Length of each congruent side
∴ 28 = 10 + 2 × Length of each congruent side
∴ Length of each congruent side = 9 cm.
Solution 12(7):
Solution 12(8):
Solution 12(9):
Solution 12(10):
Solution 12(11):
Solution 12(12):
d. 41
In ΔABC, m∠B = 90
AC2 = AB2 + BC2 = 92 + 402 = 81 + 1600 = 1681 = (41)2
∴ AC = 41
Exercise – 14.1
Solution 1:
Solution 2:
Solution 3:
Solution 4:
Solution 5:
Solution 6:
Solution 7:
Exercise – 14.2
Solution 1:
Solution 2:
Solution 3:
Solution 4:
Solution 5: