KSEEB SSLC Solutions for Class 10 Maths – Surds

KSEEB SSLC Solutions for Class 10 Maths – Surds (English Medium)

Exercise 7.1:

Question I(1):

Solution :

Question I(2):

Solution :

Question I(3):

Solution :

Question I(4):

Solution :

Question I(5):

Solution :

Question I(6):

Solution :

Question I(7):

Solution :

Question I(8):

Solution :

Question I(9):

Solution :

Question I(10):

Solution :

Question II(1):

Solution :

Question II(2):

Solution :

Question II(3):

Solution :

Question II(4):

Solution :

Question II(5):

Solution :

Question II(6):

Solution :

Question III(1):

Solution :

Question III(2):

Solution :

Question III(3):

Solution :

Question III(4):

Solution :

Exercise 7.2:

Question I(1):

Solution :

Question I(2):

Solution :

Question I(3):

Solution :

Question I(4):

Solution :

Question I(5):

Solution :

Question I(6):

Solution :

Question I(7):

Solution :

Question I(8):

Solution :

Question II(1):

Solution :

Question II(2):

Solution :

Question II(3):

Solution :

Question II(4):

Solution :

Question II(5):

Solution :

Question II(6):

Solution :

Question II(7):

Solution :

Question II(8):

Solution :

Question III(1):

Solution :

Question III(2):

Solution :

Question III(3):

Solution :

Question III(4):

Solution :

Question III(5):

Solution :

Question III(6):

Solution :

Exercise 7.3:

Question I:

Solution :

Question II:

If the product of two binomial surds is a rational number, then each surd is called the conjugate of the other.

Solution :

Question III(a):

Find the rationalizing factor of the following binomial surd:

Solution :

Question III(b):

Find the rationalizing factor of the following binomial surd:

Solution :

Question III(c):

Find the rationalizing factor of the following binomial surd:

Solution :

Question III(d):

Find the rationalizing factor of the following binomial surd:

Solution :

Exercise 7.4:

Question I(A)(1):

Rationalise the denominator and simplify.

Solution :

*Note: Answer given in the book is incorrect.

Question I(A)(2):

Rationalise the denominator and simplify.

Solution :

Question I(A)(3):

Rationalise the denominator and simplify.

Solution :

Question I(A)(4):

Rationalise the denominator and simplify.

Solution :

Question I(A)(5):

Rationalise the denominator and simplify.

Solution :

Question I(B)(1):

Rationalise the denominator and simplify.

Solution :

Question I(B)(2):

Rationalise the denominator and simplify.

Solution :

Question I(B)(3):

Rationalise the denominator and simplify.

Solution :

Question I(B)(4):

Rationalise the denominator and simplify.

Solution :

Question I(B)(5):

Rationalise the denominator and simplify.

Solution :

Question I(C)(1):

Rationalise the denominator and simplify.

Solution :

⇒ ()
⇒ =
∵ (a+b) (a-b) = a² – b²
⇒
⇒
⇒ 5 + 2√6

Question I(C)(2)

Rationalise the denominator and simplify.

Solution :

Question I(C)(3):

Rationalise the denominator and simplify.

Solution :

*Note : Answer given in the book is incorrect.

Question I(C)(4):

Rationalise the denominator and simplify.

Solution :

Question II(1):

Solution :

Question II(2):

Solution :

Question II(3):

Solution :

Question II(4):

Solution :

Question II(5):

Solution :

Question II(6):

Solution :

Question II(7):

Solution :