NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4

NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4 are part of NCERT Solutions for Class 11 Maths. Here we have given NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4.

• Conic Sections Class 11 Ex 11.1
• Conic Sections Class 11 Ex 11.2
• Conic Sections Class 11 Ex 11.3

Board	CBSE
Textbook	NCERT
Class	Class 11
Subject	Maths
Chapter	Chapter 11
Chapter Name	Conic Sections
Exercise	Ex 11.4
Number of Questions Solved	15
Category	NCERT Solutions

NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4

In each of the Exercises 1 to 6, find the coordinates of the foci and the vertices, eccentricity and the length of the latus rectum of the hyperbolas.

Ex 11.4 Class 11 Maths Question 1.
\(\frac { { x }^{ 2 } }{ 16 } -\frac { { y }^{ 2 } }{ 9 } =1\)
Solution:
Given equation of hyperbola is

Ex 11.4 Class 11 Maths Question 2.
\(\frac { { y }^{ 2 } }{ 9 } -\frac { x^{ 2 } }{ 27 } =1\)
Solution:
Given equation of hyperbola is

Ex 11.4 Class 11 Maths Question 3.
9y² – 4x² = 36
Solution:
Given equation of hyperbola is9y² – 4x² = 36

Ex 11.4 Class 11 Maths Question 4.
16x² – 9y² = 576
Solution:
Given equation of hyperbola is16x² – 9y² = 576

Ex 11.4 Class 11 Maths Question 5.
5y² – 9x² = 36
Solution:
Given equation of hyperbola is
5y² – 9x² = 36

Ex 11.4 Class 11 Maths Question 6.
49y² – 16x² = 784
Solution:
Given equation of hyperbola is49y² – 16x² = 784

In each of the Exercises 7 to 15, find the equations of the hyperbola satisfying the given conditions.

Ex 11.4 Class 11 Maths Question 7.
Vertices (±2,0), foci (±3,0)
Solution:
Vertices are (±2, 0) which lie on x-axis. So the equation of hyperbola in standard form

Ex 11.4 Class 11 Maths Question 8.
Vertices (0, ±5), foci (0, ±8)
Solution:
Vertices are (0, ±5) which lie on x-axis. So the equation of hyperbola in standard form

Ex 11.4 Class 11 Maths Question 9.
Vertices (0, ±3), foci (0, ±5)
Solution:
Vertices are (0, ±3) which lie on x-axis. So the equation of hyperbola in standard form

Ex 11.4 Class 11 Maths Question 10.
Foci (±5, 0), the transverse axis is of length 8.
Solution:
Here foci are (±5, 0) which lie on x-axis. So the equation of the hyperbola in standard

Ex 11.4 Class 11 Maths Question 11.
Foci (0, ±13), the conjugate axis is of length 24.
Solution:
Here foci are (0, ±13) which lie on y-axis.
So the equation of hyperbola in standard

Ex 11.4 Class 11 Maths Question 12.
Foci (\(\pm 3\sqrt { 5 } \),0) , the latus rectum is of length 8.
Solution:
Here foci are (\(\pm 3\sqrt { 5 } \), 0) which lie on x-axis.
So the equation of the hyperbola in standard

Ex 11.4 Class 11 Maths Question 13.
Foci (±4, 0), the latus rectum is of length 12.
Solution:
Here foci are (±4, 0) which lie on x-axis.
So the equation of the hyperbola in standard

Ex 11.4 Class 11 Maths Question 14.
Vertices (+7, 0), e = \(\frac { 4 }{ 3 } \)
Solution:
Here vertices are (±7, 0) which lie on x-axis.
So, the equation of hyperbola in standard

Ex 11.4 Class 11 Maths Question 15.
Foci (0, \(\pm \sqrt { 10 } \)), passing through (2, 3).
Solution:
Here foci are (0, \(\pm \sqrt { 10 } \)) which lie on y-axis.
So the equation of hyperbola in standard form

We hope the NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4 help you. If you have any query regarding NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections EX 11.4, drop a comment below and we will get back to you at the earliest.