NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4 are part of NCERT Solutions for Class 11 Maths. Here we have given NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 11 |

Subject |
Maths |

Chapter |
Chapter 11 |

Chapter Name |
Conic Sections |

Exercise |
Ex 11.4 |

Number of Questions Solved |
15 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 11 Maths Chapter 11 Conic Sections Ex 11.4

**In each of the Exercises 1 to 6, find the coordinates of the foci and the vertices, eccentricity and the length of the latus rectum of the hyperbolas.**

**Ex 11.4 Class 11 Maths Question 1.**

\(\frac { { x }^{ 2 } }{ 16 } -\frac { { y }^{ 2 } }{ 9 } =1\)

**Solution:**

Given equation of hyperbola is

**Ex 11.4 Class 11 Maths Question 2.**

\(\frac { { y }^{ 2 } }{ 9 } -\frac { x^{ 2 } }{ 27 } =1\)

**Solution:**

Given equation of hyperbola is

**Ex 11.4 Class 11 Maths Question 3.**

9y^{2} – 4x^{2} = 36

**Solution:**

Given equation of hyperbola is9y^{2} – 4x^{2} = 36

**Ex 11.4 Class 11 Maths Question 4.**

16x^{2} – 9y^{2} = 576

**Solution:**

Given equation of hyperbola is16x^{2} – 9y^{2} = 576

**Ex 11.4 Class 11 Maths Question 5.**

5y^{2} – 9x^{2} = 36

**Solution:**

Given equation of hyperbola is

5y^{2} – 9x^{2} = 36

**Ex 11.4 Class 11 Maths Question 6.**

49y^{2} – 16x^{2} = 784

**Solution:**

Given equation of hyperbola is49y^{2} – 16x^{2} = 784

**In each of the Exercises 7 to 15, find the equations of the hyperbola satisfying the given conditions.**

**Ex 11.4 Class 11 Maths Question 7.**

Vertices (±2,0), foci (±3,0)

**Solution:**

Vertices are (±2, 0) which lie on x-axis. So the equation of hyperbola in standard form

**Ex 11.4 Class 11 Maths Question 8.**

Vertices (0, ±5), foci (0, ±8)

**Solution:**

Vertices are (0, ±5) which lie on x-axis. So the equation of hyperbola in standard form

**Ex 11.4 Class 11 Maths Question 9.**

Vertices (0, ±3), foci (0, ±5)

**Solution:**

Vertices are (0, ±3) which lie on x-axis. So the equation of hyperbola in standard form

**Ex 11.4 Class 11 Maths Question 10.**

Foci (±5, 0), the transverse axis is of length 8.

**Solution:**

Here foci are (±5, 0) which lie on x-axis. So the equation of the hyperbola in standard

**Ex 11.4 Class 11 Maths Question 11.**

Foci (0, ±13), the conjugate axis is of length 24.

**Solution:**

Here foci are (0, ±13) which lie on y-axis.

So the equation of hyperbola in standard

**Ex 11.4 Class 11 Maths Question 12.**

Foci (\(\pm 3\sqrt { 5 } \),0) , the latus rectum is of length 8.

**Solution:**

Here foci are (\(\pm 3\sqrt { 5 } \), 0) which lie on x-axis.

So the equation of the hyperbola in standard

**Ex 11.4 Class 11 Maths Question 13.**

Foci (±4, 0), the latus rectum is of length 12.

**Solution:**

Here foci are (±4, 0) which lie on x-axis.

So the equation of the hyperbola in standard

**Ex 11.4 Class 11 Maths Question 14.**

Vertices (+7, 0), e = \(\frac { 4 }{ 3 } \)

**Solution:**

Here vertices are (±7, 0) which lie on x-axis.

So, the equation of hyperbola in standard

**Ex 11.4 Class 11 Maths Question 15.**

Foci (0, \(\pm \sqrt { 10 } \)), passing through (2, 3).

**Solution:**

Here foci are (0, \(\pm \sqrt { 10 } \)) which lie on y-axis.

So the equation of hyperbola in standard form

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