NCERT Solutions for Class 11 Maths Chapter 6 Linear Inequalities Ex 6.2 are part of NCERT Solutions for Class 11 Maths. Here we have given NCERT Solutions for Class 11 Maths Chapter 6 Linear Inequalities Ex 6.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 11 |

Subject |
Maths |

Chapter |
Chapter 6 |

Chapter Name |
Linear Inequalities |

Exercise |
Ex 6.2 |

Number of Questions Solved |
10 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 11 Maths Chapter 6 Linear Inequalities Ex 6.2

Solve the following inequalities graphically in two-dimensional plane

**Ex 6.2 Class 11 Maths Question 1.**

x + y < 5

**Solution.**

Consider the equation x + y = 5. It passes through the points (0, 5) and (5, 0). The line x + y = 5 is represented by AB. Consider the inequality x + y < 5

Put x = 0, y = 0

0 + 0 = 0 < 5, which is true. So, the origin O lies in the plane x + y < 5

∴ Shaded region represents the inequality x + y < 5

**Ex 6.2 Class 11 Maths Question 2.**

2x + y ≥ 6

**Solution.**

Consider the equation 2x + y = 6

The line passes through (0, 6), (3, 0).

The line 2x + y = 6 is represented by AB.

Now, consider 2x + y ≥ 6

Put x = 0, y = 0

0 + 0 ≥ 6, which does not satisfy this inequality.

∴ Origin does not lie in the region of 2x + y ≥ 6.

The shaded region represents the inequality 2x + y ≥ 6

**Ex 6.2 Class 11 Maths Question 3.**

3x + 4y ≤ 12

**Solution.**

We draw the graph of the equation 3x + 4y = 12. The line passes through the points (4, 0), (0, 3). This line is represented by AB. Now consider the inequality 3x + 4y ≤ 12

Putting x = 0, y = 0 0 + 0 = 0 ≤ 12, which is true

∴ Origin lies in the region of 3x + 4y ≤ 12 The shaded region represents the inequality 3x + 4y ≤ 12

**Ex 6.2 Class 11 Maths Question 4.**

y + 8 ≥ 2x

**Solution.**

Given inequality is y + 8 ≥ 2x

Let us draw the graph of the line, y+ 8 = 2x

The line passes through the points (4, 0), (0, -8).

This line is represented by AB.

Now, consider the inequality y + 8 ≥ 2x.

Putting x = 0, y = 0

0 + 8 ≥ 0, which is true

∴ Origin lies in the region of y + 8 ≥ 2x

The shaded region represents the inequality y + 8 ≥ 2x.

**Ex 6.2 Class 11 Maths Question 5.**

x – y ≤ 2

**Solution.**

Given inequality is x – y ≤ 2

Let us draw the graph of the line x – y = 2

The line passes through the points (2, 0), (0, -2)

This line is represented by AB.

∴ Origin lies in the region of x – y ≤ 2

The shaded region represents the inequality x – y ≤ 2.

**Ex 6.2 Class 11 Maths Question 6.**

2x – 3y > 6

**Solution.**

We draw the graph of line 2x – 3y = 6.

The line passes through (3, 0), (0, -2)

AB represents the equation 2x – 3y = 6

Now consider the inequality 2x – 3y > 6

Putting x = 0, y = 0

0 – 0 > 6, which is not true

∴ Origin does not lie in the region of 2x – 3y > 6.

The shaded region represents the inequality 2x – 3y > 6

**Ex 6.2 Class 11 Maths Question 7.**

-3x + 2y ≥ -6.

**Solution.**

Let us draw the line -3x + 2y = -6

The line passes through (2, 0), (0, -3)

The line AB represents the equation -3x + 2y = -6

Now consider the inequality -3x+ 2y ≥ -6

Putting x = 0, y = 0

0 + 0 ≥ -6, which is true.

∴ Origin lies in the region of -3x + 2y ≥ -6

The shaded region represents the inequality -3x + 2y ≥ – 6

**Ex 6.2 Class 11 Maths Question 8.**

3y- 5x < 30

**Solution.**

Given inequality is 3y – 5x < 30

Let us draw the graph of the line 3y – 5x = 30

The line passes through (-6, 0), (0, 10)

The line AB represents the equation 3y – 5x = 30

Now, consider the inequality 3y – 5x < 30

Putting x = 0, y = 0

0 – 0 < 30, which is true.

∴ Origin lies in the region of 3y – 5x < 30

The shaded region represents the inequality 3y – 5x < 30

**Ex 6.2 Class 11 Maths Question 9.**

y<- 2

**Solution.**

Given inequality is y < -2 ………(1)

Let us draw the graph of the line y = -2

AB is the required line.

Putting y = 0 in (1), we have

0 < -2, which is not true.

The solution region is the shaded region below the line.

Hence, every point below the line (excluding the line) is the solution area.

**Ex 6.2 Class 11 Maths Question 10.**

x > -3

**Solution.**

Let us draw the graph of x = -3

∴ AB represents the line x = -3

By putting x = 0 in the inequality x > -3

We get, 0 > -3, which is true.

∴ Origin lies in the region of x > -3.

Graph of the inequality x > -3 is shown in the figure by the shaded area

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