NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 10 |

Chapter Name |
Mensuration |

Exercise |
Ex 10.2 |

Number of Questions Solved |
1 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2

Ex 10.2 Class 6 Maths Question 1.

Find the areas of the following figures by counting square:

Solution:

Placing these figures on the centimetre square, we have

**(a)** Full squares = 9

∴ Area covered by the figure = 9 x 1 sq. cm = 9 sq. cm

**(b)** Full squares = 5

∴ Area covered by the figure = 5 x 1 sq. cm = 5 sq. cm

**(c)** Full squares = 2

Half squares = 4

∴ Area covered by the figure \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm

= (2 + 2) sq cm = 4 sq. cm

**(d)** Full squares = 10

∴ Area covered by the figure = 10 x 1 sq. cm = 10 sq. cm

**(e)** Full squares = 10

∴ Area covered by the figure = 10 x 1 sq. cm = 10 sq. cm

**(f)** Full squares = 2

Half squares = 4

∴ Area covered by the figure = \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm

= (2 + 2)sq. cm = 4 sq. cm

**(g)** Full squares = 4

Half squares = 4

∴ Area covered by the figure = \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm

= (4 + 2)sq. cm = 6 sq. cm

**(h)** Full squares = 5

∴ Area covered by the figure = 5 x 1 sq. cm

= 5 sq. cm

**(i)** Full squares = 9

∴ Area covered by the figure = 9 x 1 sq. cm

= 9 sq. cm

**(j)** Full squares = 2

Half squares = 4

∴ Area covered by the figure = \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm

= (2 + 2)sq. cm = 4 sq. cm

**(k)** Full squares = 4

Half squares = 2

∴ Area covered by the figure = \(\left( 4\times 1+2\times \frac { 1 }{ 2 } \right) \) sq. cm

= (4 + 1)sq. cm = 5 sq. cm

**(l)** Full squares = 4

More than half squares = 3

Half square = 2

∴ Area covered by the figure = \(\left( 4\times 1+3\times 1+2\times \frac { 1 }{ 2 } \right) \) sq. cm

= (4 + 3 + 1)sq. cm

= 8 sq. cm

**(m)** Full squares = 7

More than half squares = 7

Half square = 0

∴ Area covered by the figure = \(\left( 7\times 1+7\times 1+0\times \frac { 1 }{ 2 } \right) \) sq. cm

= (7 + 7 + 0)sq. cm

= 14 sq. cm

**(n)** Full squares = 10

More than half squares = 8

Half square = 0

∴ Area covered by the figure = \(\left( 10\times 1+8\times 1+0\times \frac { 1 }{ 2 } \right) \) sq. cm

= (10 + 8 + 0)sq. cm

= 18 sq. cm

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