NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2.
| Board | CBSE |
| Textbook | NCERT |
| Class | Class 6 |
| Subject | Maths |
| Chapter | Chapter 10 |
| Chapter Name | Mensuration |
| Exercise | Ex 10.2 |
| Number of Questions Solved | 1 |
| Category | NCERT Solutions |
NCERT Solutions for Class 6 Maths Chapter 10 Mensuration Ex 10.2
Ex 10.2 Class 6 Maths Question 1.
Find the areas of the following figures by counting square:
Solution:
Placing these figures on the centimetre square, we have
(a) Full squares = 9
∴ Area covered by the figure = 9 x 1 sq. cm = 9 sq. cm
(b) Full squares = 5
∴ Area covered by the figure = 5 x 1 sq. cm = 5 sq. cm
(c) Full squares = 2
Half squares = 4
∴ Area covered by the figure \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm
= (2 + 2) sq cm = 4 sq. cm
(d) Full squares = 10
∴ Area covered by the figure = 10 x 1 sq. cm = 10 sq. cm
(e) Full squares = 10
∴ Area covered by the figure = 10 x 1 sq. cm = 10 sq. cm
(f) Full squares = 2
Half squares = 4
∴ Area covered by the figure = \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm
= (2 + 2)sq. cm = 4 sq. cm
(g) Full squares = 4
Half squares = 4
∴ Area covered by the figure = \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm
= (4 + 2)sq. cm = 6 sq. cm
(h) Full squares = 5
∴ Area covered by the figure = 5 x 1 sq. cm
= 5 sq. cm
(i) Full squares = 9
∴ Area covered by the figure = 9 x 1 sq. cm
= 9 sq. cm
(j) Full squares = 2
Half squares = 4
∴ Area covered by the figure = \(\left( 2\times 1+4\times \frac { 1 }{ 2 } \right) \) sq. cm
= (2 + 2)sq. cm = 4 sq. cm
(k) Full squares = 4
Half squares = 2
∴ Area covered by the figure = \(\left( 4\times 1+2\times \frac { 1 }{ 2 } \right) \) sq. cm
= (4 + 1)sq. cm = 5 sq. cm
(l) Full squares = 4
More than half squares = 3
Half square = 2
∴ Area covered by the figure = \(\left( 4\times 1+3\times 1+2\times \frac { 1 }{ 2 } \right) \) sq. cm
= (4 + 3 + 1)sq. cm
= 8 sq. cm
(m) Full squares = 7
More than half squares = 7
Half square = 0
∴ Area covered by the figure = \(\left( 7\times 1+7\times 1+0\times \frac { 1 }{ 2 } \right) \) sq. cm
= (7 + 7 + 0)sq. cm
= 14 sq. cm
(n) Full squares = 10
More than half squares = 8
Half square = 0
∴ Area covered by the figure = \(\left( 10\times 1+8\times 1+0\times \frac { 1 }{ 2 } \right) \) sq. cm
= (10 + 8 + 0)sq. cm
= 18 sq. cm
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