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NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2.

  • Algebra Class 6 Ex 11.1
  • Algebra Class 6 Ex 11.3
  • Algebra Class 6 Ex 11.4
  • Algebra Class 6 Ex 11.5
Board CBSE
Textbook NCERT
Class Class 6
Subject Maths
Chapter Chapter 11
Chapter Name Algebra
Exercise  Ex 11.2
Number of Questions Solved 5
Category NCERT Solutions

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2

Ex 11.2 Class 6 Maths Question 1.
The side of an equilateral triangle is shown by l. Express the perimeter of the equilateral triangle using l.
Solution:
If P represents the perimeter of an equilateral triangle of side l, then P = l + l + l= 3 x l

Ex 11.2 Class 6 Maths Question 2.
The side of a regular hexagon (see figure) is denoted by l. Express the perimeter of the hexagon using l.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 20

Solution:
If P represents the perimeter of a regular hexagon of side l, then P = l + l + l + l + l + l = 6 x l.

Ex 11.2 Class 6 Maths Question 3.
A cube is a three-dimensional figure as shown in figure. It has six faces and all of them are identical squares. The length of an edge of the cube is given by l. Find the formula for the total length of the edges of a cube.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 21
Solution:
Since all the 12 edges of a cube are of same length, l. Then, their total length = 12 x l.

Ex 11.2 Class 6 Maths Question 4.
The diameter of a circle is a line, which joins two points on the circle and also passes through the centre of the circle. (In the adjoining figure AB is a diameter of the circle;
C is its centre). Express the diameter of the circle (d) in terms of its radius (r).
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 22
Solution:
Diameter AB = AC + CB
If d represents the diameter of the circle and r is the radius of circle, then
d = CP + CP [∵ CP = r]
d = r + r = 2r

Ex 11.2 Class 6 Maths Question 5.
To find sum of three numbers 14, 27 and 13, we can have two ways.
(a) We may first add 14 and 27 to get 41 and then add 13 to it to get the total sum 54 or
(b) We may add 27 and 13 to get 40 and then add 14 to get the sum 54.
Thus, (14 + 27) + 13 = 14 + (27 + 13).
This can be done for any three numbers. This property is known as the associativity of addition of numbers. Express this property which we have already studied in the chapter on Whole Numbers, in a general way, by using variables a, b and c.
Solution:
The given properly is stated as
For 3 variables a, b and c, we have
(a + b) + c = a + (b + c)

We hope the NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.2, drop a comment below and we will get back to you at the earliest.

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