NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2.
| Board | CBSE |
| Textbook | NCERT |
| Class | Class 6 |
| Subject | Maths |
| Chapter | Chapter 2 |
| Chapter Name | Whole Numbers |
| Exercise | Ex 2.2 |
| Number of Questions Solved | 7 |
| Category | NCERT Solutions |
NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2
Ex 2.2 Class 6 Maths Question 1.
Find the sum by suitable rearrangement:
(a) 837 + 208 + 363
(b) 1962 + 453 +1538 + 647
Solution:
Ex 2.2 Class 6 Maths Question 2.
Find the product by suitable rearrangement:
(a) 2 x 1768 x 50
(b) 4 x 166 x 25
(c) 8 x 291 x 125
(d) 625 x 279 x 16
(e) 285 x 5 x 60
(f) 125 x 40 x 8 x 25
Solution:
(a) 2 x 1768 x 50 = (2 x 50) x 1768
= 100 x 1768 = 176800
(b) 4 x 166 x 25 = (4 x 25) x 166
= 100 x 166 = 16600
(c) 8 x 291 x 125 = (8 x 125) x 291
= 1000 x 291 = 291000
(d) 625 x 279 x 16 = (625 x 16) x 279
= 10000 x 279 = 2790000
(e) 285 x 5 x 60 = 285 x (5 x 60)
= 285 x 300 = 85500
(f) 125 x 40 x 8 x 25 = (125 x 8) x (40 x 25)
= 1000 x 1000
= 1000000
Ex 2.2 Class 6 Maths Question 3.
Find the value of the following:
(a) 297 x 17 + 297 x 3
(b) 54279 x 92 + 8 x 54279
(c) 81265 x 169 – 81265 x 69
(d) 3845 x 5 x 782 + 769 x 25 x 218
Solution:
(a) 297 x 17 + 297 x 3 = 297 x (17 + 3)
= 297 x 20
= 5949
(b) 54279 x 92 + 8 x 54279
= 54279 x (92 + 8)
= 54279 x 100 = 5427900
(c) 81265 x 169 – 81265 x 69
= 81265 x (169 -69)
= 81265 x 100
= 8126500
(d) 3845 x 5 x 782 + 769 x 25 x 218
= 3845 x 5 x 782 + (769 x 5) x 5 x 218
= 3845x5x782 + 3845x5x218
= (3845 x 5) x (782+ 218)
=19225 x 1000
=19225000
Ex 2.2 Class 6 Maths Question 4.
Find the product using suitable properties :
(a) 738 x 103
(b) 854 x 102
(c) 258 x 1008
(d) 1005 x 168
Solution:
(a) 738 x 103 = 738 x (100 + 3)
= 738 x 100 + 738 x 3 = 73800 + 2214 = 76014
(b) 854 x 102 = 854 x (100 + 2)
= 854 x 100 + 854 x 2 = 85400 + 1708 = 87108
(c) 258 x 1008 = 258 x (1000 + 8)
= 258 x 1000 + 258 x 8 = 258000 + 2064 = 260064
(d) 1005 x 168 = (1000 + 5) x 168
= 1000 x 168 + 5 x 168
= 168000 + 840 = 168840
Ex 2.2 Class 6 Maths Question 5.
A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ? 44 per litre, how much did he spend in all on petrol?
Solution:
Petrol filled on Monday and Tuesday
= 40 litres + 50 litres
= 90 litres
Cost of petrol @ ₹ 44 per litre
= 90 x ₹ 44 = ₹ 3960
Ex 2.2 Class 6 Maths Question 6.
A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs ? 15 per litre, how much money is due to the vendor per day?
Solution:
Milk supplied to a hotel in the morning and evening
= 32 litres + 68 litres = 100 litres
Money due to vendor per day.
= 100 x ₹ 15 = ₹ 1500
Ex 2.2 Class 6 Maths Question 7.
Match the following:
(i) 425 x 136 = 425 x (6 + 30 +100) (a) Commutativity under multiplication
(ii) 2 x 49 x 50 = 2 x 50 x 49 (b) Commutativity under addition
(iii) 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition
Solution:
Matching is as under :
(i) → (c)
(ii) → (a)
(iii) → (b)
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