NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 2 |

Chapter Name |
Whole Numbers |

Exercise |
Ex 2.2 |

Number of Questions Solved |
7 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 2 Whole Numbers Ex 2.2

**Ex 2.2 Class 6 Maths Question 1.**

Find the sum by suitable rearrangement:

**(a)** 837 + 208 + 363

**(b)** 1962 + 453 +1538 + 647

**Solution:**

**Ex 2.2 Class 6 Maths Question 2.**

Find the product by suitable rearrangement:

**(a)** 2 x 1768 x 50

**(b)** 4 x 166 x 25

**(c)** 8 x 291 x 125

**(d)** 625 x 279 x 16

**(e)** 285 x 5 x 60

**(f)** 125 x 40 x 8 x 25

**Solution:**

**(a)** 2 x 1768 x 50 = (2 x 50) x 1768

= 100 x 1768 = 176800

**(b)** 4 x 166 x 25 = (4 x 25) x 166

= 100 x 166 = 16600

**(c)** 8 x 291 x 125 = (8 x 125) x 291

= 1000 x 291 = 291000

**(d)** 625 x 279 x 16 = (625 x 16) x 279

= 10000 x 279 = 2790000

**(e)** 285 x 5 x 60 = 285 x (5 x 60)

= 285 x 300 = 85500

**(f)** 125 x 40 x 8 x 25 = (125 x 8) x (40 x 25)

= 1000 x 1000

= 1000000

**Ex 2.2 Class 6 Maths Question 3.**

Find the value of the following:

**(a)** 297 x 17 + 297 x 3

**(b)** 54279 x 92 + 8 x 54279

**(c)** 81265 x 169 – 81265 x 69

**(d)** 3845 x 5 x 782 + 769 x 25 x 218

**Solution:**

**(a)** 297 x 17 + 297 x 3 = 297 x (17 + 3)

= 297 x 20

= 5949

**(b)** 54279 x 92 + 8 x 54279

= 54279 x (92 + 8)

= 54279 x 100 = 5427900

**(c)** 81265 x 169 – 81265 x 69

= 81265 x (169 -69)

= 81265 x 100

= 8126500

**(d)** 3845 x 5 x 782 + 769 x 25 x 218

= 3845 x 5 x 782 + (769 x 5) x 5 x 218

= 3845x5x782 + 3845x5x218

= (3845 x 5) x (782+ 218)

=19225 x 1000

=19225000

**Ex 2.2 Class 6 Maths Question 4.**

Find the product using suitable properties :

**(a)** 738 x 103

**(b)** 854 x 102

**(c)** 258 x 1008

**(d)** 1005 x 168

**Solution:**

**(a)** 738 x 103 = 738 x (100 + 3)

= 738 x 100 + 738 x 3 = 73800 + 2214 = 76014

**(b)** 854 x 102 = 854 x (100 + 2)

= 854 x 100 + 854 x 2 = 85400 + 1708 = 87108

**(c)** 258 x 1008 = 258 x (1000 + 8)

= 258 x 1000 + 258 x 8 = 258000 + 2064 = 260064

**(d)** 1005 x 168 = (1000 + 5) x 168

= 1000 x 168 + 5 x 168

= 168000 + 840 = 168840

**Ex 2.2 Class 6 Maths Question 5.**

A taxidriver filled his car petrol tank with 40 litres of petrol on Monday. The next day, he filled the tank with 50 litres of petrol. If the petrol costs ? 44 per litre, how much did he spend in all on petrol?

**Solution:**

Petrol filled on Monday and Tuesday

= 40 litres + 50 litres

= 90 litres

Cost of petrol @ ₹ 44 per litre

= 90 x ₹ 44 = ₹ 3960

**Ex 2.2 Class 6 Maths Question 6.**

A vendor supplies 32 litres of milk to a hotel in the morning and 68 litres of milk in the evening. If the milk costs ? 15 per litre, how much money is due to the vendor per day?

**Solution:**

Milk supplied to a hotel in the morning and evening

= 32 litres + 68 litres = 100 litres

Money due to vendor per day.

= 100 x ₹ 15 = ₹ 1500

**Ex 2.2 Class 6 Maths Question 7.**

Match the following:

**(i)** 425 x 136 = 425 x (6 + 30 +100) (a) Commutativity under multiplication

**(ii)** 2 x 49 x 50 = 2 x 50 x 49 (b) Commutativity under addition

**(iii)** 80 + 2005 + 20 = 80 + 20 + 2005 (c) Distributivity of multiplication over addition

**Solution:**

Matching is as under :

**(i)** → (c)

**(ii)** → (a)

**(iii)** → (b)

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