NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 6 |

Chapter Name |
Integers |

Exercise |
Ex 6.3 |

Number of Questions Solved |
4 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3

Ex 6.3 Class 6 Maths Question 1.

Find:

**(a)** 35-(20)

**(b)** 72 (90)

**(c)** (-15) – (-18)

**(d)** (-20) – (13)

**(e)** 23 (-12)

**(f)** (-32) – (-40)

Solution:

**(a)** 35 – 20 = (15 + 20) – 20

= 15 + (20 – 20) = 15 + 0 = 15

**(b)** 72 – 90 = 72 – (72 + 18)

= (72 – 72) + (-18)

= 0 + (-18) = -18 1

**(c)** (-15) – (-18) = (-15) + (additive inverse -18)

= -15 + 18 = -15 +(15 + 3)

= (-15 + 15) 43 = 0 + 3 = +3

**(d)** (-20) -13 = -20 -13 = -(20 + 13) = -33

**(e)** 23 – (-12) = 23 + 12 = 35

**(f)** (-32) – (-40) = -32 + 40 = (-32 + 32) +8

= 0 + 8 + 8

Ex 6.3 Class 6 Maths Question 2.

Fill in the blanks with >, < or = sign:

**(a)** (-3) + (-6) …… (-3) -(-6)

**(b)** (-21) – (-10) …… (-31) + (-11)

**(e)** 45 – (-11) ……. 57 + (-4)

**(d)** (-25) – (-42) …….. (-42) – (-25)

Solution:

**(a)** Here, (-3) + (-6) = -3 – 6 = =9

and (-3)-(-6) = -3 + 6 =3

As -9 < 3

∴ (-3) + (-6) < (-3) – (-6) (b)

**(b)** Here, (-21) – (-10) = -21 +10 = -11

and (-31)+ (-11) = -31 -11 = -42

As -11 > -42

∴ (-21) – (-10) > (-31) + (-11)

**(c)** Here, 45 – (-11) = 45 + 11 = 56

and 57 + (-4) = 57-4 = 53

As 56 > 53

∴ 45 – (-11) > 57 + (-4)

**(d)** Here, -25 – (-42) = -25 + 42

= -25 + (25 + 17)

= (-25 + 25) +17 = 0 + 17 = 17

and, (-42) – (-25) = -42 + 25

= (-17 – 25) + 25

= -17 + (-25 + 25) = -17 + 0 = -17

As 17 > -17

∴ (-25) – (-42) > (-42) – (-25)

Ex 6.3 Class 6 Maths Question 3.

Fil in the blanks:

**(a)** (-8)+ ….. = 0

**(b)** 13 + …….. = 0

**(c)** 12 + (-12) = ……

**(d)** (-4) + ……. = -12

**(e)** ………. -15 = -10

Solution:

**(a)** (-8) + (+8) = 0

**(b)** 13 + (-13) = 0

**(c)** 12 + (-12) = 0

**(d)** (-4) +(-8) = -12 [∵ -12 – (-4) = -12 + 4 = -8]

**(e)** 5-15 = -10 [∵ -10 + 15 = 5]

Ex 6.3 Class 6 Maths Question 4.

Find:

**(a)** (-7) – 8- (-25)

**(b)** (-13) + 32 – 8 – 1

**(c)** (-7) + (-8) + (-90)

**(d)** 50 – (-40) – (-2)

Solution:

**(a)** (-7) – 8 – (-25) = -7 – 8 + 25

= -15 + 25 = 10.

**(b)** (-13) + 32 – 8-1 = -13 – 8 – 1 + 32

= -22 + 32 = 10

**(c)** (-7) + (-8) + (-90) = -7 – 8 – 90 = -105.

**(d)** 50 – (-40) – (-2) = 50+ 40 + 2 = 92.

We hope the NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 6 Integers Ex 6.3, drop a comment below and we will get back to you at the earliest.