Contents

NCERT Solutions for Class 6 Maths Chapter 8 Decimals are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 8 Decimals.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 8 |

Chapter Name |
Decimals |

Exercise |
Ex 8.1, Ex 8.2, Ex 8.3, Ex 8.4, Ex 8.5, Ex 8.6 |

Number of Questions Solved |
38 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 8 Decimals

### Chapter 8 Decimals Exercise 8.1

Question 1.

Write the following as numbers in the given table:

Solution:

On filling the given table, we have

Question 2.

Write the following decimals in the place value table:

**(a)** 19.4

**(b)** 0.3

**(c)** 10.6

**(d)** 205

Solution:

Let us make a common place value table, assigning appropriate place value to the digits in the given numbers. We have,

Question 3.

Write each of the following as decimals:

**(a)** Seven- tenths

**(b)** Two tens and nine-tenths

**(c)** Fourteen point six

**(d)** One hundred and two ones

**(e)** Six htihdred point eight

Solution:

**(a)** Seven-tenths = = 0.7

**(b)** Two tens, 9 – tenths = 20 + = 20.9

**(c)** Fourteen point six = 14.6

**(d)** One Hundred and 2-ones = 1 x 100 + 0 x 10 + 2 x 1 + 0 x

= 100 + 0 + 2 = 102.0

**(e)** Six hundred point eight = 600.8

Question 4.

Write each of the following as decimals:

Solution:

Question 5.

Write the following decimals as fractions. Reduce the fractions to lowest form:

**(a)** 0.6

**(b)** 2.5

**(c)** 1.0

**(d)** 3.8

**(e)** 13.7

**(f)** 21.2

**(g)** 6.4

Solution:

Question 6.

Express the following as cm vising decimals:

**(a)** 2 mm

**(b)** 30 mm

**(c)** 116 mm

**(d)** 4 cm 2mm

**(e)** 162 mm

**(f)** 83 mm

Solution:

Question 7.

Between which two whole numbers on the number line are the given numbers lie?

Which of these whole numberes is nearer the number?

**(a)** 0.8

**(b)** 5.1

**(c)** 2.6

**(d)** 6.4

**(e)** 9.1

**(f)** 4.9

Solution:

Question 8.

Show the following numbers on the number line.

**(a)** 0.2

**(b)** 1.9

**(c)** 1.1

**(d)** 2.5

Solution:

**(a)** Since 0.2 > 0 but <1. There are 2 tenth in it. Divide the unit length between 0 and 1 into 10 equal parts and take 2 parts as shown below. Thus, A represents 0.2.

**(b)** Since 1 < 1.9 < 2. Divide the unit length between 1 and 2 into 10 equal parts and take 9 parts as shown below. Thus, A represents 1.9.

**(c)** Since 1 < 1.1 < 2. Divide the unit length between 1 and 2 into 10 equal parts and take 1 part as shown below. Thus, A represents 1.1.

**(d)** Since 2 < 2.5 < 3. Divide the unit length between 2 and 3 into 10 equal parts and take 5 parts as shown below. Thus, A represents 2.5.

Question 9.

Write the decimal number represented by the points A, B, C, D on the given number line

Solution:

Since A lies between 0 and 1 and the unit length between 0 and 1 stands divided in 10 equal parts. Also A is at the 8th point.

Thus, A represents 0.8.

Since, B lies between 1 and 2 and the unit length between 1 and 2 stands divided in 10 equal parts. Also, B lies 3 points ahead of 1. Therefore, B represents 1.3.

Since C and D lies between 2 and 3 and the unit length between 2 and 3 stands divided between 2 and 3 in 10 equal parts. Also C and D respectively lies 2 and 9 points ahead of 2.

∴ C represents 2.2 and D represents 2.9.

Question 10.

**(a)** The length of Ramesh’s notebook is 9 cm 5 mm. What will be its length in cm?

**(b)** The length of a young gram plant is 65 mm. Express its length in cm.

Solution:

**(a)** Length of Ramesh’s notebook

**(b)** Length of gram plant

### Chapter 8 Decimals Exercise 8.2

Question 1.

Complete the table with the help of these boxes and use decimals to write the number

Solution:

Completing the table, we have

Question 2.

Write the numbers given in the following place value table in decimal form:

Solution:

Question 3.

Write the following decimals in the place value table:

**(a)** 0.29

**(b)** 2.08

**(c)** 19.60

**(d)** 148.32

**(e)** 200.812

Solution:

Let us make a common place value table, assigning appropriate place value to the digits in the given numbers. We have,

Question 4.

Write each of the following as decimals:

Solution:

Question 5.

Write each of the following decimals in words:

**(a)** 0. 03

**(b)** 1.20

**(c)** 108.56

**(d)** 10.07

**(e)** 0. 032

**(f)** 5.008

Solution:

**(a)** 0.03 = Zero point zero three or three hundredths.

**(b)** 1.20 = One point two zero.

**(c)** 108.56 = One hundred eight point five six.

**(d)** 10.7 = Ten point zero seven.

**(e)** 0. 032 = Zero point zero three two.

**(f)** 5.008 = Five point zero zero eight.

Question 6.

Between which two numbers in tenths place on the number line does each of the given number lie?

**(a)** 0. 06

**(b)** 0.45

**(c)** 0.19

**(d)** 0.66

**(e)** 0.92

**(f)** 0.57

Solution:

All these points lies between 0 and 1.

Question 7.

Write as fractions in lowest terms:

**(a)** 0.60

**(b)** 0.05

**(c)** 0.75

**(d)** 0.25

**(f)** 0.125

(g) 0.066

Solution:

### Chapter 8 Decimals Exercise 8.3

Question 1.

Which is greater?

**(a)** 0.3 or 0.4

**(b)** 0.07 or 0.02

**(c)** 3 or 0.8

**(d)** 0.5 or 0.05

**(e)** 1.23 or 1.2

**(f)** 0.099 or 0.19

**(g)** 1.5 or 1.50

**(h)** 1.431 or 1.490

**(i)** 3.3 or 3.300

**(j)** 5.64 or 5.603

Solution:

In this case, the two numbers have the same parts upto tenths. The hundredth part of 5.64 is greater than that of 5.603.

∴ 5.64 > 5.603

Question 2.

Make five more examples and find the greater number from them.

**(i)** 0.5 and 0.8

**(ii)** 2.0 or 0.9

**(iii)** 0.042 or 0.22

**(iv)** 3.012 or 2.99

**(v)** 0.055 or 0.15

Solution:

Their solutions are:

### Chapter 8 Decimals Exercise 8.4

Question 1.

Express as rupees using decimals:

**(a)** 5 paise

**(b)** 75 paise

**(c)** 20 paise

**(d)** 50 rupees 90 paise

**(e)** 725 paise

Solution:

Question 2.

Express as metres using decimals:

**(a)** 15 cm

**(b)** 6 cm

**(c)** 2 m 45 m

**(d)** 9 m 7 cm

**(e)** 419 cm

Solution:

Question 3.

Express as cm using decimals:

**(a)** 5 nun

**(b)** 60 mm

**(c)** 164 mm

**(d)** 9 cm 8 mm

**(e)** 93 mm

Solution:

Question 4.

Express as km using decimals:

**(a)** 8 m

**(b)** 88 m

**(c)** 8888 m

**(d)** 70 km 5 m

Solution:

Question 5.

Express as kg using decimals:

**(a)** 2 g

**(b)** 100 g

**(c)** 3750 g

**(d)** 5 kg 8 g

**(e)** 26 kg 50 g

Solution:

### Chapter 8 Decimals Exercise 8.5

Question 1.

Find the sum in each of the following:

**(a)** 0.007 + 8.5 + 30.08

**(b)** 15 + 0.632 + 13.8

**(c)** 27.076+ 0.55 + 0.004

**(d)** 25.65 + 9.005 + 3.7

**(e)** 0.75 + 10.425 + 2

**(f)** 280.69 + 25.2 + 38

Solution:

Question 2.

Rashid spent ₹ 35.75 for Maths book and ₹ 32.60 for Science book. Find the total amount spent by Rashid.

Solution:

Money spent on Maths book = ₹ 35.75

Money spent on Science book=₹ 32.60

∴ Total money spent is =₹ 35.75 +₹ 32.60 = ₹ 68.35

Question 3.

Radhika’s mother gave her ₹ 10.50 and her father gave her ₹ 15.80, find the total amount given to Radhika by the parents.

Solution:

Money given by Radhika’s mother = ₹ 10.50

Money given by Radhika’s father = ₹ 15.80

∴ Total amount given to Radhika = ₹ 10.50 + ₹ 15.80 = ₹ 26.30

Question 4.

Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.

Solution:

Cloth bought by Nasreen for her shirt = 3 m 20 cm

Cloth bought by Nasreen for her trouser = 2 m 5 cm

∴ Total cloth bought by Nasreen = 3 m 20 cm + 2 m 5 cm

= 5 m 25 cm

Question 5.

Naresh walked 2 km 35 m in the morning and 1 km 7 m in the evening. How much distance did he walk in all?

Solution:

Distance walked in the morning = 2 km 35 m = 2.035 km

Distance walked in the evening = 1 km 7 m = 1.007 km

∴ Total distance walked by Naresh = 2.035 km +1.007 km = 3.042 km

Question 6.

Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot in order to reach her school. How far is her school from her residence?

Solution:

Distance travelled by bus = 15 km 268 m = 15.268 km

Distance travelled by car = 7 km 7 m = 7.007 km

Distance travelled on foot = 500 m = 0.500 km

Total distance of school from her residence

= 15.268 km + 7.007 km + 0.500 km = 22.775km

Question 7.

Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.

Solution:

Weight of rice purchased = 5 kg 400 g = 5.400 kg

Weight of sugar purchased = 2 kg 20 gm = 2.020 kg

Weight of flour purchased = 10 kg 850 g = 10.850 kg

Total weight of purchases = 5.400 kg +2.020 kg +10.850 kg = 18.270 kg

### Chapter 8 Decimals Exercise 8.6

Question 1.

Subtract:

**(a)** ₹ 18.25 from ₹ 20.75

**(b)** ₹ 202.54 m from 250 m

**(c)** ₹ 5.36 from ₹ 8.40

**(d)** 2.051 km from 5.206 km

**(e)** 0.314 kg from 2.107 kg

Solution:

Question 2.

Find the value of:

**(a)** 9.756 – 6.28

**(b)** 21.05 – 15.27

**(c)** 18.5 – 6.79

**(d)** 11.6 – 9.

Solution:

Question 3.

Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper?

Solution:

Cost of the book = ₹ 35.65

Money given to the shopkeeper by Raju = ₹ 50

Money he got back = ₹ 50 – ₹ 35.65 = ₹ 14.35

Question 4.

Rani had ₹ 18.50. She bought one ice-cream for ₹ 11.75. How much money does she have now?

Solution:

Money with Rani = ₹ 18.50

Money spent on ice-cream=₹ 11.75

Money left with Rani = ₹ 18.50 – ₹ 11.75 = ₹ 6.75

Question 5.

Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?

Solution:

Total length of cloth = 20 m 5 cm = 20.05 m

Length cut out for curtain = 4 m 50 cm = 4.50 m

Cloth left over = 20.05 m – 4.50 m = 15.55 m

Question 6.

Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?

Solution:

Total distance travelled by Namita

20 km 50 m = 20.050 km

Distance travelled by bus = 10 km 200 m = 10.200 km

∴ Distance travelled by auto = 20.050 km – 10.200 km

= 9.850 km

Question 7.

Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the weight of the potatoes?

Solution:

Total weight of vegetables bought = 10 kg

Weight of onions = 3 kg 500 g = 3.500 kg

Weight of tomato= 2 kg 75 g = 2.075 kg

∴ Total weight of these vegetables =3.500 kg + 2.075 kg = 5.575 kg

As per question

Weight of potatoes = 10 kg – 5.575 kg = 4.425 kg

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