CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Ex 10.2 Textbook Questions and Answers are provided by experts in order to help students secure good marks in exams.

## Class 7 Maths NCERT Solutions Chapter 10 Practical Geometry Ex 10.2

**Ex 10.2 Class 7 Maths Question 1.**

Construct ∆XYZ in which XY = 45 cm, YZ = 5 cm and ZX = 6 cm.

**Solution:**

**Steps of Construction :
**

- Draw a line segment YZ = 5 cm.
- With Y centre and draw an arc radius cm.
- With Z as a centre and draw another arc intersecting the arc radius = 6 cm, at X.
- Join XY and XZ to obtain the required triangle.

**Ex 10.2 Class 7 Maths Question 2.**

Construct an equilateral triangle of side 5.5 cm.

**Solution:**

**Steps of Construction :
**

- Draw a line segment BC = 5.5 cm.
- With centre B and radius = 5.5 cm, draw an arc.
- With centre C and radius = 5.5 cm, draw another arc intersecting the arc drawn in step 2 at A.
- Join AB and AC to obtain the required triangle.

**Ex 10.2 Class 7 Maths Question 3.**

Draw ∆PQR with PQ = 4, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

**Solution:**

**Steps of Construction :
**

- Draw a line segment QR = 3.5 cm.
- With centre Q and radius = 4 cm, draw an arc.
- With R as a centre and radius = 4 cm, draw another arc intersecting the arc drawn in step 2 at P.
- Join PQ and PR to obtain the required triangle. ∆PQR is an isosceles triangle.

**Ex 10.2 Class 7 Maths Question 4.**

Construct AABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure ∠B.

**Solution:**

**Steps of Construction :**

- Draw a line segment BC = 6 c.m

- With centre B and radius = 2.5 cm, draw an arc.
- With centre C and radius =6.5 cm, draw another arc intersecting the arc drawn in step 2 at A.
- Join AB and AC to obtain the required triangle.
- On measuring, we find that ∠B = 90°