CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 4 Simple Equations InText Questions and Answers are provided by experts in order to help students secure good marks in exams.

## Class 7 Maths NCERT Solutions Chapter 4 Simple Equations InText Questions

Try These (Page 78)

Question 1.5

The value of the expression (10y – 20) depends on the value of y. Verify this by giving five different values to y and finding for each y the value of (10y – 20). From the different values of (10y – 20), you obtain, do you see a solution to 10y – 20 = 50? If there is no solution, try giving more values to y and find whether the condition 10y – 20 = 50 is met.

Solution:

Let us find the value of the expression (10 y – 20) for different values of y.

Clearly, the value of (10y – 20) depends on the value of y.

But, none of the values is 50. Thus, y = 1 or y = 2 or y = 3 or y = 4 or y = 5 is not the solution of 10y – 20 = 50.

Let us try by giving more values to y and find whether the condition 10y – 20 = 50 is met.

When, y = 6, then l0y – 20 = 10 x 6 – 20 = 60 – 20 = 40 ≠ 50. So, y = 6 is not its solution.

When, y = 7, then l0y – 20 = 10 x 7 – 20 = 70 – 20 = 50. So, y = 7 is its solution.

Try These (Page 80)

Question 1.

Write at least one other form for each equation (ii), (iii), and (iv).

Solution:

Other forms are as under:

(i) p multiplied by 5 gives 20

(ii) 7 added to thrice of n gives 1

(iii) one-fifth of m less 2 gives 6.

Try These (Page 88)

Question 1.

Start with the same step x = 5 and make two different equations. Ask two of your classmates to solve the equations. Check whether they get the solution x = 5.

Solution:

For 1 st equation :

Starting with x = 5

Multiplying both sides by 5, 5x, = 25

Adding 5 to both sides, 5x + 5 = 30

Let us solve it,

For IInd equation :

Starting with x = 5

Multiplying both sides by 3, 3x = 15

Subtracting 3 from both sides, 3x – 3 = 12

Let us solve it,

Try These (Page 88)

Question 1.

Try to make two number puzzles, one with the solution 11 and another with 100.

Solution:

The first puzzle with solution 11: Think of a number, multiply it by 3 and add 2 to the product. The result obtained is 35. Tell me the number. The second puzzle with solution 100: Think of a number, divide it by 10 and subtract 5 from the quotient. The result obtained is 5. Tell me the number.

Try These (Page 90)

(i) When you multiply a number by 6 and subtract 5 from the product, you get 7. Can you tell me what the number is?

Solution:

Let the number be x

Then, according to the question,

(ii) What is that number one-third of which added to 5 gives 8?

Solution:

Let the number by y

Then, according to the question

Try These (Page 90)

Question 1.

There are two types of boxes containing mangoes. Each box of the larger type contains 4 more mangoes than the number of mangoes contained in 8 boxes of the smaller type. Each larger box contains 100 mangoes. Find the number of mangoes contained in the smaller box?

Solution:

Let the number of mangoes in each smaller box be x.

Then, the number of mangoes in 8 such boxes = 8x.

Therefore, number of mangoes in each larger box = 8x + 4

Thus, the number of mangoes in the smaller box is 12.