Contents

NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles are part of NCERT Solutions for Class 7 Maths. Here we have given NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 7 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Congruence of Triangles |

Exercise |
Ex 7.1, Ex 7.2. |

Number of Questions Solved |
14 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 7 Maths Chapter 7 Congruence of Triangles

### Chapter 7 Congruence of Triangles Exercise 7.1

**Ex 7.1 Class 7 Maths Question 1.**

Complete the following statements:

**(a)** Two line segments are congruent if

**(b)** Among two congruent angles, one has a measure of 70°; the measure of the other angle is

**(c)** When we write ∠A = ∠B, we actually mean

**Solution:**

**(a)** Two line segments are congruent if they have the same length.

**(b)** Among two congruent angles, one has a measure of 70° the measure of the other angle is 70°.

**(c)** When we write ∠A = ∠B, we actually mean m ∠A = m ∠B.

**Ex 7.1 Class 7 Maths Question 2.**

Give any two real-life examples for congruent shapes.

**Solution:
**Two one-rupee coins, two ten-rupee notes.

**Ex 7.1 Class 7 Maths Question 3.**

If ∆ABC = FED under the correspondence ABC ↔ FED, write all the corresponding congruent parts of the triangles.

**Solution:**

∆ABC = ∆FED means that ∆ABC superposes on ∆FED exactly such that the vertices of ∆ABC fall on the vertices of ∆FED in the following order A ↔ F, B ↔ E and C ↔ D.

**Ex 7.1 Class 7 Maths Question 4.**

If ∆DEF = BCA, write the part(s) of ∆BCA that correspond to

**Solution:
**

### Chapter 7 Congruence of Triangles Exercise 7.2

**Ex 7.2 Class 7 Maths Question 1.**

Which congruence criterion do you use in the following ?

**Solution:
**

**Ex 7.2 Class 7 Maths Question 2.**

You want to show that ∆ART = ∆PEN.

**(a)** If you have to use SSS criterion, then you need to

- AR =
- RT =
- AT =

**(b)** If it is given that ∠T = ∠N and you are to use SAS criterion, you need to have

- RT = and,
- PN =

**(c)** If it is given that AT = PN and you are to use ASA criterion, you need to have

- ?
- ?

**Solution:**

**(a)** In order to show that ∆ART = ∆PEN using SSS criterion, we need to show that

- AR = PE
- RT = EN
- AT = PN

**(b)** If m∠T = m∠N and to use SAS criterion, we need to show that

- RT = EN and
- PN = AT

**(c)** If AT = PN and to use ASA criterion, we need to show that

- ∠RAT = ∠EPN and
- ∠ATR = ∠PNE

**Ex 7.2 Class 7 Maths Question 3.
**

**Solution:**

**Ex 7.2 Class 7 Maths Question 4.**

In ∆ABC, ∠A = 30°, ∠B = 40° and ∠C = 110°

In ∆PQR, ∠P = 30°, ∠Q = 40° and ∠R = 110°.

A student says that ∆ABC = ∆PQR by AAA congruence criterion. Is he justified? Why or why not?

**Solution:**

In two triangles, if the three angles of one triangle are respectively equal to the three angles of the other, then the triangles are not necessarily congruent.

**Ex 7.2 Class 7 Maths Question 5.**

In the figure, the two triangles are congruent The corresponding parts are ∆ RAT = ?

**Solution:
**

**Ex 7.2 Class 7 Maths Question 6.**

Complete the congruence statement :

**Solution:
**

**Ex 7.2 Class 7 Maths Question 7.**

In a squared sheet, draw two triangles of equal areas such that

**(i)** the triangles are congruent.

**(ii)** the triangles are not congruent.

What can you say about their perimeters?

**Solution:
**

**Ex 7.2 Class 7 Maths Question 8.**

Draw a rough sketch of two triangles such that they have five pairs of congruent parts but still the triangles are not congruent.

**Solution:**

In some special cases (which depend on the lengths of the sides and the size of the angle involved),

SSA is enough to show congruence. However, it is not always enough. Consider the following triangles :

Here side AB is congruent to side DE (S) side AC is congruent to side DF(S) angle C is congruent to angle F(A)

But the triangles are not congruent, as we can see.

**What happens is this :** If we draw a vertical line through point A in the first triangle, we can sort of “flip” side AB around this line to get the second triangle. If we were to lay one triangle on top of the other and draw the vertical line, this how it would look.

Clearly, side DE is just side AB flipped around the line. So, we have not changed the length of the side, and the other side AC (or DF) is unchanged, as is angle C (or F). So, these two triangles that have the same SSA information, but they are not congruent.

**Ex 7.2 Class 7 Maths Question 9.**

If ∆ABC and ∆PQR are to be congruent, name one additional pair of corresponding parts. What criterion did you use?

**Solution:**

In order prove that ∆ABC ≅ ∆PQR, the additional pair of corresponding parts are named as BC = QR.

Criterion used is ASA rule of congruence

**Ex 7.2 Class 7 Maths Question 10.**

Explain, why ∆ABC ≅ ∆FED

**Solution:
**

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