NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.2.

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 11 |

Chapter Name |
Mensuration |

Exercise |
Ex 11.2 |

Number of Questions Solved |
11 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.2

**Ex 11.2 Class 8 Maths Question 1.**

The shape of the top surface of a table is trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Solution:

Area of top surface of a table

= Area of the trapezium

**Ex 11.2 Class 8 Maths Question 2.**

The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.

**Solution:**

Let the required side be x cm.

**Ex 11.2 Class 8 Maths Question 3.**

Length of the fence of a trapezium A shaped field ABCD is 120 m. IF BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD B and BC.

Solution:

Let ABCD be the given trapezium in which BC = 48 m, CD = 17 m and

AD = 40 m.

**Ex 11.2 Class 8 Maths Question 4.**

The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Solution:

Let ABCD be the given quadrilateral in which BE ⊥ AC and DF ⊥ AC.

It is given that

AC =24m, BE = 8m and DF = 13 m.

Now, area of quad. ABCD

= area of ∆ABC + area of ∆ACD

**Ex 11.2 Class 8 Maths Question 5.**

The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.

**Solution:**

Area of a rhombus = \(\frac { 1 }{ 2 } \) x (product of diagonals)

\(=\left( \frac { 1 }{ 2 } \times 7.5\times 12 \right) { cm }^{ 2 }=45{ cm }^{ 2 }\)

**Ex 11.2 Class 8 Maths Question 6.**

Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.

**Solution:**

Let ABCD be a rhombus of side 6 cm and whose altitude DF = 4 cm. Also, one of its diagonals, BD =8 cm.

Area of the rhombus ABCD

**Ex 11.2 Class 8 Maths Question 7.**

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m^{2} is ₹ 4.

**Solution:**

Area of the floor = 3000 x Area of one tile

**Ex 11.2 Class 8 Maths Question 8.**

Mohan wants to buy a trapezium shaped field. Its side along the. river is parallel to and twice the side along the road. If the area of this field is 10500 m^{2} and the perpendicular distance between the two parallel sides is 100m, find the length of the side along the river.

Solution:

Let the parallel sides of the trapezium shaped field berm and 2x m. Then, its area

∴ The length of the side along the river is 2 x 70, i.e., 140 metres.

**Ex 11.2 Class 8 Maths Question 9.**

Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.

**Solution:**

Area of the octagonal surface ABCDEFGH = Area (trap. ABCH) + Area (rect. HCDG) +Area (trap. GDEF)

**Ex 11.2 Class 8 Maths Question 10.**

There is a pentagonal shaped park as shown in the figure. For finding its area Jyoti and Kavita divided it in two different ways.

Find the area of this park using both ways. Can you suggest some other way of finding its area?

**Solution:**

Taking Jyoti’s diagram :

**Ex 11.2 Class 8 Maths Question 11.**

Diagram of the adjacent picture frame has outer dimensions = 24 cm x 28 cm and inner dimensions 16 cm x 20 cm. Find the area of each section of the frame, if the width of each section is same.

Solution:

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