NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations in One Variable Ex 2.2.

- Linear Equations In One Variable Class 8 Ex 2.1
- Linear Equations In One Variable Class 8 Ex 2.3
- Linear Equations In One Variable Class 8 Ex 2.4
- Linear Equations In One Variable Class 8 Ex 2.5
- Linear Equations In One Variable Class 8 Ex 2.6

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 2 |

Chapter Name |
Linear Equations in One Variable |

Exercise |
Ex 2.2 |

Number of Questions Solved |
16 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 2 Linear Equations In One Variable Ex 2.2

**Ex 2.2 Class 8 Maths Question 1.**

If you subtract \(\frac { 1 }{ 2 } \) from a number and multiply the result \(\frac { 1 }{ 2 } \) by you get \(\frac { 1 }{ 8 } \) What is the number ?

**Solution.**

Let the required number be x. Then,

Thus, the required number is \(\frac { 3 }{ 4 } \)

**Ex 2.2 Class 8 Maths Question 2.**

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool ?

**Solution.**

**Ex 2.2 Class 8 Maths Question 3.**

The base of an isosceles triangle is \(\frac { 4 }{ 3 } \)cm. The perimeter of the triangle is \(4\frac { 2 }{ 15 } \)cm. What is the length of either of the remaining equal sides ?

**Solution.**

Let each equal side of an isosceles triangle ABC be x cm.

**Ex 2.2 Class 8 Maths Question 4.**

Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

**Solution.
**Let the number be x and (x + 15).

Hence, the numbers are 40 and 55.

**Ex 2.2 Class 8 Maths Question 5.**

Two numbers are in the ratio 5 :3. If they differ by 18, what are the numbers ?

**Solution.**

Let the number br 5x and 3x. Then,

Hence, the numbers are 45 and 27.

**Ex 2.2 Class 8 Maths Question 6.**

Three consecutive integers add up to 51. What are these integers ?

**Solution.**

Let the consective numbers be x, (x + 1) and (x + 2). Then,

Hence, the consective numbers are 16, 17 and 18.

**Ex 2.2 Class 8 Maths Question 7.**

The sum of three consecutive multiples of 8 is 888. Find the multiples.

**Solution.**

Let the three consective multiples of 8 be 8x, 8(x + 1) and 8(x + 2).

Hence, the three consective multiples of 8 are 8 x 36, 8 x (36 + 1) and 8 x (36 + 2) i.e., 288, 296 and 3.4.

**Ex 2.2 Class 8 Maths Question 8.**

Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3 and 4 respectively, they add up to 74. Find these numbers.

**Solution.**

let the three consective integers be x, (x + 1) and (x + 2). It is given that

Hence, the numbers are 7, 8 and 9

**Ex 2.2 Class 8 Maths Question 9.**

The ages of Rahul and Haroon are in the ratio 5 : 7. Four years later, the sum of their ages will be 56 years. What are their present ages ?

**Solution.**

Let the ages of Rahul and haroom be 5x and 7x years.

**Ex 2.2 Class 8 Maths Question 10.**

The numbers of boys and girls in a class are in the ratio 7 : 5. The number of boys is 8 more than the number of girls. What is the total class strength ?

**Solution.**.

Let the number of boys and girls in a class be 7x and 5x.

Since the number of boys is 8 more than the number of girls. Therefore,

7x = 5x + 8

⇒ 7x – 5x = 8

⇒ 2x = 8

⇒ x = 4

∴ The number of boys = 7 x 4 = 28

and the number of girls = 5 x 4 = 20

Thus, the total strength of the class is 28 + 20, i. e., 48.

**Ex 2.2 Class 8 Maths Question 11.**

Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of the ages of all the three is 135 years. What is the age of each one of them ?

**Solution.**

Let Baichung’s age be x years. Then,

**Ex 2.2 Class 8 Maths Question 12.**

Fifteen years from now Ravi’s age will be four times his present age. What is Ravi’s present age ?

**Solution.
**Let Ravi’s present age be x years.

After 15 years his age will be (x +15) years.

It is given that after 15 years, Ravi’s age will be four times his present age.

**Ex 2.2 Class 8 Maths Question 13.**

A rational number is such that when you multiply it by \(\frac { 5 }{ 2 } \) and add \(\frac { 2 }{ 3 } \) to the product, you get\(-\frac { 7 }{ 12 } \). What is the number ?

**Solution.
**Let the required number be x. Then,

**Ex 2.2 Class 8 Maths Question 14.**

Lakshmi is a cashier in a bank. She has currency notes of denominations ₹ 100, ₹ 50 and ₹ 10, respectively. The ratio of the number of these notes is 2 : 3 : 5. The total cash with Lakshmi is ₹ 4,00,000. How many notes of each denomination does she have ?

**Solution.**

Let notes of denominations ₹ 100, ₹ 50 and ₹ 10 be 2x, 3x and 5x respectively.

**Ex 2.2 Class 8 Maths Question 15.**

I have a total oft 300 in coins of denomination ₹ 1, ₹ 2 and ₹ 5. The number of ₹ 2 coins is 3 times the number of ₹ 5 coins. The total number of coins is 160. How many coins of each denomination are with me ?

**Solution.
**Let the number of ₹ 5 coins be x. Then,

**Ex 2.2 Class 8 Maths Question 16.**

The organisers of an essay competition decide that a winner in the competition gets a prize of ₹ 100 and a participant who does not win gets a prize of ₹ 25. The total prize money distributed is ₹ 3,000. Find the number of winners, if the total number of participants is 63.

**Solution.**

Let x be the number of the winners: So, the number of participants who does not win is (63 – x).

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