NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.2.

- Understanding Quadrilaterals Class 8 Ex 3.1
- Understanding Quadrilaterals Class 8 Ex 3.3
- Understanding Quadrilaterals Class 8 Ex 3.4

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 3 |

Chapter Name |
Understanding Quadrilaterals |

Exercise |
Ex 3.2 |

Number of Questions Solved |
6 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 3 Understanding Quadrilaterals Ex 3.2

**Ex 3.2 Class 8 Maths Question 1.**

Find x in the following figures.

**Solution.**

We know that the sum of the exterior angles formed by producing the sides of a convex polygon in the same order is equal to 360°. Therefore,

**(a)** x + 125° + 125° = 360°

⇒ x + 250° = 360°

⇒ x = 360° – 250° = 110°

**(b) **x + 90° +60° + 90° + 70° = 360°**
**⇒ x + 310° = 360°

⇒ x = 360° – 310° = 50°

**Ex 3.2 Class 8 Maths Question 2.**

Find the measure of each exterior angle of a regular polygon of

**(i)** 9 sides

**(ii)** 15 sides

**Solution.**

**(i)** Each exterior angle of a regular polygon of 9 sides

**(ii)** Each exterior angle of a regular polygon of 15 sides

**Ex 3.2 Class 8 Maths Question 3.**

How many sides does a regular polygon have if the measure of an exterior angle is 24°?

**Solution.**

Since the number of sides of a regular polygon

**Ex 3.2 Class 8 Maths Question 4.**

How many sides does a regular polygon have if each of its interior angles is 165°?

**Solution.**

Let there be n sides of the polygon. Then, its each interior angle

Thus, there are 24 sides of the polygon.

**Ex 3.2 Class 8 Maths Question 5.**

**(a)** Is it possible to have a regular polygon with measure of each exterior angle as 22°?

**(b)** Can it be an interior angle of a regular polygon ? Why?

**Solution.**

**(a)** Since the number of sides of a regular polygon

= \(\frac { 180 }{ 11 } \),

Which is not a whole number.

A regular polygon with measure of each exterior angle as 22° is not possible.

**(b)** If interior angle = 22°, then its exterior angle = 180° – 22° = 158°.

But 158 does not divide 360 exactly.

Hence, the polygon is not possible.

**Ex 3.2 Class 8 Maths Question 6.**

**(a)** What is the minimum interior angle possible for a regular polygon? Why?

**(b)** What is the maximum exterior angle possible for a regular polygon?

**Solution.**

**(a)** The equilateral triangle being a regular polygon of 3 sides has the least measure of an interior angle = 60°.

**(b)** Since the minimum interior angle of a regular polygon is equal to 60°, therefore, the maximum exterior angle possible for a regular polygon = 180° – 60° – 120°.

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