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Properties of Triangles – Maharashtra Board Class 7 Solutions for Mathematics

Properties of Triangles – Maharashtra Board Class 7 Solutions for Mathematics (English Medium)

MathematicsGeneral ScienceMaharashtra Board Solutions

Exercise 1:

Solution 1:

In ΔABC,

  1. Segment CD is the altitude on side AB.
  2. Segment AF is the altitude on side BC.
  3. Segment BE is the altitude on side AC.

Solution 2:

  1. In ΔKLP, seg KN is an altitude.
  2. In ΔKLP, seg KM is a median.

Solution 3:

  1. Point D is the midpoint of seg VW.
  2. l(VW) = 2 × l(VD) = 2 × 5 = 10 cm

Solution 4:

Yes, segment PD can be the altitude as well as the median of ΔPQR.
Reason:
Given, segment PD is the perpendicular drawn from vertex P to the opposite side QR.
D is the midpoint of segment QR. So, PD is the median of ΔPQR.
∴ Segment PD is the median as well as the altitude of ΔPQR.

Solution 5:
Properties of Triangles - Maharashtra Board Class 7 Solutions for Mathematics-5
Properties of Triangles - Maharashtra Board Class 7 Solutions for Mathematics-5

Solution 6:

The median is the line segment joining the vertex of a triangle and the midpoint of its opposite side.
Steps of construction:

  1. Draw any ΔXYZ.
  2. Construct the bisector of each side of the triangle to find the midpoints of each of the sides of ΔXYZ.
  3. Hence, P, Q and R are the midpoints of the sides XY, YZ and ZX of ΔXYZ respectively.
  4. Join the vertex X to the midpoint Q of its opposite side YZ.
  5. Similarly, join R and Y, P and Z.

Properties of Triangles - Maharashtra Board Class 7 Solutions for Mathematics-6
Thus, seg XQ, seg YR and seg ZP are the three medians of ΔXYZ.

Solution 7:
The angle bisectors divide the given angle into two equal angles.
Steps of construction:

  1. Draw any ΔSTD.
  2. Construct the angle bisectors of each of the angles of ΔSTD.

Properties of Triangles - Maharashtra Board Class 7 Solutions for Mathematics-7

Hence, SY, DX and TZ are the three angle bisectors of ΔSTD.

Solution 8:

  1. Draw any ΔCID.
  2. Construct the perpendicular bisectors of each of the sides of ΔCID.

Properties of Triangles - Maharashtra Board Class 7 Solutions for Mathematics-8
Thus, seg DZ, seg CX and seg IY are the three perpendicular bisectors of ΔCID.

Solution 9:

Steps of construction:

  1. Draw any ΔRTO.
  2. Construct the perpendicular bisectors of each of the sides of the triangle to find the midpoint of each of the sides of ΔRTO.
  3. Hence, A, C and E are the midpoints of the sides TR, RO and OT of ΔRTO.
  4. Construct the perpendicular bisectors from the midpoints of the three sides of ΔRTO.

Properties of Triangles - Maharashtra Board Class 7 Solutions for Mathematics-9
Hence, AB, FE and CD are the three perpendicular bisectors of ΔRTO.

 

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