**Real Numbers – Maharashtra Board Class 9 Solutions for Algebra**

**Exercise – 2.1**

**Solution 1:**

**Solution 2(i):**

**Solution 2(ii):**

**Solution 2(iii):**

**Solution 2(iv):**

**Solution 2(v):**

**Solution 2(vi):**

**Solution 2(vii):**

**Solution 3(i):**

**Solution 3(ii):**

**Solution 3(iii):**

**Solution 3(iv):**

**Solution 3(v):**

**Exercise – 2.2**

**Solution 1:**

**Solution 2:**

**Solution 3:**

i. x > 2 ; y < 2

x > 2

∴2 < x

But y < 2 and 2 < x

∴y < 2 < x

∴x > y

ii. x = 4 ; 4 < y

x = 4

But 4 < y

∴x < y

iii. x > -3 ; -6 > y

x > -3 and y < -6

y < x

∴x > y

iv. -x = 5 ; -5 < y

x = -5 and y > -5

Substituting -5 for x

∴y > x

∴x < y

x > 5 ; y < -5

v. x > 5 and y < -5

∴x > y

**Solution 4:**

Draw a number line.

Mark a point O representing zero.

Take a point OA such that OA = 1.

Now draw a perpendicular line segment AB to OA, such that AB = 1.

Join the points O and B.

**Solution 5:**

**Solution 6:**

**Solution 7:**

**Solution 8:**

**Exercise – 2.3**

**Solution 1:**

**Solution 2:**

**Solution 3:**

**Solution 4:**

**Solution 5:**

**Solution 6:**

**Exercise – 2.4**

**Solution 1:**

**Exercise – 2.5**

**Solution 1:**

**Solution 2:**

**Solution 3:**

**Solution 4:**

**Exercise – 2.6**

**Solution 1(i):**

**Solution 1(ii):**

**Solution 1(iii):**

**Solution 1(iv):**

**Solution 1(v):**

**Solution 1(vi):**

**Solution 1(vii):**

**Solution 1(viii):**

**Solution 1(ix):**

**Solution 1(x):**

**Solution 2(i):**

**Solution 2(ii):**

**Solution 2(iii):**

**Solution 2(iv):**

**Solution 2(v):**

**Solution 2(vi):**

**Solution 2(vii):**

**Solution 2(viii):**

**Solution 2(ix):**

**Solution 2(x):**

**Solution 3:**

**Solution 4:**