Contents

## Selina Concise Mathematics Class 8 ICSE Solutions Chapter 15 Linear Inequations (Including Number Lines)

**Selina Publishers Concise Mathematics Class 8 ICSE Solutions Chapter 15 Linear Inequations (Including Number Lines)**

### Linear Inequations Exercise 15A – Selina Concise Mathematics Class 8 ICSE Solutions

Question 1.

If the replacement set is the set of natural numbers, solve.

(i) x – 5 < 0

(ii) x + 1 < 7

(iii) 3x – 4 > 6

(iv) 4x + 1 > 17

Solution:

Question 2.

If the replacement set = {-6, -3, 0, 3, 6, 9}; find the truth set of the following:

(i) 2x – 1 > 9

(ii) 3x + 7 < 1

Solution:

Question 3.

Solve 7 > 3x – 8; x ∈ N

Solution:

Question 4.

-17 < 9y – 8 ; y ∈ Z

Solution:

Question 5.

Solve 9x – 7 ≤ 28 + 4x; x ∈ W

Solution:

Question 6.

Solve : \(\frac { 2 }{ 3 }\)x + 8 < 12 ; x ∈ W

Solution:

Question 7.

Solve -5 (x + 4) > 30 ; x ∈ Z

Solution:

Question 8.

Solve the inquation 8 – 2x > x – 5 ; x ∈ N.

Solution:

Question 9.

Solve the inequality 18 – 3 (2x – 5) > 12; x ∈ W.

Solution:

Question 10.

Solve : \(\frac { 2x+1 }{ 3 }\) + 15 < 17; x ∈ W.

Solution:

Question 11.

Solve : -3 + x < 2, x ∈ N

Solution:

Question 12.

Solve : 4x – 5 > 10 – x, x ∈ {0, 1, 2, 3, 4, 5, 6, 7}

Solution:

Question 13.

Solve : 15 – 2(2x – 1) < 15, x ∈ Z.

Solution:

Question 14.

Solve : \(\frac { 2x+3 }{ 5 }\) > \(\frac { 4x-1 }{ 2 }\) , x ∈ W.

Solution:

### Linear Inequations Exercise 15B – Selina Concise Mathematics Class 8 ICSE Solutions

Solve and graph the solution set on a number line :

Question 1.

x – 5 < -2 ; x ∈ N

Solution:

Question 2.

3x – 1 > 5 ; x ∈ W

Solution:

Question 3.

-3x + 12 < -15 ; x ∈ R.

Solution:

Question 4.

7 > 3x – 8 ; x ∈ W

Solution:

Question 5.

8x – 8 < – 24 ; x ∈ Z

Solution:

Question 6.

8x – 9 > 35 – 3x ; x ∈ N

Solution:

Question 7.

5x + 4 > 8x – 11 ; x ∈ Z

Solution:

Question 8.

\(\frac { 2x }{ 5 }\) + 1 < -3 ; x ∈ R

Solution:

Question 9.

\(\frac { x }{ 2 }\) > -1 + \(\frac { 3x }{ 4 }\) ; x ∈ N

Solution:

Question 10.

\(\frac { 2 }{ 3 }\) x + 5 ≤ \(\frac { 1 }{ 2 }\) x + 6 ; x ∈ W

Solution:

Question 11.

Solve the inequation 5(x – 2) > 4 (x + 3) – 24 and represent its solution on a number line.

Given the replacement set is {-4, -3, -2, -1, 0, 1, 2, 3, 4}.

Solution:

Question 12.

Solve \(\frac { 2 }{ 3 }\) (x – 1) + 4 < 10 and represent its solution on a number line.

Given replacement set is {-8, -6, -4, 3, 6, 8, 12}.

Solution:

Question 13.

For each inequation, given below, represent the solution on a number line :

(i) \(\frac { 5 }{ 2 }\) – 2x ≥ \(\frac { 1 }{ 2 }\) ; x ∈ W

(ii) 3(2x – 1) ≥ 2(2x + 3), x ∈ Z

(iii) 2(4 – 3x) ≤ 4(x – 5), x ∈ W

(iv) 4(3x + 1) > 2(4x – 1), x is a negative integer

(v) \(\frac { 4 – x }{ 2 }\) < 3, x ∈ R

(vi) -2(x + 8) ≤ 8, x ∈ R

Solution: