Solve sin x − cos x = 0?
Answer:
\(x=\frac{\pi}{4}+n \pi\)
Explanation:
We have:
Which we can rearrange as follows:
\(∴ \sin x=\cos x\)
\(∴ \frac{\sin x}{\cos x}=1\)
\(∴ \tan x=1\)
\(\#:: \mathrm{x}=(\arctan 1)+\mathrm{npi} \backslash \backslash \# \text { where } n \in \mathbb{Z}\)
\(∴ x=\frac{\pi}{4}+n \pi\)