What are the formulae of stannous bromide and stannic bromide?
Answer:
For
stannous bromide………….?
Explanation:
The material is formed formed from \(S n^{2+} \text { and } 2 \times B r^{-}\) ions………. And hence the formula is \(S n B r_{2}\)
On the other hand, the formula for \(\text { stannic halide is } S n X_{4} \text {, i.e. tin(IV) halide. }\)