What Is [Latex](1+i)^{6} ?[/Latex]
Answer:
\((1+i)^{6}=-8 i\)
Explanation:
\((1+i)^{2}=1+2 i+i^{2}=2 i\)
\((2 i)^{3}=2^{3} \cdot i^{2} \cdot i=-8 i\)
So:
\((1+i)^{6}=\left((1+i)^{2}\right)^{3}=-8 i\)
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