What is the molar mass of calcium nitrate \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2} ?\)
Answer:
\(164.086 \mathrm{~g} / \mathrm{mol}\) is the molar mass of calcium nitrate, \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\)
Explanation:
The molar mass of \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}\) is calculated by multiplying the molar mass of each element by its subscript (remember to multiply the subscripts for \(\mathrm{NO}_{3} \text { by } 2\)) and adding the results. The molar mass of an element is its atomic weight on the periodic table in grams/mole, or g/mol.
\(\text { Molar mass Ca: }\)
\(\begin{aligned}
&(1 \times 40.078 \mathrm{~g} / \mathrm{mol} \mathrm{Ca})+(2 \times 14.007 \mathrm{~g} / \mathrm{mol} \mathrm{N})+(6 \times 15.999 \mathrm{~g} \mathrm{O}) \\
&=164.086 \mathrm{~g} / \mathrm{mol}
\end{aligned}\)