NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.6 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.6.

- Triangles Class 10 Ex 6.1
- Triangles Class 10 Ex 6.2
- Triangles Class 10 Ex 6.3
- Triangles Class 10 Ex 6.4
- Triangles Class 10 Ex 6.5
- Triangles Class 10 Ex 6.6

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 6 |

Chapter Name |
Triangles |

Exercise |
Ex 6.6 |

Number of Questions Solved |
10 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.6

**Ex 6.6 Class 10 Maths Question 1.
**

**In the given figure, PS is the bisector of ∠QPR of ∆PQR. Prove that**

**Solution:**

**Ex 6.6 Class 10 Maths Question 2.
**

**In the given figure, D is a point on hypotenuse AC of ∆ABC, DM ⊥ BC, and DN ⊥ AB. Prove that:**

**(i)**DM

^{2}= DN X MC

**(ii)**DN

^{2}= DM X AN

**Solution:**

**Ex 6.6 Class 10 Maths Question 3.
**

**In the given figure, ABc is triangle in which ∠ABC > 90° and AD ⊥ CB produced. Prove that AC**

^{2}= AB^{2}+ BC^{2}+ 2BC X BD**Solution:**

**Ex 6.6 Class 10 Maths Question 4.
**

**In the given figure, ABC is a triangle in which ∠ABC 90° and AD ⊥ CB. Prove that AC**

^{2}= AB^{2}+ BC^{2}– 2BC X BD**Solution:**

**Ex 6.6 Class 10 Maths Question 5.
**

**In the given figure, Ad is a median of a triangle ABC and AM ⊥ BC. Prove that**

**Solution:**

**Ex 6.6 Class 10 Maths Question 6.
**

**Prove that the sum of the squares of the diagonals of a parallelogram is equal to the sum of the squares of its sides.**

**Solution:**

**Ex 6.6 Class 10 Maths Question 7.
**

**In the given figure, two chords AB and CD intersect each other at the point P. Prove that:**

**(i)**∆APC ~∆DPB

**AP X PB = CP X DP**

(ii)

(ii)

**Solution:**

**Ex 6.6 Class 10 Maths Question 8.
**

**In the given figure, two chords Ab and CD of a circle intersect each other at the point P (when produced) outside the circle. Prove that:**

**(i)**∆PAC ~ ∆PDB

**PA X PB = PC X PD**

(ii)

(ii)

**Solution:**

**Ex 6.6 Class 10 Maths Question 9.
**

**In the given figure, D is a point on side BC of ∆ABC, such that Prove that AD is the bisector of ∆BAC.**

**Solution:**

**Ex 6.6 Class 10 Maths Question 10.
**

**Nazima is fly fishing in a stream. The trip of her fishing rod is 1.8m above the surface of the water and the fly at the end of the string rests on the water 3.6m away and 2.4 m from a point directly under the trip of the rod. Assuming that her string (from the trip of the rod to the fly) is that, how much string does she have out (see the figure)? If the pills in the string at the rate of 5 cm per second, what will be the horizontal distance of the fly from her after 12 seconds?**

**Solution:**

We hope the NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.6 help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 6 Triangles Ex 6.6, drop a comment below and we will get back to you at the earliest.

shravan kumar pandey says

thanks