NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exz 14.2 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2.

- Practical Geometry Class 6 Ex 14.1
- Practical Geometry Class 6 Ex 14.3
- Practical Geometry Class 6 Ex 14.4
- Practical Geometry Class 6 Ex 14.5
- Practical Geometry Class 6 Ex 14.6

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 14.2 |

Number of Questions Solved |
5 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Question 1.

Draw a line segment of length 7.3 cm, using a ruler.

Solution:

**Steps of Construction:**

- Mark a point A on the plane of the paper and place the ruler so that zero mark of the ruler is at A.

- Mark with pencil a point B against the mark on the ruler which indicates 7.3 cm.
- Join points A and B by moving the tip of the pencil against the straight edge of the ruler.

The line segment AB so obtained is the required line segment.

Question 2.

Construct a line segment of length 5.6 cm using ruler and compasses.

Solution:

**Steps of Construction:**

- Mark a point A on the plane of the paper and draw a line, say l, passing through it.

- Place the steel end of the compasses at zero mark on the ruler and open out it such that the pencil end on the mark indicates 5.6 cm.
- Transfer the compasses as it is to the line l so that the steel end is on A.
- With the pencil end make a small stroke on l so as to cut it at B.
- The segment AB so obtained is the required line segment.

Question 3.

Construct of length 7.8 cm. From this, cut off of length 4.7 cm. Measure .

Solution:

**Steps of Construction:**

- Draw a line segment AB of length 7.8 cm.

- Using compasses find a point C on the line segment AB so that segment AC = 4.7 cm.
- On measuring BC, we find that BC = 3.1 cm.

Question 4.

Given of length __3.9__ cm, construct such that the length of is twice that of . Verify by measurement.

Solution:

**Steps of Construction:**

- Draw a line l and mark a point P on it.

- Using compasses find a point X so that PX(= AB) = 3.9 cm on the line l.
- Using compasses find a point Q so that XQ = 3.9 cm on the line l.

Thus, PQ = PX + XQ = 3.9 cm + 3.9 cm

= 2(3.9 cm) = 2AB.

Question 5.

Given of length 7.3 cm and of length 3.4 cm, construct a line segment such that the length of is equal to the difference between the lengths of and . Verify by measurement

Solution:

**Steps of Construction:**

- Draw line segments AB = 7.3 cm and CD = 3.4 cm.
- Draw a line l and mark a point X on it.
- Using compasses find a point P on the line l so that segment XP = segment AB (i.e., 7.3 cm).
- Using compasses find a point Y so that the segment PY = segment CD (i.e., 3.4 cm). The segment XY so obtained is the required segment, because XY = OP -PY – AB -CD.

We hope the NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 help you. If you have any query regarding NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2, drop a comment below and we will get back to you at the earliest.

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