NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Exz 14.3 are part of NCERT Solutions for Class 6 Maths. Here we have given NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3.

- Practical Geometry Class 6 Ex 14.1
- Practical Geometry Class 6 Ex 14.2
- Practical Geometry Class 6 Ex 14.4
- Practical Geometry Class 6 Ex 14.5
- Practical Geometry Class 6 Ex 14.6

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 6 |

Subject |
Maths |

Chapter |
Chapter 14 |

Chapter Name |
Practical Geometry |

Exercise |
Ex 14.3 |

Number of Questions Solved |
2 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.3

Ex 14.3 Class 6 Maths Question 1.

Draw any line segment . Without measuring , construct a copy of .

Solution:

**Steps of Construction:**

Let PQ be the given line segment and l be a given line.

- Mark a point 0 on the line l.
- Open out the compasses and adjust so that the steel end is on A and the pencil end is A on B.
- Transfer the compasses to the line l without disturbing their opening so that the steel end is on 0.
- With the pencil end make a small stroke on the line l to cut it at the point P.

Then, the fine segment OP so obtained = the given line segment AB.

Ex 14.3 Class 6 Maths Question 2.

Given some line segment , whose length you do not know, construct such that the length of is twice that of .

Solution:

**Steps of Construction:**

Let AB be the given line segment.

- Draw any line l and make a point 0 on it.
- Open out the compasses in such way that the steel end is on A and the pencil end is on B.
- Transfer the compasses without disturbing their opening to the line l so that the steel end is on O.
- With the pencil end make a small stroke on -the line l to cut it at the point P.
- Repeat the steps 3 and 4 with same opening having P as the initial point and Q as the terminal point.

Then, the segment OQ = OP + PQ = AB + AB= 2 AB.

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