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NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2

NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2.

  • Algebraic Expressions and Identities Class 8 Ex 9.1
  • Algebraic Expressions and Identities Class 8 Ex 9.3
  • Algebraic Expressions and Identities Class 8 Ex 9.4
  • Algebraic Expressions and Identities Class 8 Ex 9.5
Board CBSE
Textbook NCERT
Class Class 8
Subject Maths
Chapter Chapter 9
Chapter Name Algebraic Expressions and Identities
Exercise Ex 9.2
Number of Questions Solved 5
Category NCERT Solutions

NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2

Ex 9.2 Class 8 Maths Question 1.
Find the product of the following pairs of monomials :
(i) 4, 7p
(ii) -4p, 7p
(iii) – 4p, 7pq
(iv) 4p3 , – 3p
(v) 4p, 0
Solution:
(i) 4 x 7p = (4 x 7) x p = 28p
(ii) – 4 p x 7p = (- 4 x 7) x (px P)
= -28p1 + 1 = – 28p2
(iii) -4px 7pq = (- 4 x 7) x (p x p x q)
= -28 p1+1q = – 28p2q
(iv) 4p3 x – 3p = (4 x – 3) x (p3 x p)
= – 12p3+1 = =-12p4
(v) 4p x 0 = (4 x 0) x p = 0 x p = 0

Ex 9.2 Class 8 Maths Question 2.
Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively :
(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2); (3mn, 4np)
Solution:
We know that the area of a rectangle = l x b, where l = length and b = breadth.
Therefore, the areas of rectangles with pair of monomials (p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2) and (3mn, 4np) as their lengths and breadths are given by
pxq=pq
10 m x 5n = (10 x 5) x (m x n) = 50 mn
20x2 x 5y2 = (20 x 5) x (x2 x y2) = 100x2y2
4x x 3x2 = (4 x 3) x (x x x2)
= 12x2
and, 3 mn x 4np = (3×4 )x(mxnxnxp)
=12 mn2p

Ex 9.2 Class 8 Maths Question 3.
Complete the table of products :
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities 6
Solution:
Completed table is as under :
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities 7

Ex 9.2 Class 8 Maths Question 4.
Obtain the volume of rectangular boxes with the following length, breadth and height respectively
(i) 5a, 3a2, 7a4
(ii) 2p, 4q, 8r
(iii) xy, 2x2y, 2xy2
(iv) a, 2b, 3c
Solution:
(i) Required volume = 5a x 3a2 x 7a4
= (5 x 3 x 7) x (a x a2 x a4)
= 105a1+2+4 =105a7

(ii) Required volume = 2p x 4q x 8r
= (2 x 4 x 8 )x p x q x r = 64 pqr

(iii) Required volume =xy x 2x2y x 2xy2
= (1 x 2 x 2) x (x x x2 x x x y x y x y2)
= 4x1+2+1 y1+1+2 = 4x4y4

(iv) Required volume =a x 2b x 3c
= (1 x 2 x 3) x (a x b x c)
= 6abc

Ex 9.2 Class 8 Maths Question 5.
Obtain the product of
(i) xy, yz, zx
(ii) a, – a2, a3
(iii) 2, 4y, 8y2, 16y3
(iv) a, 26, 3c, 6a6c
(v) m, – mn, mnp
Solution:
NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities 8

We hope the NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2 help you. If you have any query regarding NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.2, drop a comment below and we will get back to you at the earliest.

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