NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.5 are part of NCERT Solutions for Class 8 Maths. Here we have given NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.5.

- Algebraic Expressions and Identities Class 8 Ex 9.1
- Algebraic Expressions and Identities Class 8 Ex 9.2
- Algebraic Expressions and Identities Class 8 Ex 9.3
- Algebraic Expressions and Identities Class 8 Ex 9.4

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 8 |

Subject |
Maths |

Chapter |
Chapter 9 |

Chapter Name |
Algebraic Expressions and Identities |

Exercise |
Ex 9.5 |

Number of Questions Solved |
8 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities Ex 9.5

**Question 1.**

Use a suitable identity to get each of the following products,

**(i)** (x + 3) (x + 3)

**(ii)** (2y + 5)(2y + 5)

**(iii)** (2a – 7) (2a – 7)

**(iv)**

**(v)** (1.1m – 0.4) (1.1m + 0.4)

**(vi)** (a^{2} + b^{2}) (- a^{2} + b^{2})

**(vii)** (6x – 7) (6x + 7)

**(viii)** (- a + c) (- a + c)

**(ix)**

**(x)** (7a – 9b)(7a – 9b)

**Solution:**

**Question 2.**

Use the identity (x + a) (x + b) = x^{2} + (a + b)x + ab to find the following products.

**(i)** (x + 3) (x + 7)

**(ii)** (4x + 5) (4x + 1)

**(iii)** (4^{2} – 5) (4x – 1)

**(iv)** (4x + 5) (4^{2} – 1)

**(v)** (2x + 5y) (2x + 3y)

**(vi)** (2a^{2} + 9) (2a^{2} + 5)

**(vii)** (xyz – 4) (xyz – 2)

**Solution:**

**Question 3.**

Find the following squares by using the identities :

**(i)** (b – 7)^{2}

**(ii)** (xy + 3z)^{2}

**(iii)** (6x^{2} – 5y^{2})

**(iv)**

**(v)** (0.4p – 0.5q)^{2}

**(vi)** (2xy + 5y)^{2}

**Solution:**

**Question 4.**

Simplify :

**(i)** (a^{2} – b^{2})^{2}

**(ii)** (2x + 5)^{2} – (2x – 5)^{2}

**(iii)** (7m – 8n)^{2} + (7m + 8n)^{2}

**(iv)** (4m + 5n)^{2} + (5m + 4n)^{2}

**(v)** (2.5p – 1.5q)^{2} – (1.5p – 2.5q)^{2}

**(vi)** (ab + bc)^{2} – 2ab^{2}c

**(vii)** (m^{2} – n^{2}m)^{2} + 2m^{3}n^{2}

**Solution:**

**Question 5.**

Show that :

**(i)** (3x + 7)^{2} – 84x = (3x – 7)^{2}

**(ii)** (9p – 5q)^{2} + 180pq = (9p + 5q)^{2}

**(iii)**

**(iv)** (4pq + 3q)^{2} – (4pq – 3q)^{2} = 48pq^{2}

**(v)** (a – b)(a + b) + (b – c)(b + c) + (c – a)(c + a) = 0

**Solution:**

**Question 6.**

Using identities, evaluate : .

**(i)** 71^{2}

**(ii)** 99^{2}

**(iii)** 102^{2}

**(iv)** 998^{2}

**(v)** 5.2^{2}

**(vi)** 297 x 303

**(vii)** 78 x 82

**(viii)** 8.9^{2}

**(ix)** 1.05 x 9.5

**Solution:**

**Question 7.**

Using a^{2} – b^{2} = (a + b) (a – b), find

**(i)** 51^{2} – 49^{2}

**(ii)** (1.02)^{2} – (0.98)^{2}

**(iii) **153^{2} – 147^{2}

**(iv)** 12.1^{2} – 7.9^{2}

**Solution:**

**Question 8.**

Using (x + a) (x + b) = x + (a + b)x + ab, find

**(i)** 103 x 104

**(ii)** 5.1 x 5.2

**(iii)** 103 x 98

**(iv)** 9.7 x 9.8

**Solution:**

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