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NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3

NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.

  • Surface Areas and Volumes Class 9 Ex 13.1
  • Surface Areas and Volumes Class 9 Ex 13.2
  • Surface Areas and Volumes Class 9 Ex 13.3
  • Surface Areas and Volumes Class 9 Ex 13.4
  • Surface Areas and Volumes Class 9 Ex 13.5
  • Surface Areas and Volumes Class 9 Ex 13.6
  • Surface Areas and Volumes Class 9 Ex 13.7
  • Surface Areas and Volumes Class 9 Ex 13.8
  • Surface Areas and Volumes Class 9 Ex 13.9
Board CBSE
Textbook NCERT
Class Class 9
Subject Maths
Chapter Chapter 13
Chapter Name Surface Areas and Volumes
Exercise  Ex 13.3
Number of Questions Solved 8
Category NCERT Solutions

NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3

Chapter 13 Surface Areas and Volumes Ex 13.3

Assume π = \(\cfrac { 22 }{ 7 } \) unless stated otherwise.
Ex 13.3 Class 9 Maths Question 1.
Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area.
Solution.
We have, diameter = 10.5 cm
∴ Radius (r) = \(\cfrac { 10.5 }{ 2 } \) = 5.25 cm and slant height (l) = 10 cm
Now, curved surface area of the cone = πrl = \(\cfrac { 22 }{ 7 } \) x 5.25 x 10 = 165 cm2

Ex 13.3 Class 9 Maths Question 2.
Find the total surface area of a cone, if its slant height is 21 m and diameter of its base is 24 m.
Solution.
We have, slant height l = 21m
and    diameter = 24 m
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.1

Ex 13.3 Class 9 Maths Question 3.
Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find
(i) radius of the base and
(ii) total surface area of the cone.
Solution.
We have, slant height, l = 14 cm
Curved surface area of a cone =308 cm2
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.2

Ex 13.3 Class 9 Maths Question 4.
A conical tent is 10 m high and the radius of its base is 24 m. Find
(i) slant height of the tent.
(ii) cost of the canvas required to make the tent, if the cost of 1 m2 canvas is Rs.70.
Solution.
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.3

Ex 13.3 Class 9 Maths Question 5.
What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will he required for stitching margins and wastage in cutting is approximately 20 cm. (use π= 3.14)
Solution.
Let r, h and l be the radius, height and slant height of the tent, respectively.
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.4
Ex 13.3 Class 9 Maths Question 6.
The slant height and base diameter of a conical tomb are 25 m and 14 m, respectively. Find the cost of white-washing its curved surface at the rate of Rs. 210 per 100 m2.
Solution.
We have, slant height (l) = 25 m and diameter = 14 m .
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.5

Ex 13.3 Class 9 Maths Question 7.
A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.
Solution.
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.6

Ex 13.3 Class 9 Maths Question 8.
A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is ? 12 per m2, what will be the cost of painting all these cones?
(Use π = 3.14 and take \(\sqrt { 1.04 } \) = 1.02)
Solution.
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.7
NCERT Solutions for Class 9 Maths Chapter 13 Surface Areas and Volumes Ex 13.3.8

 

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