NCERT Solutions for Class 9 Maths Chapter 7 Triangles Ex 7.3 are part of NCERT Solutions for Class 9 Maths. Here we have given NCERT Solutions for Class 9 Maths Chapter 7 Triangles Ex 7.3.

- Triangles Class 9 Ex 7.1
- Triangles Class 9 Ex 7.2
- Triangles Class 9 Ex 7.3
- Triangles Class 9 Ex 7.4
- Triangles Class 9 Ex 7.5

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 9 |

Subject |
Maths |

Chapter |
Chapter 7 |

Chapter Name |
Triangles |

Exercise |
Ex 7.3 |

Number of Questions Solved |
5 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 9 Maths Chapter 7 Triangles Ex 7.3

Question 1.

Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see figure). If ΔD is extended to intersect BC at P, show that

(i) ΔABD ≅ ΔACD

(ii) ΔABP ≅ ΔACP

(iii) AP bisects ∠A as well as ∠D

(iv) AP is the perpendicular bisector g of

Solution:

Given: Δ ABC and Δ DBC are two isosceles triangles having common base BC, such that AB = AC and DB = DC.

To prove : (i) Δ ABD ≅ Δ ACD

(ii) ΔABP ≅ Δ ACP

(iii) AP bisects ∠A as well as ∠D

(iv) AP is the perpendicular bisector of BC

Question 2.

AD is an altitude of an isosceles ∠ABC in which AB = AC. Show that

(i) AD bisects BC.

(ii) AD bisects ∠A.

Solution:

Given: Δ ABC is an isosceles triangle and AD⊥ BC, AB = AC.

Question 3.

Two sides AB and BC and median AM of one triangle ABC are respectively equal to sides PQ and QR and median PN of ΔPQR (see figure). Show that

(i) ΔABM ≅ ΔPQN

(ii) Δ ABC ≅ ΔPQR

Solution:

Question 4.

BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles

Solution:

**
**Question 5.

ABC is an isosceles triangle with AB = AC. Draw AP ⊥ BC to show that ∠B = ∠C.

Solution:

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