## NCERT Class 10 Maths Lab Manual – Comparison of Curved Surface Areas and Total Surface Areas of Two Right Circular Cylinders

**Objective**

To compare the curved surface areas and total surface areas of two right circular cylinders which are formed from rectangular sheets of paper with same dimensions.

**Prerequisite Knowledge**

- Construction of a cylinder from rectangular sheet by paper folding.
- Area of rectangle = length X breadth
- Circumference and area of a circle.

C=\(2\pi{r}\) , A = \(\pi {r}^{2}\)

You can also download **NCERT Maths Solution Class 10** to help you to revise complete syllabus and score more marks in your examinations.

**Materials Required**

Coloured glazed paper, sketch pens, a pair of scissors, fevicol, cellotape, geometry box.

**Procedure
**

1. Take two rectangular sheets of paper of same dimensions as l= 14 cm and b =7 cm named as rectangle 1 and rectangle 2 .

2.Curve the rectangle 1 along its length l=14 cm.

3. Join two ends with cellotape to get a cylinder.

4. Similarly curve the rectangle 2 along its breadth b = 7 cm to get another cylinder as shown in figure.

**Observation**

**For rectangle 1:**

length of the rectangle = circumference of the circular base of the cylinder

l= \(2\pi {r}_{1}\)= 14 cm.

\({r}_{1}=\frac {14}{2\pi} =\frac {7}{\pi}\)

breadth of the rectangle = height of the cylinder

b = h = 7 cm.

curved surface area \({C}_{1}\quad \) = \(2\pi{r}_{2}{h}_{2}\) =

\(2\pi \times \frac {7}{2\pi } \times 14=98{cm}^{2}\)

Total surface area \({ T }_{ 1 }\quad =\quad 2\pi { r }_{1}^{2}\quad +\quad { C}_{1}\quad =\quad 2\pi \quad \times \frac { 49 }{ {\pi }^{ 2}} \quad +\quad 98\quad =\quad 98(\frac {1+\pi }{\pi })\)

**For rectangle 2:**

breadth of the rectangle = circumference of circular base of the cylinder

b=\(2\pi { r }_{ 2 }\) = 7 cm

\({r}_{2}\quad =\quad\frac {7}{2\pi}\)

length of the rectangle = height of the cylinder

l= \({ h }_{ 2 }\) = 14 cm.

curved surface area \({C}_{2}\quad =2\pi {r}_{2}{ h}_{2}\quad =\quad 2\pi \quad \times \frac { 7}{2\pi}\quad \times 14\quad =\quad 98\quad {cm}^{2}\)

Total surface area \(T_{ 2 }\quad =2\pi { r }_{ 2 }^{ 2 }\quad +{ C }_{ 2 }\)

=\(2\pi \times \frac {49}{ 4{\pi}^{2}}\quad +\quad 98\quad =49(\frac {1}{2\pi } +2)\quad =\quad 49(\frac { 1+4\pi}{\pi})\)

**Result**

- The curved surface areas (or lateral surface areas) of two cylinders of different height and radius formed from the two rectangular sheets of paper of same dimensions are same.
- The total surface areas of two cylinders of different height and radius formed from the two rectangular sheets of paper of same dimensions are not same.

**Learning Outcome**

Concept of comparison of curved surface area and total surface area of two cylinders formed from the two rectangular sheets of paper of same dimension is more clear. Students can understand easily that

\({C}_{1}={C}_{2}\) but \({T}_{1}\mp {T}_{2}\)

**Activity Time
**

- Take a rectangular sheet of paper of size 22 cm x 10 cm. Form two cylinders

(i) curved along its length

(ii) curved along its breadth.

Compare the lateral surface areas and total surface areas of these two cylinders.

**Question 1:**

Find the height of a right circular cylinder made from a rectangle of length 15 cm and breadth 12 cm. It is curved along

its length.

**Answer:**

12 cm

**Question 2:**

What is the curved surface area of a cylinder obtained from a square of side 5 cm ?

**Answer:**

25 cm^{2}

**Question 3:**

Radius ofthebaseofa paper cylinder is 7 cm and it is cut along its height. Find the length of the paper obtained.

**Answer:**

l= circumference of base = \(2\pi r=2\times\frac {22}{7} \times 7\) = 44 cm

**Multiple Choice Questions**

**Question 1:**

If the circumference of a circular base of a cylinder of height 2 cm is 132 cm, then the radius of the base is

(a) 21 cm

(b) 42 cm

(c) \(\frac {21}{2}\) cm

(d) none of these

**Question 2:**

A rectangular sheet of paper 44 cm X 18 cm is rolled along its length and a cylinder is formed. What will be the height of the cylinder ?

(a) 44 cm

(b) 18 cm

(c) 22 cm

(d) 9 cm

**Question 3:**

The area of a rectangular paper is 88 cm . Find its length if we obtain a circular cylinder of height 14 cm from it. [Hint : 27\(\pi\)rh =area of rectangle]

(a) 44 cm

(b) 88 cm

(c) \(\frac {44}{8}\)

(d) none of these

**Question 4:**

The diameter of a roller is 1.4 m and it is 2 m long. How much area will it cover in 2 revolutions ?

(a) 17.6 cm^{2}

(b) 16.7 m^{2}

(c) 61.7 m^{2}

(d) none of these

**Question 5:**

The area of a circular base of a cylinder is \(\pi\) cm^{2}and its height is 5 cm. Find the lateral surface area and .total surface area of the cylinder.

(a) 8\(\pi\) cm^{2},10\(\pi\) cm^{2
}(b) 10\(\pi\) cm^{2}, 12\(\pi\) cm^{2}

(c) 10\(\pi\) cm^{2}, 10\(\pi\) cm^{2
}(d) none of these

**Answers
**1. (a)

2. (b)

3. (c)

4. (a)

5. (b)

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