NCERT Class 10 Maths Lab Manual – Ratio of Areas of Two Similar Triangles
To verify “The ratio of the areas of two similar triangles is equal to the ratio of the square of their corresponding sides” by performing an activity.
- Concept of parallel lines.
- Division of a line in a given ratio.
Chart paper, construction box, coloured pens, a pair of scissors, fevicol.
- Take a chart paper and cut a ∆ABC with AB = 6cm, BC = 6cm, CA = 6cm.
- Mark 5 points P1, P2, …. , P5 at a distance of 1cm each on side AB and Q1, Q2,…..,Q5 at a distance of 1cm each on side AC as shown in fig.(i).
- Join P1Q1, P2Q2, …………, P5Q5 as shown in fig. (ii).
- Draw lines parallel to AC from P1, P2, P5 and also draw lines parallel to AB from the points Q1, Q2, ……., Q5 as shown in fig. (iii).
- Thus ∆ABC is divided into 36 smaller triangles and all are similar to each other and of equal area.
- Construct a ∆PQR with PQ = of AB, PR = of AC and QR = of BC i.e. 3cm each on another chart paper.
- Mark D1, D2 and E1, E2 on sides PQ and PR respectively.
- Repeat steps 3 and 4.
- Thus ∆PQR is divided into 9 smaller similar triangles equal in area.
- area of ∆ABC = area of 36 smaller ∆’s
- area of ∆PQR = area of 9 smaller ∆’s
= [9 smaller Δ’s/36 smaller Δ’s = = (1/2)2
(because ΔABC ∼ ΔPQR)
Thus it is verified that the ratio of the areas of two similar triangles is equal to the ratio of the square of their corresponding sides.
Concept of area theorem is clear to the students through this activity.
1. Take isosceles similar triangles and scalene similar triangles and try to verify this activity. Here isosceles triangles, ∆ABC ~ ∆PQR. Scalene triangle ∆DEF ~ ∆KLM
What are the criteria for two triangles to be similar ?
Two triangles are said to be similar, if
- their corresponding angles are equal.
- their corresponding sides are in proportion
∆ABC ~ ∆DEF and their areas are respectively 64 cm2 and 121 cm2. If EF = 15.4 cm, then findBC.
Is it true, if the areas of two similar triangles are equal, then they are congruent ?
What is the ratio of the area of an equilateral triangle described on one side of a square to the area of an equilateral triangle described on one of its diagonal ?
Are a square and a rhombus of side 3 cm similar ?
Is a rhombus of side 3 cm congruent to another rhombus of side 4 cm ?
Is the ratio of the areas of two similar triangles equal to the square of the ratio of their corresponding medians ?
Multiple Choice Questions
ABC and BDE are two equilateral triangles, such that D is the mid-point of BC. The ratio of the areas of ΔABC and ΔBDE is
Sides of two similar triangles are in the ratio 4 : 9. Areas of these triangles are in the ratio
If in two similar triangles PQR and LMN, if QR =15 cm and MN = 10 cm, then the ratio of the areas of triangles is
Two isosceles triangles have equal vertical angles and their areas are in the ratio 16 : 25. Then the ratio of their corresponding heights is
(a) 16 : 25
(b) 256 : 625
(c) 4 : 5
(d) none of these
∆ABC ~ ∆DEF. If AC = 19 cm and DF = 8 cm, then the ratio of the areas of the two triangles is
(a) 361 : 64
(b) 19 : 8
(c) 19 : 4
(d) none of these
In the given figure, PB and QA are perpendicular to segment AB. If PO = 5 cm, QO = 7 cm and area (∆POB) = 150 cm2, then area of ∆QOA is
(a) 254 cm2
(b) 294 cm2
(c) 244 cm2
(d) 49 cm2
Diagonals of a trapezium ABCD with AB || DC intersect each other at the point O. If AB = 2CD, find the ratio of the areas of triangles AOB and COD.
ABC and DBC are two triangles on the same base BC. If AD intersects BC at O, then the ratio of area (∆ABC) to area (∆DBC) is
(d) None of these
Area (∆ABC) : Area (∆DEF) = 25 : 36. Then AB : DE is
(a) 625 : 1296
(b) 25 : 36
(c) 6 : 5
(d) 5 : 6
∆DEF ~ ∆ABC; If DE : AB = 2 : 3 and area ∆DEF is equal to 44 square units, then area (∆ABC) is
(a) 120 sq. units
(b) 99 sq. units
(c) 66 sq. units
(d) none of these