NCERT Class 9 Maths Lab Manual – Verify the Algebraic Identity (a-b)² = a²- 2ab+b²
To verify the algebraic identity (a – b)² = a² – 2ab + b².
- Drawing sheet
- Coloured papers
- Square and its area.
- Rectangle and its area.
- For square and its area refer to Activity 3.
- For rectangle and its area refer to Activity 3.
- From a coloured paper, cut a square PQRS of side a units, (see Fig. 4.1)
- Further, cut out another square TQWX of side b units such that b < a. (see Fig. 4.2)
- Now, cut out a rectangle USRV of length a units and breadth b units from another coloured paper, (see Fig. 4.3)
- Now further, cut out another rectangle ZVWX of length a units and breadth b units, (see Fig. 4.4)
- Now, arrange figures 4.1, 4.2, 4.3 and 4.4, according to their vertices and paste it on a drawing sheet, (see Fig. 4.5)
From the figures 4.1,4.2, 4.3 and 4.4, we have Area of square PQRS = a²
Area of square TQWX = b²
Area of rectangle USRV = ab and Area of rectangle ZVWX – ab
Area of square PUZT = Area of square PQRS + Area of square TQWX – Area of rectangle ZVWX – Area of rectangle USRV
= a² + b² – ba-ab
= (a² -2ab + b²) …(i)
Also, from Fig. 4.5, it is clear that PUZT is a square whose each side is (a – b).
Area of square PUZT = (Side)²
= [(a-b)]² =(a-b)² …(ii)
From Eqs. (i) and (ii), we get (a – b)² = (a² – 2ab + b²)
Here, area is in square units.
On actual measurement, we get
a = ………… ,
b= ………… ,
(a-b) = ………… ,
a² = ………… ,
b² = ………… ,
(a² – b²) = ………… ,
ab = ………… ,
and 2ab = ………… ,
Hence, (a – b)² = a² – 2ab + b²
Algebraic identity (a – b)² = a² – 2ab + b² has been verified.
The identity (a – b)² = a² -2ab + b² may be used for
- calculating the square of a number which can be expressed as a difference of two convenient numbers.
- simplification and factorization of algebraic expressions.
What do you mean by an algebraic identity?
An algebraic identity is an algebraic equation which is true for all values of variables occurring in it.
Is (x – 3y)² = x² – 6xy + 9y² an algebraic identity?
Which identity should be use to expand (3x – 2y)²?
(a – b)² = a² – 2ab + b²
Is the identity (a – b) = a² – 2ab + b² hold for negative values of a and b?
What do we mean by degree of an algebraic expression?
The highest power of the variable involved in the algebraic expression is called its degree.
The algebraic identity is true for every real number.
Suppose we want square of any natural number, then it is possible to find the square of any natural number by using the identity
(a – b)² =a² +b² – 2ab
In an identity (a – b)² =a² +b² – 2ab, if both variables are equal, then find the value of (a – b)².
When a = b, then
(a-b)² = (b-b)² =0
Verify the algebraic identity (a-b)² = a² – 2ab + b² by taking a = 9 and b = 4.