NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2

NCERT Maths Solutions for Chapter 4 Ex 4.2 Class 10 acts as the best resource during your learning and helps you score well in your board exams.

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2.

• Quadratic Equations Class 10 Ex 4.1
• Quadratic Equations Class 10 Ex 4.2
• Quadratic Equations Class 10 Ex 4.3
• Quadratic Equations Class 10 Ex 4.4

Board	CBSE
Textbook	NCERT
Class	Class 10
Subject	Maths
Chapter	Chapter 4
Chapter Name	Quadratic Equations
Exercise	Ex 4.2
Number of Questions Solved	6
Category	NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.2

Ex 4.2 Class 10 Maths Question 1.
Find the roots of the following quadratic equations by factorisation:
(i) x² -3x – 10 = 0
(ii) 2x² + x – 6 = 0
(iii)  + 7x + 5 = 0
(iv) 2x² – x + = 0 8
(v) 100 x² – 20 X + 1 = 0
Solution:

Ex 4.2 Class 10 Maths Question 2.
Solve the following situations mathematically:
(i) John and Jivanti together have 45 marbles. Both of them lost 5 marbles each and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.
(ii) A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of toys produced in a day. On a particular day, the total cost of production was ₹750. We would like to find out the number of toys produced on that day.
Solution:
(i) Let the number of marbles John had be x
Then, the number of marbles Jivanti had = 45 -x
After losing 5 marbles:
The number of marbles left with John, = x – 5
The number of marbles left with Jivanti, = 45 -x – 5 = 40 -x

Ex 4.2 Class 10 Maths Question 3.
Find two numbers whose sum is 27 and product is 182.
Solution:
Let the first number be x, then another number will be 27 – x.
According to the questions, we have:

Hence, the required numbers are 13 and 14.

Ex 4.2 Class 10 Maths Question 4.
Find two consecutive positive integers, sum of whose squares is 365.
Solution:
Let the two consecutive integers be x and x + 1.
Then according to the question, we have:

Since the integers are positive, so neglecting x = -14, we have x = 13.
Hence, 13 and 14 are two consecutive positive integers.

Ex 4.2 Class 10 Maths Question 5.
The altitude of a right triangle is 7 cm less than its base. If the hypotenuse is 13 cm, find the other two sides.
Solution:
Let the base of right triangle be x cm.
Then, altitude of right triangle will be (x – 7) cm
Hypotenuse = 13cm   [Given]
By Pythagoras’ theorem, we have:

Ex 4.2 Class 10 Maths Question 6.
A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was ₹90, find the number of articles produced and the cost of each article.
Solution:

 

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