NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.4 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.4.

- Quadratic Equations Class 10 Ex 4.1
- Quadratic Equations Class 10 Ex 4.2
- Quadratic Equations Class 10 Ex 4.3
- Quadratic Equations Class 10 Ex 4.4

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 10 |

Subject |
Maths |

Chapter |
Chapter 4 |

Chapter Name |
Quadratic Equations |

Exercise |
Ex 4.4 |

Number of Questions Solved |
5 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 10 Maths Chapter 4 Quadratic Equations Ex 4.4

**Ex 4.4 Class 10 Maths Question 1.
**

**Find the nature of the roots of the following quadratic equations. If the real roots exist, find them:**

(i) 2x² -3x + 5 = 0

(ii) 3x

^{2}– \(4\sqrt { 3 } x\) + 4 = 0

(iii) 2x

^{2}-6x + 3 = 0

**Solution:**

**(i) Given: 2x**

^{2}– 3x + 5 = 0**(ii) Given: 3x ^{2} – \(4\sqrt { 3 } x\) + 4 = 0**

**(iii) Given: 2x ^{2}-6x + 3 = 0 **

**Ex 4.4 Class 10 Maths Question 2.
**

**Find the values of k for each of the following quadratic equations, so that they have two equal roots.**

**(1) 2x**

^{2}+ kx + 3 = 0**(2) kx (x – 2) + 6 = 0**

**Solution:**

Hence, k = 6.

**Ex 4.4 Class 10 Maths Question 3.
**

**Is it possible to design a rectangular mango grove whose length is twice its breadth, and the area is 800 m**

^{2}? If so, find its length and breadth.**Solution:**

Let breadth of the rectangular be x m

Then, the length of rectangular will be 2x m.

According to question, we have

**Ex 4.4 Class 10 Maths Question 4.
**

**Is the following situation possible? If so, determine their present ages.**

**The sum of the ages of two friends is 20 years. Four years ago, the product of their ages in years was 48.**

**Solution:**

Let the present age of one friend be x years

Then, the present age of other friend be (20 -x) years.

Four years ago, one friend’s age was (x – 4) years

According to question, we have

(x-4) (16-x) = 48

⇒ 16x – x

^{2}– 64 + 4x = 48

⇒ -x

^{2}– 20x – 64 – 118 = 0

⇒ -x

^{2}– 20x + 112 = 0

**Ex 4.4 Class 10 Maths Question 5.
**

**Is it possible to design a rectangular park of perimeter 80 m and area 400 m**

^{2}? If so, find its length and breadth.**Solution:**

Let the length of rectangular park be x.

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