NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.3 are part of NCERT Solutions for Class 12 Maths. Here we have given NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Ex 5.3.

- Continuity and Differentiability Class 12 Ex 5.1
- Continuity and Differentiability Class 12 Ex 5.2
- Continuity and Differentiability Class 12 Ex 5.4
- Continuity and Differentiability Class 12 Ex 5.5
- Continuity and Differentiability Class 12 Ex 5.6
- Continuity and Differentiability Class 12 Ex 5.7
- Continuity and Differentiability Class 12 Ex 5.8

Board |
CBSE |

Textbook |
NCERT |

Class |
Class 12 |

Subject |
Maths |

Chapter |
Chapter 5 |

Chapter Name |
Continuity and Differentiability |

Exercise |
Ex 5.3 |

Number of Questions Solved |
15 |

Category |
NCERT Solutions |

## NCERT Solutions for Class 12 Maths Chapter 5 Continuity and Differentiability Exc 5.3

**Find in the following**

**Question 1.**

2x + 3y = sinx

**Solution:**

2x + 3y = sinx

Differentiating w.r.t x,

=>

**Question 2.**

2x + 3y = siny

**Solution:**

2x + 3y = siny

Differentiating w.r.t x,

=>

**Question 3.**

ax + by² = cosy

**Solution:**

ax + by² = cosy

Differentiate w.r.t. x,

=>

**Question 4.**

xy + y² = tan x + y

**Solution:**

xy + y² = tanx + y

Differentiating w.r.t. x,

**Question 5.**

x² + xy + y² = 100

**Solution:**

x² + xy + xy = 100

Differentiating w.r.t. x,

**Question 6.**

x³ + x²y + xy² + y³ = 81

**Solution:**

Given that

x³ + x²y + xy² + y³ = 81

Differentiating both sides we get

**Question 7.**

sin² y + cos xy = π

**Solution:**

Given that

sin² y + cos xy = π

Differentiating both sides we get

**Question 8.**

sin²x + cos²y = 1

**Solution:**

Given that

sin²x + cos²y = 1

Differentiating both sides, we get

**Question 9.**

**Solution:**

put x = tanθ

**Question 10.**

**Solution:**

put x = tanθ

**Question 11.**

**Solution:**

put x = tanθ

**Question 12.**

**Solution:**

put x = tanθ

we get

**Question 13.**

**Solution:**

put x = tanθ

we get

**Question 14.**

**Solution:**

put x = tanθ

we get

**Question 15.**

**Solution:**

put x = tanθ

we get

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