GSEB Solutions for Class 8 Mathematics – Equation (English Medium)
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Exercise
Solution 1(1):
Solution 1(2):
Solution 1(3):
Solution 1(4):
Solution 1(5):
Solution 2(1):
Solution 2(2):
Solution 2(3):
Solution 2(4):
Practice 1
Solution 1:
Solution 2:
Solution 3:
Solution 4:
Solution 5:
Solution 6:
Solution 7:
Solution 8:
Solution 9:
Solution 10:
Solution 11:
Solution 12:
Practice 2
Solution 1:
Solution 2:
Solution 3:
Solution 4:
Solution 5:
Solution 6:
Solution 7:
Let the present age of Ravi be x years.
∴ Present age of his father = 4x years
After 10 years,
Ravi’s age = (x + 10) years and
Age of his father = (4x + 10) years
At that time, the age of Ravi’s father will be three times the age of Ravi.
∴ (4x + 10) = 3(x + 10)
∴ 4x + 10 = 3x + 30
∴ 4x – 3x = 30 – 10
∴ x = 20
Then, 4x = 4 × 20 = 80
Thus, Ravi’s present age is 20 years and that of his father is 80 years.
Practice 3
Solution 1(1):
4x + 13 = 3x + 15
∴ 4x – 3x = 15 – 13
∴ x = 2
∴ The solution of the equation is x = 2.
Solution 1(2):
Solution 1(3):
y + 18 = 2y – 7
∴ y – 2y = -7 – 18
∴ -y = -25
∴ y = 25
∴ The solution of the equation is x = 25.
Solution 1(4):
Solution 1(5):
Solution 1(6):
Solution 1(7):
Solution 2(1):
Solution 2(2):
Solution 2(3):
Let the number of students in the class be x.
Number of chocolates received by each student = 7
∴ Number of chocolate = 7x
If there were 5 more students, then number of students = (x + 5)
Then, number of chocolates received by each student
= 7 – 1
= 6
Now, number of chocolates = 6(x + 5)
∴ 7x = 6(x + 5)
∴ 7x = 6x + 30
∴ 7x – 6x = 30
∴ x = 30
Thus, there are 30 students in the class.
Solution 2(4):
Practice 4
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Solution 1(4):
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Solution 1(11):
Solution 1(12):
Practice 5
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