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NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2

CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 Textbook Questions and Answers are provided by experts in order to help students secure good marks in exams.

Class 7 Maths NCERT Solutions Chapter 11 Perimeter and Area Ex 11.2

Question 1.
Find the area of each of the following parallelograms :
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 10
Solution:
(a) Area of the parallelogram = base × height = (7 × 4) cm2 = 28 cm2

(b) Area of the parallelogram = base × height = (5 × 3) cm2 = 15 cm2

(c) Area of the karallelogram = base × height = (2.5 × 3.5) cm2 = 8.75 cm2

(d) Area of the parallelogram = base × height = (5 × 4.8) cm2 = 24 cm2

(e) Area of the parallelogram = base × height = (2 × 4.4) cm2 = 8.8 cm2

Question 2.
Find the area of each of the following triangles :
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 11
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 12

Question 3.
Find the missing values :
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 13
Solution:
We know that
Area of a parallelogram = Base × Height
Therefore, the missing values are calculated as shown :
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 14

Question 4.
Find the missing values :
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 15
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 16

Question 5.
PQRS is a parallelogram (in the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find
(a) the area of the parallelogram PQRS.
(b) QN, if PS = 8 cm.
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 17
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 18

Question 6.
DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (in the given figure). If the area of the parallelogram is 1470 cm2, AB = 35 cm, AD = 49 cm, find the length of BM and DL.
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 19
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 20

Question 7.
∆ ABC is right-angled at A (in the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also, find the length of AD.
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 21
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 22

Question 8.
∆ ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (in the given figure). The height of AD from A to BC is 6 cm. Find the area of A ABC. What will be the height from C to AB i.e., CE?
Solution:
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 23
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area 24

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