CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 Textbook Questions and Answers are provided by experts in order to help students secure good marks in exams.
Class 7 Maths NCERT Solutions Chapter 11 Perimeter and Area Ex 11.2
Question 1.
Find the area of each of the following parallelograms :
Solution:
(a) Area of the parallelogram = base × height = (7 × 4) cm2 = 28 cm2
(b) Area of the parallelogram = base × height = (5 × 3) cm2 = 15 cm2
(c) Area of the karallelogram = base × height = (2.5 × 3.5) cm2 = 8.75 cm2
(d) Area of the parallelogram = base × height = (5 × 4.8) cm2 = 24 cm2
(e) Area of the parallelogram = base × height = (2 × 4.4) cm2 = 8.8 cm2
Question 2.
Find the area of each of the following triangles :
Solution:
Question 3.
Find the missing values :
Solution:
We know that
Area of a parallelogram = Base × Height
Therefore, the missing values are calculated as shown :
Question 4.
Find the missing values :
Solution:
Question 5.
PQRS is a parallelogram (in the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find
(a) the area of the parallelogram PQRS.
(b) QN, if PS = 8 cm.
Solution:
Question 6.
DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (in the given figure). If the area of the parallelogram is 1470 cm2, AB = 35 cm, AD = 49 cm, find the length of BM and DL.
Solution:
Question 7.
∆ ABC is right-angled at A (in the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also, find the length of AD.
Solution:
Question 8.
∆ ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (in the given figure). The height of AD from A to BC is 6 cm. Find the area of A ABC. What will be the height from C to AB i.e., CE?
Solution:
