CBSE students can refer to NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.2 Textbook Questions and Answers are provided by experts in order to help students secure good marks in exams.

## Class 7 Maths NCERT Solutions Chapter 11 Perimeter and Area Ex 11.2

**Question 1.**

Find the area of each of the following parallelograms :

**Solution:**

**(a)** Area of the parallelogram = base × height = (7 × 4) cm^{2} = 28 cm^{2}

**(b)** Area of the parallelogram = base × height = (5 × 3) cm^{2} = 15 cm^{2}

**(c)** Area of the karallelogram = base × height = (2.5 × 3.5) cm^{2} = 8.75 cm^{2}

**(d)** Area of the parallelogram = base × height = (5 × 4.8) cm^{2} = 24 cm^{2}

**(e)** Area of the parallelogram = base × height = (2 × 4.4) cm2 = 8.8 cm^{2}

**Question 2.**

Find the area of each of the following triangles :

**Solution:
**

**Question 3.**

Find the missing values :

**Solution:**

We know that

Area of a parallelogram = Base × Height

Therefore, the missing values are calculated as shown :

**Question 4.**

Find the missing values :

**Solution:
**

**Question 5.**

PQRS is a parallelogram (in the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 12 cm and QM = 7.6 cm. Find

**(a)** the area of the parallelogram PQRS.

**(b)** QN, if PS = 8 cm.

**Solution:
**

**Question 6.**

DL and BM are the heights on sides AB and AD respectively of parallelogram ABCD (in the given figure). If the area of the parallelogram is 1470 cm^{2}, AB = 35 cm, AD = 49 cm, find the length of BM and DL.

**Solution:
**

**Question 7.**

∆ ABC is right-angled at A (in the given figure). AD is perpendicular to BC. If AB = 5 cm, BC = 13 cm and AC = 12 cm, find the area of ∆ABC. Also, find the length of AD.

**Solution:
**

**Question 8.**

∆ ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (in the given figure). The height of AD from A to BC is 6 cm. Find the area of A ABC. What will be the height from C to AB i.e., CE?

**Solution:
**